Amines Nomenclature

8 MCQs9-step worked example
Source: NCERT Polymers and Chemistry in Everyday LifePYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The trap that costs marks here: confusing Hofmann elimination product selectivity with Saytzeff (Zaitsev) selectivity. When you see a quaternary ammonium hydroxide undergoing elimination, the product is the least substituted alkene — the opposite of what you'd pick for an alkyl halide with a base.

Nomenclature and classification of amines

Amines are derivatives of ammonia where one, two, or three hydrogen atoms are replaced by alkyl or aryl groups (NCERT Class 12 Chemistry Chapter 13, page 2).

Classification:

  • Primary (1°): One H replaced — R–NH₂ (e.g., methylamine, CH₃NH₂)
  • Secondary (2°): Two H replaced — R₂NH (e.g., dimethylamine, (CH₃)₂NH)
  • Tertiary (3°): Three H replaced — R₃N (e.g., trimethylamine, (CH₃)₃N)

IUPAC naming rules:

  1. Identify the longest chain containing –NH₂ as the parent.
  2. Replace terminal "-e" with "-amine" (methanamine, ethanamine, propan-1-amine).
  3. For secondary/tertiary amines, the largest alkyl group is the parent chain; smaller groups carry the prefix "N-" (e.g., N-methylethanamine, N,N-dimethylmethanamine).
  4. When –NH₂ is a substituent on a ring or higher-priority chain, use "amino-" prefix (e.g., 3-aminopentane).

Common name system: alkyl group names + "amine" as one word (methylamine, diethylamine, triphenylamine).

Hofmann elimination — the nomenclature-adjacent reaction trap: Quaternary ammonium hydroxide (R₄N⁺OH⁻) heated → eliminates to form the least substituted alkene (Hofmann product). This is anti-Saytzeff. The bulky leaving group (NR₃) and base attack the less hindered β-hydrogen. Confusing this with standard E2 of alkyl halides (Saytzeff → most substituted alkene) is the high-frequency trap for this topic.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Which of the following is a tertiary amine?

MCQ 2Easy RecallPractice

The IUPAC name of (CH₃)₂CHNH₂ is:

MCQ 3Easy RecallPractice

The IUPAC name of CH₃–NH–C₂H₅ is:

MCQ 4Direct ApplicationPractice

Hofmann elimination of N,N,N-trimethylbutan-2-aminium hydroxide gives predominantly:

MCQ 5Direct ApplicationPractice

Which compound is named N,N-diethylethanamine?

MCQ 6Direct ApplicationPractice

An amine has the structure: C₆H₅–NH–CH₃. Its correct IUPAC name is:

MCQ 7Concept TrapPractice

In Hofmann elimination, why does the least substituted alkene form preferentially?

MCQ 8CalculationPractice

Consider the quaternary salt: (CH₃)₃N⁺–CH₂–CH(CH₃)₂ OH⁻. On heating, which alkene is the major Hofmann elimination product?

Worked Example

  1. 1

    Given

    - Substrate: tetraethylammonium hydroxide, (C₂H₅)₄N⁺ OH⁻ - Reaction: strong heating (pyrolysis)

  2. 2

    Required

    Identify the major elimination product.

  3. 3

    Concept

    Hofmann elimination: quaternary ammonium hydroxide → least substituted alkene + tertiary amine + water. Anti-Saytzeff selectivity due to steric bulk of the –NR₃ leaving group.

  4. 4

    Formula / Rule

    Hofmann rule: β-elimination from quaternary ammonium salts preferentially removes the β-H from the least substituted carbon → terminal alkene.

  5. 5

    Substitution / Analysis

    All four groups on nitrogen are identical (ethyl). Each ethyl group has β-hydrogens on the terminal CH₃. Elimination from any ethyl group gives the same product: ethene (CH₂=CH₂).

  6. 6

    Calculation

    (C₂H₅)₄N⁺ OH⁻ → CH₂=CH₂ + (C₂H₅)₃N + H₂O Since all groups are equivalent, there is no substitution-selectivity question — ethene is the sole alkene product.

  7. 7

    Final answer

    **Major product: ethene (CH₂=CH₂)**, with triethylamine as the amine by-product.

  8. 8

    Common trap

    Picking a higher alkene (butene) by imagining two ethyl groups combine. They don't — Hofmann elimination breaks one C–N bond and removes one β-H from the same alkyl chain. Each elimination event produces a two-carbon alkene from one ethyl group.

  9. 9

    Similar NEET-style question

    "Exhaustive methylation of propan-1-amine followed by treatment with Ag₂O and heating gives which alkene as the major product?" (Answer: propene — the only alkene possible from the propyl chain, which is also the least substituted terminal alkene consistent with Hofmann.) ---

Before solving, remember these

Primary (1°): R-NH₂. Secondary (2°): R₂NH. Tertiary (3°): R₃N. Aliphatic vs aromatic. Quaternary ammonium salt: R₄N⁺X⁻.

-- NCERT, p. 2

Formulas

pKb of common amines (aqueous)

Aqueous basicity order: 2° ≈ 1° > 3° > NH3. Aromatic amines much weaker due to resonance delocalisation of lone pair.

SymbolQuantitySI Unit
pKb-log Kb-

Valid when

  • Aqueous solution; gas-phase order is 3°>2°>1°

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Inorganic Exception

Student treats aniline as stronger base than methylamine. Aniline weaker due to lone-pair delocalization into ring.

When it triggers

Basicity ordering across aromatic and aliphatic amines.

How to avoid

Aliphatic amines (CH3NH2) > NH3 > aromatic amines (C6H5NH2). Aniline lone pair delocalised into ring → less available for protonation.

Category: Organic Reaction Conditions

Quaternary ammonium hydroxide (Hofmann) elimination favours LESS substituted alkene (anti-Saytzeff). Halide elimination (E2) follows Saytzeff (more substituted).

When it triggers

E2 elimination question with quaternary ammonium hydroxide vs alkyl halide.

How to avoid

Hofmann: bulky leaving group + base → least substituted alkene (Hofmann product). Saytzeff: alkyl halide + base → most substituted alkene (Zaitsev product).

Past Year Questions

11 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2023

The correct order of energies of molecular orbitals of N molecule, is 2

11s < *1s < 2s < *2s < 2p < (2p = 2p ) < (*2p = *2p ) < *2p z x y x y z
21s < *1s < 2s < *2s < 2p < *2p < (2p = 2p ) < (*2p = *2p ) z z x y x y
31s < *1s < 2s < *2s < (2p = 2p ) < (*2p = *2p ) < 2p < *2p x y x y z z
41s < *1s < 2s < *2s < (2p = 2p ) < 2p < (*2p = *2p ) < *2p x y z x y z
NTA Answer: Option 4(final)
NEET 2022

Match List-I with List-II. List – I List – II (Products formed) (Reaction of carbonyl compound with) (a) Cyanohydrin (i) NH OH 2 (b) Acetal (ii) RNH 2 (c) Schiff's base (iii) alcohol (d) Oxime (iv) HCN Choose the correct answer from the options given below

1(a) – (iv), (b) – (iii), (c) – (ii), (d) – (i)
2(a) – (iii), (b) – (iv), (c) – (ii), (d) – (i)
3(a) – (ii), (b) – (iii), (c) – (iv), (d) – (i)
4(a) – (i), (b) – (iii), (c) – (ii), (d) – (iv)
NTA Answer: Option 1(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Sources

NCERT refs: Class 12 Chemistry Chapter 13, p.2

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