Boiling point elevation
ΔT_b = K_b × m, where K_b is ebullioscopic constant of solvent (water: 0.52 K·kg/mol), m is molality.
-- NCERT Class 12 Chemistry, Ch. 1, p. 18When you dissolve a non-volatile solute in a solvent, the boiling point of the solution is higher than that of the pure solvent. This is boiling-point elevation — a colligative property that depends only on the number of solute particles, not their identity.
The trap that costs marks: an ionic compound like NaCl dissociates into ions. If a question hands you NaCl dissolved in water and you plug molality straight into ΔT_b = K_b · m, you get the answer for a non-electrolyte. The actual elevation is larger because NaCl produces two ions per formula unit — you must multiply by the Van 't Hoff factor i. Forgetting i is a common confusion in NEET colligative-property calculations.
The core relationship (NCERT Class 12 Chemistry Chapter 1, page 18):
ΔT_b = i · K_b · m
where ΔT_b is the elevation in boiling point, K_b is the ebullioscopic constant of the solvent (for water, K_b = 0.52 K·kg/mol), m is molality (moles of solute per kg of solvent), and i is the Van 't Hoff factor.
For non-electrolytes (glucose, urea), i = 1 and the formula reduces to ΔT_b = K_b · m. For electrolytes: NaCl → Na⁺ + Cl⁻ gives i ≈ 2; CaCl₂ → Ca²⁺ + 2Cl⁻ gives i ≈ 3.
Key points to lock in:
Watch out: when the question says "0.1 molal NaCl," the molality refers to the formula units dissolved, not the total ion concentration. The i factor handles the ion count separately.
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
The boiling-point elevation of a solution depends on:
The ebullioscopic constant K_b depends on:
Which of the following is used as the unit of molality?
3.0 g of urea (molar mass = 60 g/mol) is dissolved in 500 g of water. The boiling-point elevation is (K_b for water = 0.52 K·kg/mol):
The Van 't Hoff factor *i* for K₂SO₄, assuming complete dissociation, is:
0.1 molal aqueous solutions of NaCl and glucose are prepared. Which has a higher boiling point?
5.85 g of NaCl (molar mass = 58.5 g/mol) is dissolved in 250 g of water. Assuming complete dissociation, the boiling-point elevation is (K_b for water = 0.52 K·kg/mol):
An aqueous solution of a non-electrolyte solute boils at 100.26°C. If K_b for water is 0.52 K·kg/mol, the molality of the solution is:
Given
- Mass of urea (w₂) = 6.0 g - Molar mass of urea (M₂) = 60 g/mol (exact, problem-defined) - Mass of solvent (w₁) = 200 g = 0.200 kg - K_b for water = 0.52 K·kg/mol - Urea is a non-electrolyte → *i* = 1
Required
Boiling point of the solution (T_b).
Concept
Boiling-point elevation is a colligative property. A non-volatile solute raises the boiling point by ΔT_b = i · K_b · m. For non-electrolytes, *i* = 1.
Formula
ΔT_b = i · K_b · m, where m = n / (mass of solvent in kg)
Substitution
Moles of urea: n = 6.0 / 60 = 0.10 mol Molality: m = 0.10 / 0.200 = 0.50 mol/kg ΔT_b = 1 × 0.52 × 0.50
Calculation
ΔT_b = 0.52 × 0.50 = 0.26 K Note: the molar mass 60 g/mol and the integer 1 (Van 't Hoff factor for a non-electrolyte) are exact values — they do not limit significant figures. The given data (6.0 g, 200 g, 0.52 K·kg/mol) are all 2 significant figures, so the answer is reported to 2 significant figures.
Final answer
T_b = 100.00 + 0.26 = **100.26°C** The boiling point of the solution is 100.26°C (or equivalently, ΔT_b = 0.26 K).
Common trap
If the solute were NaCl instead of urea at the same molality, forgetting to multiply by *i* = 2 would give exactly half the correct ΔT_b. For any ionic solute, always ask: "How many ions does one formula unit produce?"
Similar NEET-style question
"0.5 molal aqueous solution of CaCl₂ is prepared. Calculate the elevation in boiling point. Assume complete dissociation. (K_b = 0.52 K·kg/mol)." Approach: CaCl₂ → Ca²⁺ + 2Cl⁻, so *i* = 3. ΔT_b = 3 × 0.52 × 0.5 = 0.78 K. ---
ΔT_b = K_b × m, where K_b is ebullioscopic constant of solvent (water: 0.52 K·kg/mol), m is molality.
-- NCERT Class 12 Chemistry, Ch. 1, p. 18Molal concentration: moles of solute per kg of solvent. Temperature-independent.
| Symbol | Quantity | SI Unit |
|---|---|---|
| m | molality | mol/kg |
| n | moles solute | mol |
Molar concentration: moles of solute per litre of solution.
| Symbol | Quantity | SI Unit |
|---|---|---|
| M | molarity | mol/L |
| n | moles solute | mol |
| V | solution volume | L |
Solute raises boiling point. K_b is ebullioscopic constant of solvent (water: 0.52 K kg/mol).
| Symbol | Quantity | SI Unit |
|---|---|---|
| ΔT_b | BP elevation | K |
| K_b | ebullioscopic constant | K kg/mol |
| m | molality | mol/kg |
Solute lowers freezing point. K_f is cryoscopic constant of solvent (water: 1.86 K kg/mol). Used for molar mass determination.
| Symbol | Quantity | SI Unit |
|---|---|---|
| ΔT_f | FP depression | K |
| K_f | cryoscopic constant | K kg/mol |
| m | molality | mol/kg |
Pressure required to prevent osmosis. C in mol/L; T in K. Used for high-molar-mass biomolecules.
| Symbol | Quantity | SI Unit |
|---|---|---|
| π | osmotic pressure | Pa |
| C | molarity | mol/L |
| R | gas constant | J/mol/K |
| T | temp | K |
Total vapor pressure of ideal solution = sum of mole-fraction-weighted vapor pressures of components.
| Symbol | Quantity | SI Unit |
|---|---|---|
| p | total vapor pressure | Pa |
| p_i° | pure component vp | Pa |
| x_i | mole fraction | - |
For non-volatile solute: relative lowering of VP equals mole fraction of solute.
| Symbol | Quantity | SI Unit |
|---|---|---|
| p | solution vp | Pa |
| p° | pure solvent vp | Pa |
| x_solute | mole fraction | - |
Correction factor for electrolytes. NaCl: i≈2; CaCl₂: i≈3. Multiply colligative formula by i.
| Symbol | Quantity | SI Unit |
|---|---|---|
| i | Van't Hoff factor | - |
These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.
Category: Similar Terms
Student uses mass fraction (w₁/total mass) where mole fraction (n₁/total moles) is required.
Question gives masses or molar masses and asks about Raoult's law or vapor pressure.
Raoult's law uses MOLE fractions, not mass fractions. Convert mass to moles first using molar mass.
Category: Similar Terms
Student uses non-electrolyte colligative formula for ionic compound. NaCl: i ≈ 2; CaCl₂: i ≈ 3.
Question gives an ionic compound (NaCl, CaCl₂, K₂SO₄) and asks for colligative property.
For electrolytes, multiply colligative formula by Van't Hoff factor i. NaCl → Na⁺ + Cl⁻ (i=2). CaCl₂ → Ca²⁺ + 2Cl⁻ (i=3). K₂SO₄ → 2K⁺ + SO₄²⁻ (i=3).
Root cause: formula misuse
Convert mass to moles first using molar mass. Raoult uses MOLE fractions.
Root cause: formula misuse
For NaCl i ≈ 2, CaCl₂ i ≈ 3, K₂SO₄ i ≈ 3. Multiply colligative formulas by i.
9 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.
Which of the following aqueous solution will exhibit highest boiling point?
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The structures of beryllium chloride in solid state and vapour phase, are :
Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.
forgets i factor electrolytes
Uses non-electrolyte formula for ionic solute
forgets conversion of units
Mixes Pa with atm; L with m^3
uses mass fractions not mole
Substitutes mass fraction for x
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