For ideal solutions: p_total = p₁°χ₁ + p₂°χ₂. Vapour pressure of solution lies between vapour pressures of pure components and varies linearly with mole fraction.
-- NCERT Class 12 Chemistry, Ch. 1, p. 8Vapour Pressure Raoult
Lesson
The trap that costs marks on Raoult's law questions is deceptively simple: substituting mass fractions where mole fractions are required. A question gives you 46 g of ethanol and 72 g of water, and you divide masses instead of converting to moles first. The answer you get looks reasonable — but it is wrong, and it earns you −1.
Raoult's law states that the partial vapour pressure of each component in an ideal binary solution equals the product of its pure-component vapour pressure and its mole fraction in the liquid phase (NCERT Class 12 Chemistry Chapter 1, page 8):
p = p₁° x₁ + p₂° x₂
Here p₁° and p₂° are the vapour pressures of pure components 1 and 2, and x₁, x₂ are their mole fractions in the liquid (x₁ + x₂ = 1). The total vapour pressure p varies linearly with composition for an ideal solution — this is the signature of Raoult's law.
Where it applies: both components must be volatile, and the solution must behave ideally (similar intermolecular forces — e.g., benzene + toluene, hexane + heptane).
The mole-fraction trap in detail. When a stem gives masses, you must:
- Convert each mass to moles: n = mass / molar mass.
- Calculate mole fractions: x₁ = n₁ / (n₁ + n₂).
- Only then substitute into Raoult's law.
Skipping step 1 — using mass ratios directly — is the documented high-frequency mistake on this topic. Every distractor option that looks "close but off" in a Raoult's law question is likely the mass-fraction answer.
Watch out: if only one component is volatile (non-volatile solute dissolved in a volatile solvent), Raoult's law simplifies to the relative lowering of vapour pressure form, which is a separate topic.
Practice MCQs
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
According to Raoult's law, the partial vapour pressure of a component in an ideal solution is directly proportional to which quantity?
Raoult's law in the form p = p₁° x₁ + p₂° x₂ applies when:
For an ideal binary solution obeying Raoult's law, the plot of total vapour pressure versus mole fraction of one component is:
A solution contains 2 mol of benzene (p° = 100 mmHg) and 3 mol of toluene (p° = 40 mmHg). Assuming ideal behaviour, the total vapour pressure of the solution is:
46 g of ethanol (M = 46 g/mol, p° = 44 mmHg) is mixed with 36 g of water (M = 18 g/mol, p° = 55 mmHg). Assuming an ideal solution, the total vapour pressure is closest to:
For an ideal solution of A (p°_A = 300 mmHg) and B (p°_B = 100 mmHg), at what mole fraction of A will the total vapour pressure be 200 mmHg?
78 g of benzene (M = 78 g/mol, p° = 120 mmHg) is mixed with 92 g of toluene (M = 92 g/mol, p° = 50 mmHg). The mole fraction of benzene in the **vapour phase** is closest to:
An ideal solution is prepared by mixing 32 g of methanol (M = 32 g/mol, p° = 90 mmHg) and 46 g of ethanol (M = 46 g/mol, p° = 45 mmHg). The total vapour pressure of the solution is:
Quick recall before you leave
Worked Example
Pattern: Raoult's law VP calculation (NEET pattern: raoults law vp)
- 1
Given
A solution contains 60 g of component A (molar mass = 60 g/mol, p°_A = 150 mmHg) and 40 g of component B (molar mass = 80 g/mol, p°_B = 60 mmHg). Assume ideal behaviour.
- 2
Required
Total vapour pressure of the solution.
- 3
Concept
Raoult's law: each component's partial vapour pressure equals its pure VP multiplied by its mole fraction in the liquid phase. The total VP is the sum of partial pressures.
- 4
Formula
p = p°_A x_A + p°_B x_B
- 5
Substitution
n_A = 60/60 = 1.00 mol n_B = 40/80 = 0.50 mol x_A = 1.00/(1.00 + 0.50) = 1.00/1.50 = 0.667 x_B = 0.50/1.50 = 0.333 p = 150 × 0.667 + 60 × 0.333
- 6
Calculation
p = 100.0 + 20.0 = 120.0 mmHg Note: the molar masses 60 g/mol and 80 g/mol are exact problem-defined values and do not limit significant figures in this calculation.
- 7
Final answer
p = 120 mmHg
- 8
Common trap
If you used mass fractions instead of mole fractions: mass fraction of A = 60/100 = 0.60, mass fraction of B = 0.40 → p = 150 × 0.60 + 60 × 0.40 = 90 + 24 = 114 mmHg. This is **wrong** — and it would appear as a tempting distractor option.
- 9
Similar NEET-style question
A solution contains 46 g of ethanol (M = 46, p° = 44 mmHg) and 18 g of water (M = 18, p° = 55 mmHg). Find the total vapour pressure assuming ideal behaviour. [Answer: n_ethanol = 1, n_water = 1; x = 0.5 each; p = 44 × 0.5 + 55 × 0.5 = 49.5 mmHg.] ---
Before solving, remember these
Formulas
Molality
Molal concentration: moles of solute per kg of solvent. Temperature-independent.
| Symbol | Quantity | SI Unit |
|---|---|---|
| m | molality | mol/kg |
| n | moles solute | mol |
Valid when
- Mass of SOLVENT (not solution)
Molarity
Molar concentration: moles of solute per litre of solution.
| Symbol | Quantity | SI Unit |
|---|---|---|
| M | molarity | mol/L |
| n | moles solute | mol |
| V | solution volume | L |
Valid when
- Volume of SOLUTION not solvent
- Temperature dependent (volume changes with T)
Boiling-point elevation
Solute raises boiling point. K_b is ebullioscopic constant of solvent (water: 0.52 K kg/mol).
| Symbol | Quantity | SI Unit |
|---|---|---|
| ΔT_b | BP elevation | K |
| K_b | ebullioscopic constant | K kg/mol |
| m | molality | mol/kg |
Valid when
- Dilute solution
- Non-electrolyte
Freezing-point depression
Solute lowers freezing point. K_f is cryoscopic constant of solvent (water: 1.86 K kg/mol). Used for molar mass determination.
| Symbol | Quantity | SI Unit |
|---|---|---|
| ΔT_f | FP depression | K |
| K_f | cryoscopic constant | K kg/mol |
| m | molality | mol/kg |
Valid when
- Dilute solution
- Non-electrolyte (else multiply by i)
Osmotic pressure
Pressure required to prevent osmosis. C in mol/L; T in K. Used for high-molar-mass biomolecules.
| Symbol | Quantity | SI Unit |
|---|---|---|
| π | osmotic pressure | Pa |
| C | molarity | mol/L |
| R | gas constant | J/mol/K |
| T | temp | K |
Valid when
- Dilute solution
- Semipermeable membrane separating pure solvent from solution
Raoult's law
Total vapor pressure of ideal solution = sum of mole-fraction-weighted vapor pressures of components.
| Symbol | Quantity | SI Unit |
|---|---|---|
| p | total vapor pressure | Pa |
| p_i° | pure component vp | Pa |
| x_i | mole fraction | - |
Valid when
- Ideal solution
- Both volatile
Relative lowering of VP
For non-volatile solute: relative lowering of VP equals mole fraction of solute.
| Symbol | Quantity | SI Unit |
|---|---|---|
| p | solution vp | Pa |
| p° | pure solvent vp | Pa |
| x_solute | mole fraction | - |
Valid when
- Non-volatile solute
- Dilute solution
- Non-electrolyte (else use i)
Van't Hoff factor
Correction factor for electrolytes. NaCl: i≈2; CaCl₂: i≈3. Multiply colligative formula by i.
| Symbol | Quantity | SI Unit |
|---|---|---|
| i | Van't Hoff factor | - |
Valid when
- Electrolyte solution
- Account for ion-pair association/dissociation
Exam Traps & Common Mistakes
These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.
Category: Similar Terms
Student uses mass fraction (w₁/total mass) where mole fraction (n₁/total moles) is required.
When it triggers
Question gives masses or molar masses and asks about Raoult's law or vapor pressure.
How to avoid
Raoult's law uses MOLE fractions, not mass fractions. Convert mass to moles first using molar mass.
Category: Similar Terms
Student uses non-electrolyte colligative formula for ionic compound. NaCl: i ≈ 2; CaCl₂: i ≈ 3.
When it triggers
Question gives an ionic compound (NaCl, CaCl₂, K₂SO₄) and asks for colligative property.
How to avoid
For electrolytes, multiply colligative formula by Van't Hoff factor i. NaCl → Na⁺ + Cl⁻ (i=2). CaCl₂ → Ca²⁺ + 2Cl⁻ (i=3). K₂SO₄ → 2K⁺ + SO₄²⁻ (i=3).
Root cause: formula misuse
Correction
Convert mass to moles first using molar mass. Raoult uses MOLE fractions.
Root cause: formula misuse
Correction
For NaCl i ≈ 2, CaCl₂ i ≈ 3, K₂SO₄ i ≈ 3. Multiply colligative formulas by i.
Past Year Questions
9 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.
Which of the following aqueous solution will exhibit highest boiling point?
The IUPAC name of an element with atomic number 119 is
The structures of beryllium chloride in solid state and vapour phase, are :
How NEET usually asks this
Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.
Calculate ΔT_f or ΔT_b given molality. Or determine molar mass from observed colligative property.
Common distractors
forgets i factor electrolytes
Uses non-electrolyte formula for ionic solute
π = CRT. Find molar mass of solute from observed osmotic pressure.
Common distractors
forgets conversion of units
Mixes Pa with atm; L with m^3
Find total VP of ideal solution from mole fractions and pure-component VPs.
Common distractors
uses mass fractions not mole
Substitutes mass fraction for x
Sources
Test yourself on this topic with real past-paper questions:
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