Colour Magnetic Coordination

8 MCQs1 revision card9-step worked example
Source: NCERT Coordination CompoundsPYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The trap: Students default to one spin state when asked about colour or magnetic behaviour of a complex — they forget that the ligand's field strength determines whether a d-orbital configuration is high-spin or low-spin, which directly decides the number of unpaired electrons (magnetic moment) and the magnitude of Δ₀ (colour).

Colour in coordination compounds arises because the d–d transition absorbs a specific wavelength from visible light; the complementary colour is what we observe. The energy gap Δ₀ between t₂g and e_g sets determines which wavelength is absorbed. A larger Δ₀ (strong-field ligand) shifts absorption toward violet/blue → complex appears yellow/orange. A smaller Δ₀ (weak-field ligand) shifts absorption toward red → complex appears green/blue (NCERT Class 12 Chemistry Chapter 5, page 23).

Magnetic properties depend on unpaired electrons. The spin-only magnetic moment is μ = √(n(n+2)) BM. The critical question: what is n? That depends on whether the complex is high-spin or low-spin — controlled entirely by the ligand field strength relative to pairing energy P.

The spectrochemical series decides everything: I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < H₂O < NH₃ < en < CN⁻ < CO

  • Strong-field (CN⁻, CO, NH₃/en for certain metals): Δ₀ > P → electrons pair in t₂g → low-spin → fewer unpaired electrons → lower μ.
  • Weak-field (F⁻, Cl⁻, H₂O): Δ₀ < P → electrons spread across both sets → high-spin → more unpaired electrons → higher μ.

Watch-out: A d⁶ metal with CN⁻ has n = 0 (diamagnetic, low-spin), but the same d⁶ metal with H₂O has n = 4 (paramagnetic, high-spin). One ligand swap changes μ from 0 to 4.90 BM. NEET exploits this gap regularly.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

The colour of a coordination compound is due to:

MCQ 2Easy RecallPractice

Which of the following complexes is expected to be colourless?

MCQ 3Easy RecallPractice

The correct order of field strength in the spectrochemical series is:

MCQ 4Direct ApplicationPractice

[Fe(CN)₆]⁴⁻ contains Fe²⁺ (d⁶). Given that CN⁻ is a strong-field ligand, the number of unpaired electrons and magnetic moment are:

MCQ 5Direct ApplicationPractice

[CoF₆]³⁻ contains Co³⁺ (d⁶). F⁻ is a weak-field ligand. The magnetic moment of this complex is approximately:

MCQ 6Direct ApplicationPractice

Two octahedral complexes of Cr³⁺ (d³) are: [Cr(NH₃)₆]³⁺ and [Cr(H₂O)₆]³⁺. Which statement about their colours is correct?

MCQ 7CalculationPractice

[Mn(CN)₆]⁴⁻ and [Mn(H₂O)₆]²⁺ both contain Mn²⁺ (d⁵). Calculate the difference in their magnetic moments (μ_high − μ_low):

MCQ 8CalculationPractice

An octahedral complex of Fe³⁺ (d⁵) with a strong-field ligand shows μ = 1.73 BM. If the ligand is replaced by a weak-field ligand, the new magnetic moment and the change in number of unpaired electrons are:

Quick recall before you leave

Worked Example

Pattern: P.CHE.U12.CRYSTAL_FIELD_HIGH_LOW_SPIN (observed NEET 2021, 2024)

  1. 1

    Given

    - Complex: [Co(NH₃)₆]³⁺ - Metal ion: Co³⁺ - d-electron count: d⁶ (Co is atomic number 27; Co³⁺ = 27 − 3 = 24 electrons; [Ar]3d⁶) - Ligand: NH₃

  2. 2

    Required

    Determine (a) whether the complex is high-spin or low-spin, (b) the number of unpaired electrons, and (c) the magnetic moment.

  3. 3

    Concept

    The spectrochemical series classifies NH₃ as a strong-field ligand. For octahedral complexes, if Δ₀ > P (pairing energy), electrons preferentially pair in t₂g before occupying e_g → low-spin.

  4. 4

    Formula

    μ = √(n(n+2)) BM

  5. 5

    Substitution

    NH₃ is strong-field → Δ₀ > P → low-spin d⁶ configuration: - t₂g⁶ e_g⁰ → all 6 electrons paired in t₂g - n = 0 μ = √(0(0+2)) = √0 = 0 BM

  6. 6

    Calculation

    μ = 0 BM. The complex is diamagnetic.

  7. 7

    Final answer

    [Co(NH₃)₆]³⁺ is a **low-spin, diamagnetic** complex with μ = 0 BM. **Note on exact values:** The integers 6 (electron count) and 0 (unpaired count) are exact counting numbers and do not limit significant figures in the magnetic moment calculation.

  8. 8

    Common trap

    Defaulting to high-spin: if you forgot NH₃ is strong-field and assumed high-spin d⁶ (t₂g⁴ e_g²), you would get n = 4, μ = 4.90 BM — the exact wrong answer NTA places as a distractor.

  9. 9

    Similar NEET-style question

    "Calculate the magnetic moment of [Fe(H₂O)₆]²⁺. Given: Fe²⁺ is d⁶, H₂O is a weak-field ligand." (Answer: high-spin, n = 4, μ = √(4×6) = √24 ≈ 4.90 BM — paramagnetic.) ---

Before solving, remember these

Ligands ordered by increasing Δ: I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < H₂O < NH₃ < en < CN⁻ < CO. Predicts colour and magnetic properties of complexes.

-- NCERT Class 12 Chemistry, Ch. 5, p. 23

Formulas

Crystal field splitting (octahedral vs tetrahedral)

Tetrahedral splitting is smaller than octahedral due to fewer/farther ligands.

SymbolQuantitySI Unit
Delta_ooctahedral splittingJ or eV
Delta_ttetrahedral splittingJ or eV

Valid when

  • Same metal and same ligand
  • Mostly high-spin tetrahedral due to small Δ_t

Magnetic moment of coordination complex

Same spin-only formula but n depends on high-spin/low-spin from CFT.

SymbolQuantitySI Unit
nunpaired electrons-

Valid when

  • High vs low spin determined by Δ_o vs P
  • Octahedral (or tetrahedral with Δ_t)

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Similar Terms

Student defaults to one spin state. Strong-field ligand (CN⁻, CO, NH₃ for some) → low-spin (Δ > P, electrons pair). Weak-field (F⁻, H₂O, Cl⁻) → high-spin.

When it triggers

Coordination compound with given ligand asking for magnetic moment, color, or spin state.

How to avoid

Memorise spectrochemical series: I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < H₂O < NH₃ < en < CN⁻ < CO. NH₃, CN⁻, CO usually strong-field. F⁻, H₂O, Cl⁻ usually weak-field.

Past Year Questions

11 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2025

Given below are two statements : Statement I : Ferromagnetism is considered as an extreme form of paramagnetism. Statement II : The number of unpaired electrons in a Cr2+ ion (Z = 24) is the same as that of a Nd3+ ion (Z = 60). In the light of the above statements, choose the correct answer from the options given below :

1Statement I is false but Statement II is true
2Both Statement I and Statement II are true
3Both Statement I and Statement II are false
4Statement I is true but Statement II is false
NTA Answer: Option 4(final)
NEET 2024Revised key

Given below are two statements : Statement I: Both [Co(NH ) ]3+ and [CoF ]3– complexes are octahedral but differ in their magnetic behaviour. 3 6 6 Statement II: [Co(NH ) ]3+ is diamagnetic whereas [CoF ]3– is paramagnetic. 3 6 6 In the light of the above statements, choose the correct answer from the options given below:

1Both Statement I and Statement II are true
2Both Statement I and Statement II are false
3Statement I is true but Statement II is false
4Statement I is false but Statement II is true
NTA Answer: Option 1(revised_final)
NEET 2022

Identify the incorrect statement from the following.

1The shapes of d xy , d yz and d zx orbitals are similar to each other; and d x2−y2 and d z2 are similar to each other.
2All the five 5d orbitals are different in size when compared to the respective 4d orbitals.
3All the five 4d orbitals have shapes similar to the respective 3d orbitals.
4In an atom, all the five 3d orbitals are equal in energy in free state.
NTA Answer: Option 1(final)
NEET 2021

Ethylene diaminetetraacetate (EDTA) ion is :

1Tridentate ligand with three "N" donor atoms
2Hexadentate ligand with four "O" and two "N" donor atoms
3Unidentate ligand
4Bidentate ligand with two "N" donor atoms
NTA Answer: Option 2(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Sources

NCERT refs: Class 12 Chemistry Chapter 5, p.23

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