Magnetic properties
Paramagnetic: unpaired electrons. Magnetic moment μ = √(n(n+2)) BM (spin only), where n = unpaired e⁻. Diamagnetic: all e⁻ paired (e.g. Zn²⁺ d¹⁰).
-- NCERT Class 12 Chemistry, Ch. 4, p. 16The magnetic behaviour of transition metal ions comes down to one question: how many unpaired electrons does the ion have? Get that count wrong, and you pick the wrong magnetic moment from the spin-only formula — a common source of lost marks.
Classification. Substances with unpaired electrons are paramagnetic (attracted into a magnetic field). Substances with all electrons paired are diamagnetic (weakly repelled). Among transition metals, paramagnetism dominates because partially filled d-orbitals readily hold unpaired electrons.
The spin-only formula. NCERT Class 12 Chemistry Chapter 4 (page 16) gives:
μ = √(n(n+2)) BM
where n = number of unpaired electrons. This approximation ignores orbital angular momentum contribution — valid for first-row d-block ions where crystal field quenching suppresses orbital contribution.
Counting unpaired electrons. Write the electronic configuration of the ion (not the atom). Remove electrons from 4s first, then from 3d. For example: Fe²⁺ is [Ar] 3d⁶ — four unpaired electrons in a free ion (high-spin). Fe³⁺ is [Ar] 3d⁵ — five unpaired electrons.
Watch-out. The trap is counting unpaired electrons from the neutral atom configuration rather than the ion configuration. Always strip 4s electrons first, then count d-orbital occupancy in the ionic state. A second common error: confusing high-spin and low-spin counts without being told the ligand field strength — in NEET, assume high-spin (weak field) unless the question explicitly states otherwise.
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
Which of the following ions is diamagnetic?
The spin-only magnetic moment of Mn²⁺ (3d⁵) is:
Among Ti³⁺, V³⁺, Cr³⁺, and Mn²⁺, the ion with the highest magnetic moment is:
Cu⁺ is diamagnetic while Cu²⁺ is paramagnetic. This is because:
A transition metal ion has a magnetic moment of 3.87 BM. The number of unpaired electrons in the ion is:
Which statement correctly describes the spin-only magnetic moment formula?
Fe²⁺ has a spin-only magnetic moment of approximately:
An ion with electronic configuration [Ar] 3d³ is placed in a magnetic field. Its magnetic moment and magnetic behaviour are:
Given
Co (Z = 27): [Ar] 3d⁷ 4s². Co²⁺ removes 2 electrons (4s² first) → [Ar] 3d⁷.
Required
Spin-only magnetic moment (μ) and magnetic classification.
Concept
The spin-only formula relates the number of unpaired electrons to the observed magnetic moment. For high-spin first-row transition metal ions, count unpaired electrons in the d-subshell after removing appropriate electrons.
Formula
μ = √(n(n+2)) BM
Substitution
Co²⁺ is 3d⁷. Filling 5 d-orbitals with 7 electrons (Hund's rule, high-spin): ↑↓ ↑↓ ↑ ↑ ↑ → n = 3 unpaired electrons. μ = √(3 × (3+2)) = √(3 × 5) = √15
Calculation
μ = √15 = 3.87 BM
Final answer
μ = 3.87 BM. Since n = 3 > 0, Co²⁺ is paramagnetic. Note: The integers 3, 5, and 15 in the formula are exact counting numbers and mathematical products — they do not limit significant figures. The result 3.87 BM carries three significant figures by convention of the spin-only formula output.
Common trap
Counting unpaired electrons from the neutral atom (3d⁷ 4s²) instead of the ion (3d⁷). Here both happen to give the same d-configuration for Co²⁺, but for ions like Fe²⁺ (not Fe atom's [Ar] 3d⁶ 4s² → ion is [Ar] 3d⁶), confusing atom vs ion configurations is a frequent source of wrong n values. Always write the ion configuration explicitly.
Similar NEET-style question
Calculate the magnetic moment of Ni²⁺ and identify whether a complex [Ni(H₂O)₆]²⁺ would be attracted to or repelled by a magnetic field.
Paramagnetic: unpaired electrons. Magnetic moment μ = √(n(n+2)) BM (spin only), where n = unpaired e⁻. Diamagnetic: all e⁻ paired (e.g. Zn²⁺ d¹⁰).
-- NCERT Class 12 Chemistry, Ch. 4, p. 16Magnetic moment from n unpaired electrons. 1 unpaired: 1.73 BM; 5: 5.92 BM.
| Symbol | Quantity | SI Unit |
|---|---|---|
| n | unpaired electrons | - |
| mu | magnetic moment | Bohr magneton |
Predicts paramagnetic moment of d-block ion. n unpaired electrons in d-orbitals.
| Symbol | Quantity | SI Unit |
|---|---|---|
| n | unpaired electrons | - |
| mu | magnetic moment | BM |
Catalogues common stable oxidation states across first-row transition metals.
| Symbol | Quantity | SI Unit |
|---|---|---|
| OS | oxidation state | - |
These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.
Category: Inorganic Exception
Student assumes Mn²⁺ is the product regardless of medium. Acidic: → Mn²⁺ (5e⁻). Neutral/weakly basic: → MnO₂ (3e⁻). Strongly basic: → MnO₄²⁻ (1e⁻).
Question gives KMnO4 oxidation in unspecified or specific medium.
Always check medium. In acidic: Mn(+7) → Mn(+2). In neutral: → Mn(+4) (MnO₂). In basic: → Mn(+6) (manganate). The number of electrons (n) in Nernst calculations depends accordingly.
Root cause: concept gap
Acidic: → Mn²⁺ (5e⁻). Neutral/weakly basic: → MnO₂ (3e⁻). Strongly basic: → MnO₄²⁻ (1e⁻).
Root cause: concept gap
Lanthanoid contraction (imperfect 4f shielding) makes 5d elements similar in size to 4d. Zr/Hf, Nb/Ta, Mo/W have nearly identical chemistry.
10 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.
The correct order of decreasing basic strength of the given amines is:
The pair of lanthanoid ions which are diamagnetic is
Which one of the following statements is correct?
Gadolinium has a low value of third ionisation enthalpy because of
Tritium, a radioactive isotope of hydrogen, emits which of the following particles? (β–)
Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.
uses acidic formula in basic medium
Assumes Mn²⁺ regardless of medium
predicts large difference due to period shift
Expects 5d to be much larger than 4d
misses d0 d10 stability
Doesn't account for closed-shell stability
Test yourself on this topic with real past-paper questions:
Practice this topic →Get a structured 30-day study plan and a complete formula booklet — delivered to your inbox instantly.