Lanthanoids

8 MCQs9-step worked example
Source: NCERT The d and f Block ElementsPYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The trap: Students predict that 5d transition metals (Hf, Ta, W) should be significantly larger than their 4d counterparts (Zr, Nb, Mo) because they sit one period lower. NEET exploits this by asking why 4d and 5d pairs show nearly identical atomic radii and similar chemistry.

What lanthanoid contraction actually is: The 14 lanthanoid elements (Ce to Lu) are filled across the 4f subshell. The 4f electrons shield nuclear charge poorly — their diffuse orbital shape means each added proton is only partially screened. Consequently, effective nuclear charge increases steadily from La (Z = 57) to Lu (Z = 71), shrinking atomic and ionic radii progressively across the series (NCERT Class 12 Chemistry Chapter 4, page 24).

The downstream consequence for 5d elements: By the time you reach Hf (Z = 72), the cumulative contraction across the 14 lanthanoids has offset the expected size increase from adding a new shell. Result: Zr (4d) and Hf (5d) have nearly identical atomic radii (~160 pm). This extends to Nb/Ta and Mo/W pairs — similar size means similar chemistry (lattice energies, bond strengths, coordination behaviour).

Key facts for NEET:

  • Cause: poor shielding by 4f electrons (NOT d or p electrons).
  • Effect: 5d elements are unexpectedly similar in size to 4d elements in the same group.
  • Common oxidation state of lanthanoids: +3 (most stable across the series); Ce also shows +4 (attains noble-gas 4f⁰ core), Eu shows +2 (achieves half-filled 4f⁷).

Watch out: Questions may frame the contraction as affecting only lanthanoids themselves. Remember the consequence extends to ALL subsequent elements — the 5d series and even post-lanthanoid p-block elements are affected.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

What is the primary cause of lanthanoid contraction?

MCQ 2Easy RecallPractice

Which is the most common and stable oxidation state exhibited by lanthanoid elements?

MCQ 3Easy RecallPractice

Ce⁴⁺ is stable because it achieves which electronic configuration?

MCQ 4Direct ApplicationPractice

Which pair of elements from the 4d and 5d series has nearly identical atomic radii due to lanthanoid contraction?

MCQ 5Direct ApplicationPractice

Eu²⁺ is unusually stable among lanthanoid divalent ions. What is the electronic configuration of Eu²⁺ that explains this stability?

MCQ 6Direct ApplicationPractice

As a consequence of lanthanoid contraction, which property of 4d and 5d transition metals in the same group becomes nearly equal?

MCQ 7Concept TrapPractice

A student claims: "Since Hf is one full period below Zr, it must have significantly larger atomic radius." What concept directly refutes this prediction?

MCQ 8CalculationPractice

Among the lanthanoid ions Sm³⁺ (4f⁵), Eu³⁺ (4f⁶), Gd³⁺ (4f⁷), and Tb³⁺ (4f⁸), which ion would be LEAST likely to deviate from the +3 oxidation state and show a +2 or +4 state?

Worked Example

Pattern: Lanthanoid contraction — effect on 4d/5d element properties (P.CHE.U11.LANTHANOID_CONTRACTION, observed in PYQ 2022, 2025).

  1. 1

    Given

    The following atomic radii are provided: - Zr (4d, Group 4): 160 pm - Hf (5d, Group 4): 159 pm - Ti (3d, Group 4): 147 pm

  2. 2

    Required

    Explain why Hf, despite being one period below Zr, has nearly the same atomic radius. Predict whether Hf and Zr would show similar or different chemical properties.

  3. 3

    Concept

    Lanthanoid contraction: across Ce (Z = 58) to Lu (Z = 71), poor shielding by 4f electrons causes a cumulative decrease in atomic radius (~12–15 pm total). This contraction offsets the expected increase from adding a new electron shell.

  4. 4

    Formula/Principle

    No quantitative formula — this is a qualitative comparison. The principle: if two elements in the same group have nearly identical atomic/ionic radii, they will exhibit similar lattice energies, bond strengths, and overall chemical behaviour.

  5. 5

    Substitution/Application

    - Expected: Hf should be ~10–15 pm larger than Zr (one extra shell, analogous to Ti→Zr increase of 13 pm). - Actual: Hf is 159 pm ≈ 160 pm (Zr). The "missing" expansion is absorbed by lanthanoid contraction across the 14 lanthanoid elements.

  6. 6

    Calculation

    Radius difference: |160 − 159| = 1 pm ≈ negligible. Compare with Ti→Zr difference: 160 − 147 = 13 pm (a full shell increase without intervening f-block).

  7. 7

    Final answer

    Lanthanoid contraction explains why Hf and Zr have nearly identical radii (difference ~1 pm vs expected ~13 pm). Consequence: Hf and Zr exhibit remarkably similar chemical properties — they form similar compounds, have similar coordination numbers, and are difficult to separate.

  8. 8

    Common trap

    Students predict Hf should be "much larger" because it's in period 6. They forget the 14-element lanthanoid contraction that intervenes between the 4d and 5d series. This trap appears as a distractor: "5d elements are always larger than 4d elements in the same group."

  9. 9

    Similar NEET-style question

    "Nb and Ta have very similar atomic radii. Which of the following best explains this observation? (A) d-orbital expansion (B) Actinoid contraction (C) Lanthanoid contraction (D) Relativistic effects" Answer: (C). The same principle applies to all 4d/5d pairs in Groups 4–7. ---

Before solving, remember these

Steady decrease in atomic/ionic size across lanthanide series due to imperfect shielding by f-electrons. Causes 4d ≈ 5d size; explains close properties of Zr/Hf, Nb/Ta, Mo/W (4d/5d pairs).

-- NCERT Class 12 Chemistry, Ch. 4, p. 24

Formulas

Spin-only magnetic moment

Magnetic moment from n unpaired electrons. 1 unpaired: 1.73 BM; 5: 5.92 BM.

SymbolQuantitySI Unit
nunpaired electrons-
mumagnetic momentBohr magneton

Valid when

  • Spin-only contribution (no orbital contribution)
  • Octahedral or tetrahedral complex

Spin-only magnetic moment for transition metal

Predicts paramagnetic moment of d-block ion. n unpaired electrons in d-orbitals.

SymbolQuantitySI Unit
nunpaired electrons-
mumagnetic momentBM

Valid when

  • Spin-only contribution
  • Octahedral or tetrahedral complex
  • First-row d-block

Common oxidation states (first-row TM)

Catalogues common stable oxidation states across first-row transition metals.

SymbolQuantitySI Unit
OSoxidation state-

Valid when

  • First-row d-block
  • Common (not exotic) compounds

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Inorganic Exception

Student assumes Mn²⁺ is the product regardless of medium. Acidic: → Mn²⁺ (5e⁻). Neutral/weakly basic: → MnO₂ (3e⁻). Strongly basic: → MnO₄²⁻ (1e⁻).

When it triggers

Question gives KMnO4 oxidation in unspecified or specific medium.

How to avoid

Always check medium. In acidic: Mn(+7) → Mn(+2). In neutral: → Mn(+4) (MnO₂). In basic: → Mn(+6) (manganate). The number of electrons (n) in Nernst calculations depends accordingly.

Past Year Questions

10 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2025

The correct order of decreasing basic strength of the given amines is:

1benzenamine > ethanamine > N-methylaniline > N-ethylethanamine
2N-methylaniline > benzenamine > ethanamine > N-ethylethanamine
3N-ethylethanamine > ethanamine > benzenamine > N-methylaniline
4N-ethylethanamine > ethanamine > N-methylaniline > benzenamine
NTA Answer: Option 4(final)
NEET 2023

Which one of the following statements is correct?

1All enzymes that utilise ATP in phosphate transfer require Ca as the cofactor
2The bone in human body is an inert and unchanging substance
3Mg plays roles in neuromuscular function and interneuronal transmission
4The daily requirement of Mg and Ca in the human body is estimated to be 0.2-0.3 g
NTA Answer: Option 4(final)
NEET 2023

Which of the following statements are INCORRECT? A. All the transition metals except scandium form MO oxides which are ionic. B. The highest oxidation number corresponding to the group number in transition metal oxides is attained in Sc O to Mn O . 2 3 2 7 C. Basic character increases from V O to V O to V O . 2 3 2 4 2 5 D. V 2 O 4 dissolves in acids to give VO3 4 –salts. E. CrO is basic but Cr O is amphoteric. 2 3 Choose the correct answer from the options given below:

1B and D only
2C and D only
3B and C only
4A and E only
NTA Answer: Option 2(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Sources

NCERT refs: Class 12 Chemistry Chapter 4, p.24

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