Ligands Coordination Number

8 MCQs9-step worked example
Source: NCERT Coordination CompoundsPYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The trap that costs marks here: confusing the coordination number with the total number of ions or atoms attached to a metal. Counter-ions sitting outside the coordination sphere are not ligands — counting them inflates the coordination number and leads straight to a wrong answer.

What a ligand actually is. A ligand is a neutral molecule or ion that donates at least one lone pair of electrons to a central metal atom or ion, forming a coordinate bond (NCERT Class 12 Chemistry Chapter 5, page 4). The metal is the Lewis acid; the ligand is the Lewis base. Only species directly bonded to the metal inside the coordination sphere count.

Denticity — how many donor atoms one ligand has. A monodentate ligand (Cl⁻, NH₃, H₂O) donates through one atom. A bidentate ligand (ethylenediamine, oxalate) donates through two atoms. Polydentate ligands like EDTA⁴⁻ donate through six atoms. Denticity matters because the coordination number equals the total number of donor atoms, not the total number of ligand molecules.

Coordination number. It is the number of ligand donor atoms directly bonded to the central metal ion. For [Co(NH₃)₆]³⁺, six monodentate NH₃ molecules give coordination number 6. For [Co(en)₃]³⁺, three bidentate ethylenediamine ligands still give coordination number 6 (3 ligands × 2 donor atoms each). The counter-ions (Cl⁻ outside the bracket in [Co(NH₃)₆]Cl₃) do not count.

Primary vs secondary valency (Werner's theory). Primary valency is the oxidation state — satisfied by counter-ions and ionizable. Secondary valency is the coordination number — satisfied by ligands and fixed for a given complex. NEET questions frequently ask you to distinguish these: a common distractor treats all attached species as ligands, conflating primary and secondary valencies.

Watch-out: When a formula like CoCl₃·6NH₃ is written without brackets, identify which species are inside the coordination sphere (ligands) and which are ionizable counter-ions before assigning the coordination number.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Which of the following is a bidentate ligand?

MCQ 2Easy RecallPractice

The coordination number of the central metal ion in [PtCl₆]²⁻ is:

MCQ 3Easy RecallPractice

In Werner's theory, the primary valency of the metal in [Co(NH₃)₆]Cl₃ is:

MCQ 4Direct ApplicationPractice

The coordination number of Co³⁺ in [Co(en)₂Cl₂]⁺ is:

MCQ 5Direct ApplicationPractice

In CoCl₃·4NH₃, the number of ionizable chloride ions (counter-ions outside the coordination sphere) is 1. What is the coordination number of Co³⁺?

MCQ 6Direct ApplicationPractice

EDTA⁴⁻ is a hexadentate ligand. What is the coordination number of Fe³⁺ in [Fe(EDTA)]⁻?

MCQ 7Concept TrapPractice

The compound CoCl₃·6NH₃ gives 3 moles of AgCl on treatment with excess AgNO₃. Which of the following correctly represents the complex?

MCQ 8CalculationPractice

A complex of Cr³⁺ with formula CrCl₃·5NH₃ produces 2 moles of AgCl per mole of complex with excess AgNO₃. What is the coordination number of Cr³⁺ in this complex?

Worked Example

  1. 1

    Given

    A compound has the empirical formula PtCl₄·2NH₃. It is non-electrolyte (zero moles of AgCl with excess AgNO₃, no conductance in solution).

  2. 2

    Required

    Determine: (a) the coordination number of Pt, (b) the formula of the complex, (c) the primary and secondary valencies.

  3. 3

    Concept

    Non-electrolyte means zero ionizable ions — all species are inside the coordination sphere. Primary valency (oxidation state) is satisfied within the complex itself. Secondary valency equals coordination number (NCERT Class 12 Chemistry Chapter 5, page 4).

  4. 4

    Formula / Rule

    Coordination number = total number of ligand donor atoms bonded to the metal. Primary valency of Pt = charge balanced by ligands within the sphere.

  5. 5

    Substitution

    Zero ionizable Cl⁻ → all 4 Cl⁻ are coordinated ligands. 2 NH₃ are also coordinated ligands. All are monodentate.

  6. 6

    Calculation

    Coordination number = 4 (from Cl⁻) + 2 (from NH₃) = **6**. Complex formula: [PtCl₄(NH₃)₂] (no counter-ions outside the bracket). Oxidation state of Pt: let x + 4(−1) + 2(0) = 0, so x = +4. Primary valency = +4 (satisfied by the 4 Cl⁻ within the sphere). Secondary valency = 6. Note: The integer counts (4 Cl⁻, 2 NH₃) are exact counting numbers and do not limit significant figures.

  7. 7

    Final answer

    Coordination number of Pt⁴⁺ = **6**. Formula: [PtCl₄(NH₃)₂]. Primary valency = 4, secondary valency = 6.

  8. 8

    Common trap

    Assuming that because there are 4 Cl⁻, some must be counter-ions — this leads to writing [PtCl₂(NH₃)₂]Cl₂ or similar. The conductance data (non-electrolyte) rules this out: zero ionizable ions means all chlorides are coordinated.

  9. 9

    Similar NEET-style question

    A compound CrCl₃·3NH₃ does not precipitate AgCl with AgNO₃ and is a non-electrolyte. Write the structural formula and find the coordination number of Cr. *(Answer: [CrCl₃(NH₃)₃], coordination number = 6, primary valency = 3, secondary valency = 6.)* ---

Before solving, remember these

Ligand: ion or neutral molecule donating electron pair to metal (Lewis base). Monodentate (1 site, e.g. NH₃, Cl⁻). Bidentate (2 sites, e.g. en, ox²⁻). Polydentate (chelate, e.g. EDTA⁴⁻ has 6 sites). Coordination number = number of donor atoms attached.

-- NCERT Class 12 Chemistry, Ch. 5, p. 4

Formulas

Crystal field splitting (octahedral vs tetrahedral)

Tetrahedral splitting is smaller than octahedral due to fewer/farther ligands.

SymbolQuantitySI Unit
Delta_ooctahedral splittingJ or eV
Delta_ttetrahedral splittingJ or eV

Valid when

  • Same metal and same ligand
  • Mostly high-spin tetrahedral due to small Δ_t

Magnetic moment of coordination complex

Same spin-only formula but n depends on high-spin/low-spin from CFT.

SymbolQuantitySI Unit
nunpaired electrons-

Valid when

  • High vs low spin determined by Δ_o vs P
  • Octahedral (or tetrahedral with Δ_t)

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Similar Terms

Student defaults to one spin state. Strong-field ligand (CN⁻, CO, NH₃ for some) → low-spin (Δ > P, electrons pair). Weak-field (F⁻, H₂O, Cl⁻) → high-spin.

When it triggers

Coordination compound with given ligand asking for magnetic moment, color, or spin state.

How to avoid

Memorise spectrochemical series: I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < H₂O < NH₃ < en < CN⁻ < CO. NH₃, CN⁻, CO usually strong-field. F⁻, H₂O, Cl⁻ usually weak-field.

Past Year Questions

11 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2025

Given below are two statements : Statement I : Ferromagnetism is considered as an extreme form of paramagnetism. Statement II : The number of unpaired electrons in a Cr2+ ion (Z = 24) is the same as that of a Nd3+ ion (Z = 60). In the light of the above statements, choose the correct answer from the options given below :

1Statement I is false but Statement II is true
2Both Statement I and Statement II are true
3Both Statement I and Statement II are false
4Statement I is true but Statement II is false
NTA Answer: Option 4(final)
NEET 2024Revised key

Given below are two statements : Statement I: Both [Co(NH ) ]3+ and [CoF ]3– complexes are octahedral but differ in their magnetic behaviour. 3 6 6 Statement II: [Co(NH ) ]3+ is diamagnetic whereas [CoF ]3– is paramagnetic. 3 6 6 In the light of the above statements, choose the correct answer from the options given below:

1Both Statement I and Statement II are true
2Both Statement I and Statement II are false
3Statement I is true but Statement II is false
4Statement I is false but Statement II is true
NTA Answer: Option 1(revised_final)
NEET 2022

Identify the incorrect statement from the following.

1The shapes of d xy , d yz and d zx orbitals are similar to each other; and d x2−y2 and d z2 are similar to each other.
2All the five 5d orbitals are different in size when compared to the respective 4d orbitals.
3All the five 4d orbitals have shapes similar to the respective 3d orbitals.
4In an atom, all the five 3d orbitals are equal in energy in free state.
NTA Answer: Option 1(final)
NEET 2021

Ethylene diaminetetraacetate (EDTA) ion is :

1Tridentate ligand with three "N" donor atoms
2Hexadentate ligand with four "O" and two "N" donor atoms
3Unidentate ligand
4Bidentate ligand with two "N" donor atoms
NTA Answer: Option 2(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Sources

NCERT refs: Class 12 Chemistry Chapter 5, p.4

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