Ideal Non Ideal Solutions

8 MCQs1 revision card9-step worked example
Source: NCERT SolutionsPYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The trap that costs marks on ideal vs. non-ideal solution questions is deceptively simple: you're given masses of two liquids and asked to find the total vapour pressure. You plug the masses straight into Raoult's law as if they were mole fractions. They aren't. Raoult's law demands mole fractions, not mass fractions — and confusing the two produces a wrong answer that often appears as a distractor.

What makes a solution ideal? NCERT Class 12 Chemistry Chapter 1 (page 10) defines an ideal solution as one where the intermolecular forces between solute–solvent, solute–solute, and solvent–solvent are nearly identical. In such a solution, each component obeys Raoult's law over the entire composition range:

p = p₁° x₁ + p₂° x₂

where p₁° and p₂° are vapour pressures of the pure components and x₁, x₂ are their mole fractions.

Key signatures of an ideal solution: ΔH_mix = 0, ΔV_mix = 0. Examples: benzene + toluene, n-hexane + n-heptane.

Non-ideal solutions deviate because intermolecular forces change on mixing:

  • Positive deviation (A–B forces weaker than A–A and B–B): observed VP > Raoult's law prediction. Example: ethanol + acetone. Can form a minimum-boiling azeotrope.
  • Negative deviation (A–B forces stronger): observed VP < Raoult's law prediction. Example: chloroform + acetone. Can form a maximum-boiling azeotrope.

NEET connection: Questions test whether you can (a) calculate total VP from mole fractions using Raoult's law, and (b) classify a system as positive or negative deviation from given data. The mole-vs-mass fraction trap appears as a distractor in Raoult's law VP calculations — a common source of negative marks.

Watch out: When a problem gives component amounts in grams, always convert to moles first. The number you divide by total moles is the mole fraction — never the mass ratio.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Which of the following is a characteristic of an ideal solution?

MCQ 2Easy RecallPractice

An ethanol–acetone mixture shows a total vapour pressure higher than predicted by Raoult's law. This is an example of:

MCQ 3Easy RecallPractice

Which pair of liquids is most likely to form an ideal solution?

MCQ 4Direct ApplicationPractice

A solution of two volatile liquids A and B has p°_A = 300 mmHg and p°_B = 500 mmHg. If x_A = 0.40, the total vapour pressure of the ideal solution is:

MCQ 5Direct ApplicationPractice

46 g of ethanol (M = 46 g/mol) and 18 g of water (M = 18 g/mol) are mixed. The mole fraction of ethanol in the solution is:

MCQ 6Direct ApplicationPractice

A binary liquid mixture shows negative deviation from Raoult's law. Which statement is correct?

MCQ 7CalculationPractice

Two liquids A (M_A = 78 g/mol, p°_A = 120 mmHg) and B (M_B = 92 g/mol, p°_B = 60 mmHg) form an ideal solution. If 78 g of A and 184 g of B are mixed, the total vapour pressure is:

MCQ 8Concept TrapPractice

For an ideal solution of two volatile components, a plot of total vapour pressure (p) vs. mole fraction of component A (x_A) is:

Quick recall before you leave

Worked Example

  1. 1

    Given

    Two volatile liquids P and Q form an ideal solution. p°_P = 150 mmHg, p°_Q = 350 mmHg. M_P = 60 g/mol, M_Q = 40 g/mol. A solution contains 120 g of P and 80 g of Q.

  2. 2

    Required

    Total vapour pressure of the solution.

  3. 3

    Concept

    For an ideal solution, Raoult's law states that total VP is the sum of each component's pure VP weighted by its mole fraction. The mole fraction must be calculated from moles — not from mass.

  4. 4

    Formula

    p = p°_P × x_P + p°_Q × x_Q

  5. 5

    Substitution setup

    Moles of P = 120/60 = 2 mol Moles of Q = 80/40 = 2 mol Total moles = 4 mol x_P = 2/4 = 0.50, x_Q = 2/4 = 0.50 p = 150 × 0.50 + 350 × 0.50

  6. 6

    Calculation

    p = 75 + 175 = 250 mmHg Note: the molar masses (60 g/mol, 40 g/mol) are exact problem-defined values and do not limit significant figures.

  7. 7

    Final answer

    Total vapour pressure = 250 mmHg

  8. 8

    Common trap

    If you used mass fractions instead of mole fractions: mass fraction of P = 120/200 = 0.60, mass fraction of Q = 0.40. Then p = 150 × 0.60 + 350 × 0.40 = 90 + 140 = 230 mmHg — a wrong answer that would appear as a distractor. The error: Raoult's law uses mole fractions, not mass fractions.

  9. 9

    Similar NEET-style question

    Benzene (M = 78 g/mol, p° = 100 mmHg) and toluene (M = 92 g/mol, p° = 40 mmHg) form an ideal solution. If 39 g of benzene is mixed with 46 g of toluene, find the total vapour pressure. (Answer: moles benzene = 0.50, moles toluene = 0.50; x = 0.50 each; p = 100 × 0.50 + 40 × 0.50 = 70 mmHg.) ---

Before solving, remember these

Ideal: obeys Raoult's law over all composition; ΔH_mix = 0, ΔV_mix = 0 (e.g. n-hexane + n-heptane). Positive deviation: A-B interactions weaker than A-A, B-B (more volatile). Negative deviation: A-B stronger (less volatile).

-- NCERT Class 12 Chemistry, Ch. 1, p. 10

Formulas

Molality

Molal concentration: moles of solute per kg of solvent. Temperature-independent.

SymbolQuantitySI Unit
mmolalitymol/kg
nmoles solutemol

Valid when

  • Mass of SOLVENT (not solution)

Molarity

Molar concentration: moles of solute per litre of solution.

SymbolQuantitySI Unit
Mmolaritymol/L
nmoles solutemol
Vsolution volumeL

Valid when

  • Volume of SOLUTION not solvent
  • Temperature dependent (volume changes with T)

Boiling-point elevation

Solute raises boiling point. K_b is ebullioscopic constant of solvent (water: 0.52 K kg/mol).

SymbolQuantitySI Unit
ΔT_bBP elevationK
K_bebullioscopic constantK kg/mol
mmolalitymol/kg

Valid when

  • Dilute solution
  • Non-electrolyte

Freezing-point depression

Solute lowers freezing point. K_f is cryoscopic constant of solvent (water: 1.86 K kg/mol). Used for molar mass determination.

SymbolQuantitySI Unit
ΔT_fFP depressionK
K_fcryoscopic constantK kg/mol
mmolalitymol/kg

Valid when

  • Dilute solution
  • Non-electrolyte (else multiply by i)

Osmotic pressure

Pressure required to prevent osmosis. C in mol/L; T in K. Used for high-molar-mass biomolecules.

SymbolQuantitySI Unit
πosmotic pressurePa
Cmolaritymol/L
Rgas constantJ/mol/K
TtempK

Valid when

  • Dilute solution
  • Semipermeable membrane separating pure solvent from solution

Raoult's law

Total vapor pressure of ideal solution = sum of mole-fraction-weighted vapor pressures of components.

SymbolQuantitySI Unit
ptotal vapor pressurePa
p_i°pure component vpPa
x_imole fraction-

Valid when

  • Ideal solution
  • Both volatile

Relative lowering of VP

For non-volatile solute: relative lowering of VP equals mole fraction of solute.

SymbolQuantitySI Unit
psolution vpPa
pure solvent vpPa
x_solutemole fraction-

Valid when

  • Non-volatile solute
  • Dilute solution
  • Non-electrolyte (else use i)

Van't Hoff factor

Correction factor for electrolytes. NaCl: i≈2; CaCl₂: i≈3. Multiply colligative formula by i.

SymbolQuantitySI Unit
iVan't Hoff factor-

Valid when

  • Electrolyte solution
  • Account for ion-pair association/dissociation

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Similar Terms

Student uses mass fraction (w₁/total mass) where mole fraction (n₁/total moles) is required.

When it triggers

Question gives masses or molar masses and asks about Raoult's law or vapor pressure.

How to avoid

Raoult's law uses MOLE fractions, not mass fractions. Convert mass to moles first using molar mass.

Category: Similar Terms

Student uses non-electrolyte colligative formula for ionic compound. NaCl: i ≈ 2; CaCl₂: i ≈ 3.

When it triggers

Question gives an ionic compound (NaCl, CaCl₂, K₂SO₄) and asks for colligative property.

How to avoid

For electrolytes, multiply colligative formula by Van't Hoff factor i. NaCl → Na⁺ + Cl⁻ (i=2). CaCl₂ → Ca²⁺ + 2Cl⁻ (i=3). K₂SO₄ → 2K⁺ + SO₄²⁻ (i=3).

Past Year Questions

9 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2024Revised key

Given below are two statements: Statement I: The boiling point of hydrides of Group 16 elements follow the order H O > H Te > H Se > H S. 2 2 2 2 Statement II: On the basis of molecular mass, H O is expected to have lower boiling point than the other 2 members of the group but due to the presence of extensive H-bonding in H O, it has higher boiling point. 2 In the light of the above statements, choose the correct answer from the options given below:

1Both Statement I and Statement II are true
2Both Statement I and Statement II are false
3Statement I is true but Statement II is false
4Statement I is false but Statement II is true
NTA Answer: Option 1(revised_final)
NEET 2023

Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R Assertion A : Helium is used to dilute oxygen in diving apparatus. Reason R : Helium has high solubility in O . 2 In the light of the above statements, choose the correct answer from the options given below

1Both A and R are true and R is NOT the correct explanation of A
2A is true but R is false
3A is false but R is true
4Both A and R are true and R is the correct explanation of A
NTA Answer: Option 2(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

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