Elevation Boiling Point

8 MCQs3 revision cards9-step worked example
Source: NCERT SolutionsPYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

When you dissolve a non-volatile solute in a solvent, the boiling point of the solution is higher than that of the pure solvent. This is boiling-point elevation — a colligative property that depends only on the number of solute particles, not their identity.

The trap that costs marks: an ionic compound like NaCl dissociates into ions. If a question hands you NaCl dissolved in water and you plug molality straight into ΔT_b = K_b · m, you get the answer for a non-electrolyte. The actual elevation is larger because NaCl produces two ions per formula unit — you must multiply by the Van 't Hoff factor i. Forgetting i is a common confusion in NEET colligative-property calculations.

The core relationship (NCERT Class 12 Chemistry Chapter 1, page 18):

ΔT_b = i · K_b · m

where ΔT_b is the elevation in boiling point, K_b is the ebullioscopic constant of the solvent (for water, K_b = 0.52 K·kg/mol), m is molality (moles of solute per kg of solvent), and i is the Van 't Hoff factor.

For non-electrolytes (glucose, urea), i = 1 and the formula reduces to ΔT_b = K_b · m. For electrolytes: NaCl → Na⁺ + Cl⁻ gives i ≈ 2; CaCl₂ → Ca²⁺ + 2Cl⁻ gives i ≈ 3.

Key points to lock in:

  1. Molality, not molarity — colligative formulas use moles of solute per kg of solvent, not per litre of solution. Molality is temperature-independent.
  2. K_b is a solvent property. Water's K_b = 0.52 K·kg/mol. Different solvents have different K_b values.
  3. Higher ΔT_b means more solute particles. Comparing 0.1 m NaCl (i = 2) vs 0.1 m glucose (i = 1): NaCl gives double the elevation.
  4. Boiling-point elevation can be used to determine molar mass of an unknown non-electrolyte solute: M₂ = (i · K_b · w₂ × 1000) / (ΔT_b · w₁), where w₂ is mass of solute and w₁ is mass of solvent in grams.

Watch out: when the question says "0.1 molal NaCl," the molality refers to the formula units dissolved, not the total ion concentration. The i factor handles the ion count separately.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

The boiling-point elevation of a solution depends on:

MCQ 2Easy RecallPractice

The ebullioscopic constant K_b depends on:

MCQ 3Easy RecallPractice

Which of the following is used as the unit of molality?

MCQ 4Direct ApplicationPractice

3.0 g of urea (molar mass = 60 g/mol) is dissolved in 500 g of water. The boiling-point elevation is (K_b for water = 0.52 K·kg/mol):

MCQ 5Direct ApplicationPractice

The Van 't Hoff factor *i* for K₂SO₄, assuming complete dissociation, is:

MCQ 6Direct ApplicationPractice

0.1 molal aqueous solutions of NaCl and glucose are prepared. Which has a higher boiling point?

MCQ 7CalculationPractice

5.85 g of NaCl (molar mass = 58.5 g/mol) is dissolved in 250 g of water. Assuming complete dissociation, the boiling-point elevation is (K_b for water = 0.52 K·kg/mol):

MCQ 8CalculationPractice

An aqueous solution of a non-electrolyte solute boils at 100.26°C. If K_b for water is 0.52 K·kg/mol, the molality of the solution is:

Quick recall before you leave

Worked Example

  1. 1

    Given

    - Mass of urea (w₂) = 6.0 g - Molar mass of urea (M₂) = 60 g/mol (exact, problem-defined) - Mass of solvent (w₁) = 200 g = 0.200 kg - K_b for water = 0.52 K·kg/mol - Urea is a non-electrolyte → *i* = 1

  2. 2

    Required

    Boiling point of the solution (T_b).

  3. 3

    Concept

    Boiling-point elevation is a colligative property. A non-volatile solute raises the boiling point by ΔT_b = i · K_b · m. For non-electrolytes, *i* = 1.

  4. 4

    Formula

    ΔT_b = i · K_b · m, where m = n / (mass of solvent in kg)

  5. 5

    Substitution

    Moles of urea: n = 6.0 / 60 = 0.10 mol Molality: m = 0.10 / 0.200 = 0.50 mol/kg ΔT_b = 1 × 0.52 × 0.50

  6. 6

    Calculation

    ΔT_b = 0.52 × 0.50 = 0.26 K Note: the molar mass 60 g/mol and the integer 1 (Van 't Hoff factor for a non-electrolyte) are exact values — they do not limit significant figures. The given data (6.0 g, 200 g, 0.52 K·kg/mol) are all 2 significant figures, so the answer is reported to 2 significant figures.

  7. 7

    Final answer

    T_b = 100.00 + 0.26 = **100.26°C** The boiling point of the solution is 100.26°C (or equivalently, ΔT_b = 0.26 K).

  8. 8

    Common trap

    If the solute were NaCl instead of urea at the same molality, forgetting to multiply by *i* = 2 would give exactly half the correct ΔT_b. For any ionic solute, always ask: "How many ions does one formula unit produce?"

  9. 9

    Similar NEET-style question

    "0.5 molal aqueous solution of CaCl₂ is prepared. Calculate the elevation in boiling point. Assume complete dissociation. (K_b = 0.52 K·kg/mol)." Approach: CaCl₂ → Ca²⁺ + 2Cl⁻, so *i* = 3. ΔT_b = 3 × 0.52 × 0.5 = 0.78 K. ---

Before solving, remember these

ΔT_b = K_b × m, where K_b is ebullioscopic constant of solvent (water: 0.52 K·kg/mol), m is molality.

-- NCERT Class 12 Chemistry, Ch. 1, p. 18

Formulas

Molality

Molal concentration: moles of solute per kg of solvent. Temperature-independent.

SymbolQuantitySI Unit
mmolalitymol/kg
nmoles solutemol

Valid when

  • Mass of SOLVENT (not solution)

Molarity

Molar concentration: moles of solute per litre of solution.

SymbolQuantitySI Unit
Mmolaritymol/L
nmoles solutemol
Vsolution volumeL

Valid when

  • Volume of SOLUTION not solvent
  • Temperature dependent (volume changes with T)

Boiling-point elevation

Solute raises boiling point. K_b is ebullioscopic constant of solvent (water: 0.52 K kg/mol).

SymbolQuantitySI Unit
ΔT_bBP elevationK
K_bebullioscopic constantK kg/mol
mmolalitymol/kg

Valid when

  • Dilute solution
  • Non-electrolyte

Freezing-point depression

Solute lowers freezing point. K_f is cryoscopic constant of solvent (water: 1.86 K kg/mol). Used for molar mass determination.

SymbolQuantitySI Unit
ΔT_fFP depressionK
K_fcryoscopic constantK kg/mol
mmolalitymol/kg

Valid when

  • Dilute solution
  • Non-electrolyte (else multiply by i)

Osmotic pressure

Pressure required to prevent osmosis. C in mol/L; T in K. Used for high-molar-mass biomolecules.

SymbolQuantitySI Unit
πosmotic pressurePa
Cmolaritymol/L
Rgas constantJ/mol/K
TtempK

Valid when

  • Dilute solution
  • Semipermeable membrane separating pure solvent from solution

Raoult's law

Total vapor pressure of ideal solution = sum of mole-fraction-weighted vapor pressures of components.

SymbolQuantitySI Unit
ptotal vapor pressurePa
p_i°pure component vpPa
x_imole fraction-

Valid when

  • Ideal solution
  • Both volatile

Relative lowering of VP

For non-volatile solute: relative lowering of VP equals mole fraction of solute.

SymbolQuantitySI Unit
psolution vpPa
pure solvent vpPa
x_solutemole fraction-

Valid when

  • Non-volatile solute
  • Dilute solution
  • Non-electrolyte (else use i)

Van't Hoff factor

Correction factor for electrolytes. NaCl: i≈2; CaCl₂: i≈3. Multiply colligative formula by i.

SymbolQuantitySI Unit
iVan't Hoff factor-

Valid when

  • Electrolyte solution
  • Account for ion-pair association/dissociation

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Similar Terms

Student uses mass fraction (w₁/total mass) where mole fraction (n₁/total moles) is required.

When it triggers

Question gives masses or molar masses and asks about Raoult's law or vapor pressure.

How to avoid

Raoult's law uses MOLE fractions, not mass fractions. Convert mass to moles first using molar mass.

Category: Similar Terms

Student uses non-electrolyte colligative formula for ionic compound. NaCl: i ≈ 2; CaCl₂: i ≈ 3.

When it triggers

Question gives an ionic compound (NaCl, CaCl₂, K₂SO₄) and asks for colligative property.

How to avoid

For electrolytes, multiply colligative formula by Van't Hoff factor i. NaCl → Na⁺ + Cl⁻ (i=2). CaCl₂ → Ca²⁺ + 2Cl⁻ (i=3). K₂SO₄ → 2K⁺ + SO₄²⁻ (i=3).

Past Year Questions

9 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2024Revised key

Given below are two statements: Statement I: The boiling point of hydrides of Group 16 elements follow the order H O > H Te > H Se > H S. 2 2 2 2 Statement II: On the basis of molecular mass, H O is expected to have lower boiling point than the other 2 members of the group but due to the presence of extensive H-bonding in H O, it has higher boiling point. 2 In the light of the above statements, choose the correct answer from the options given below:

1Both Statement I and Statement II are true
2Both Statement I and Statement II are false
3Statement I is true but Statement II is false
4Statement I is false but Statement II is true
NTA Answer: Option 1(revised_final)
NEET 2023

Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R Assertion A : Helium is used to dilute oxygen in diving apparatus. Reason R : Helium has high solubility in O . 2 In the light of the above statements, choose the correct answer from the options given below

1Both A and R are true and R is NOT the correct explanation of A
2A is true but R is false
3A is false but R is true
4Both A and R are true and R is the correct explanation of A
NTA Answer: Option 2(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Sources

NCERT refs: Class 12 Chemistry Chapter 1, p.18

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