Common batteries
Dry cell (Leclanché): Zn anode, MnO₂/C cathode, ~1.5 V. Lead accumulator: Pb anode, PbO₂ cathode, H₂SO₄ electrolyte, ~2 V/cell. Fuel cell: H₂/O₂ → H₂O + electrical energy.
-- NCERT Class 12 Chemistry, Ch. 2, p. 54The dry cell (Leclanché cell) and the lead-acid accumulator are two commercially important electrochemical cells that NEET tests at the recall and direct-application level. The topic appears with low-to-medium frequency (~0.4 questions/year), but when it appears, marks are easy to secure — or easy to lose if you confuse the electrode reactions.
Dry cell (Leclanché cell). The anode is zinc (the outer casing). The cathode is a carbon rod surrounded by powdered MnO₂ and carbon black. The electrolyte is a moist paste of NH₄Cl and ZnCl₂. At the anode: Zn → Zn²⁺ + 2e⁻. At the cathode: MnO₂ + NH₄⁺ + e⁻ → MnO(OH) + NH₃. The cell potential is approximately 1.5 V. It is a primary cell — non-rechargeable — because the zinc casing is irreversibly consumed (NCERT Class 12 Chemistry Chapter 2, page 54).
Lead-acid accumulator. The anode is spongy lead (Pb). The cathode is PbO₂ packed on a lead grid. The electrolyte is ~38% H₂SO₄. During discharge: at the anode, Pb → PbSO₄; at the cathode, PbO₂ → PbSO₄. Both electrodes convert to lead sulfate — this is the key detail NEET exploits. The cell potential is approximately 2 V per cell (six cells give the familiar 12 V car battery). It is a secondary cell — rechargeable — because the electrode reactions reverse on applying external voltage.
Common confusion NEET targets: mixing up which cell is primary vs. secondary; confusing the anode material (zinc in dry cell, lead in accumulator); forgetting that both electrodes in the lead accumulator form PbSO₄ during discharge; and misidentifying the electrolyte (paste in dry cell, dilute H₂SO₄ in accumulator).
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
In a Leclanché dry cell, the anode is made of:
Answer: D. The zinc casing acts as the anode in a dry cell. The carbon rod is the current collector at the cathode side (NCERT Class 12 Chemistry Chapter 2, page 54).
Why A is wrong: A — The carbon rod serves as the cathode current collector, not the anode. This is a frequent swap error.
Why B is wrong: B — MnO₂ is the depolarizer packed around the cathode carbon rod, not the anode.
Why C is wrong: C — Lead is the anode material in a lead-acid accumulator, not in a dry cell.
The lead-acid accumulator is classified as a:
Answer: A. A lead-acid accumulator is rechargeable — its electrode reactions are reversible upon applying external voltage — making it a secondary cell (NCERT Class 12 Chemistry Chapter 2, page 54).
Why B is wrong: B — A fuel cell continuously consumes fuel (e.g., H₂-O₂ cell). The accumulator stores chemical energy internally.
Why C is wrong: C — A primary cell is non-rechargeable (e.g., the dry cell). The lead accumulator can be recharged by reversing the discharge reactions.
Why D is wrong: D — A concentration cell has identical electrodes differing only in electrolyte concentration. The lead accumulator has two different electrode materials (Pb and PbO₂).
The electrolyte used in a dry cell is:
Answer: B. The Leclanché dry cell uses a moist paste of ammonium chloride and zinc chloride as the electrolyte (NCERT Class 12 Chemistry Chapter 2, page 54).
Why A is wrong: A — Dilute H₂SO₄ is the electrolyte of the lead-acid accumulator, not the dry cell.
Why C is wrong: C — Concentrated HCl is not used in any standard commercial cell discussed in the NCERT syllabus.
Why D is wrong: D — Aqueous KOH is used in alkaline batteries and certain fuel cells, not in the standard Leclanché dry cell.
During discharge of a lead-acid accumulator, the product formed at BOTH electrodes is:
Answer: C. During discharge, Pb at the anode is oxidized to PbSO₄ and PbO₂ at the cathode is reduced to PbSO₄. Both electrodes convert to lead sulfate (NCERT Class 12 Chemistry Chapter 2, page 54).
Why A is wrong: A — Spongy Pb is the anode material BEFORE discharge. During discharge it is consumed, not formed.
Why B is wrong: B — PbO is not a product in either the discharge or charge half-reactions of the lead-acid cell.
Why D is wrong: D — PbO₂ is the cathode material before discharge. It is consumed during discharge, not formed.
A standard car battery is rated at 12 V. If each lead-acid cell produces approximately 2 V, the number of cells connected in series is:
Answer: C. Number of cells = total voltage / voltage per cell = 12 V / 2 V = 6. Six cells are connected in series in a standard 12 V lead-acid battery.
Why A is wrong: A — 3 cells × 2 V = 6 V, not 12 V. This error halves the cell count.
Why B is wrong: B — 4 cells × 2 V = 8 V. This does not match the 12 V rating.
Why D is wrong: D — This would give 12 × 2 V = 24 V, which is a heavy-duty truck battery, not a standard car battery.
During the charging of a lead-acid accumulator, the reaction at the cathode (negative plate) is:
Answer: B. During charging, the reaction reverses. At the negative plate (cathode during charging), PbSO₄ is reduced back to spongy Pb: PbSO₄ + 2e⁻ → Pb + SO₄²⁻ (NCERT Class 12 Chemistry Chapter 2, page 54).
Why A is wrong: A — This is a generic oxidation half-reaction, not the specific charging cathode reaction. During charging, reduction occurs at the cathode.
Why C is wrong: C — This is the reaction at the positive plate (anode) during charging, where PbSO₄ is oxidized back to PbO₂. This is the opposite electrode.
Why D is wrong: D — This is the cathode reaction during DISCHARGE, not during charging. Charging reverses the discharge reactions.
Which of the following correctly distinguishes a dry cell from a lead-acid accumulator?
Answer: A. The dry cell operates at ~1.5 V and is a primary (non-rechargeable) cell, while each cell in the lead-acid accumulator operates at ~2 V and is secondary (rechargeable). The voltage distinction is a direct factual comparison (NCERT Class 12 Chemistry Chapter 2, page 54).
Why B is wrong: B — This swaps the electrolytes. The dry cell uses NH₄Cl/ZnCl₂ paste; the lead accumulator uses dilute H₂SO₄.
Why C is wrong: C — This reverses the classification. The dry cell is primary (non-rechargeable) and the lead accumulator is secondary (rechargeable).
Why D is wrong: D — The lead-acid accumulator is rechargeable (secondary). Only the dry cell is non-rechargeable (primary).
When a lead-acid accumulator is fully discharged, the density of the H₂SO₄ electrolyte decreases. The best explanation is:
Answer: D. The overall discharge reaction consumes H₂SO₄ and produces water (Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O). As sulfuric acid is consumed and water is formed, the electrolyte becomes more dilute and its density drops. This density change is used practically to test the state of charge.
Why A is wrong: A — Evaporation would increase acid concentration and density, not decrease it. The opposite is observed during discharge.
Why B is wrong: B — SO₄²⁻ ions are incorporated into solid PbSO₄ on the electrode plates, not removed from the cell. The net effect is H₂SO₄ depletion from the electrolyte.
Why C is wrong: C — Lead does not dissolve freely in the acid. Lead converts to PbSO₄ at the electrode surface; it is the consumption of H₂SO₄ that drives the density decrease.
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Given
A lead-acid accumulator consists of cells, each with spongy Pb as anode and PbO₂ as cathode, with ~38% H₂SO₄ electrolyte. Each cell produces approximately 2 V. A battery is rated at 12 V.
Required
(a) Number of cells in the battery.
(b) Write the overall discharge reaction.
(c) Explain why electrolyte density decreases during discharge.
Concept
The lead-acid accumulator is a secondary cell. During discharge, both electrodes form PbSO₄ and H₂SO₄ is consumed with water produced. Cells are connected in series so total voltage = n × voltage per cell.
Formula
Total voltage = number of cells × voltage per cell.
Overall discharge: Pb(s) + PbO₂(s) + 2H₂SO₄(aq) → 2PbSO₄(s) + 2H₂O(l)
Substitution
12 V = n × 2 V
Calculation
n = 12 / 2 = 6 cells.
Note: 12 and 2 are exact integers (specified values), so no significant-figure ambiguity arises.
Final answer
(a) 6 cells connected in series.
(b) Pb(s) + PbO₂(s) + 2H₂SO₄(aq) → 2PbSO₄(s) + 2H₂O(l).
(c) H₂SO₄ is consumed and H₂O is produced during discharge, diluting the electrolyte and reducing its density. This is why a hydrometer reading can indicate charge level.
Common trap
Forgetting that BOTH electrodes form PbSO₄ during discharge. Students sometimes write Pb at the cathode product or PbO₂ at the anode product. The symmetry of the PbSO₄ product is the single most tested detail.
Similar NEET-style question
"A lead-acid battery rated at 24 V is used in a heavy vehicle. How many cells does it contain, and what is the product at both electrodes during discharge?"
Answer: 12 cells (24 V / 2 V); product at both electrodes is PbSO₄.
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Dry cell (Leclanché): Zn anode, MnO₂/C cathode, ~1.5 V. Lead accumulator: Pb anode, PbO₂ cathode, H₂SO₄ electrolyte, ~2 V/cell. Fuel cell: H₂/O₂ → H₂O + electrical energy.
-- NCERT Class 12 Chemistry, Ch. 2, p. 54More in Redox Reactions and Electrochemistry: 4 exam traps and mistakes · 5 formulas · 2 question patterns from its other lessons.
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