Diazonium salts
Aryl diazonium chloride: ArN₂⁺Cl⁻. Prepared by diazotisation: ArNH₂ + HCl + NaNO₂ at 0-5°C → ArN₂⁺Cl⁻. Highly versatile in synthesis.
-- NCERT, p. 16The diazonium salt question on NEET is a reagent-recall trap. You see a benzenediazonium chloride (C₆H₅N₂⁺Cl⁻) reacting with a copper salt or water, and the answer hinges on whether you remember which copper reagent gives which product. Confuse Sandmeyer with Gattermann and you lose four marks — the wrong option is designed to look right.
What is a diazonium salt? When a primary aromatic amine (like aniline) reacts with nitrous acid (NaNO₂ + HCl) at 273–278 K, the amino group is replaced by the diazonium group (–N₂⁺). The product, benzenediazonium chloride, is the gateway to a wide range of aromatic substitutions that are otherwise difficult or impossible by direct methods (NCERT Class 12 Chemistry Chapter 9, page 16).
Why is this synthetically important? The –N₂⁺ group can be replaced by –Cl, –Br, –CN, –I, –OH, –H, –F, and –NO₂ through specific named reactions. This makes diazonium chemistry the single most versatile route to substituted benzene rings in NCERT organic chemistry (NCERT Class 12 Chemistry Chapter 9, page 18).
The high-frequency trap — Sandmeyer vs. Gattermann reagent confusion. Both reactions replace –N₂⁺ with a halide, but the reagents differ:
Other key conversions: hydrolysis with warm water gives ArOH (phenol). Reaction with HBF₄ followed by heating gives ArF (Balz–Schiemann). Reaction with H₃PO₂ gives ArH (deamination). Azo coupling with phenol or aniline in alkaline medium gives azo dyes.
Watch out: NEET distractors routinely swap the Sandmeyer reagent (CuX) with the Gattermann reagent (Cu + HX). Anchor the distinction: Sandmeyer = cuprous salt; Gattermann = copper powder + acid.
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
Benzenediazonium chloride is obtained by treating aniline with NaNO₂ and HCl at 273–278 K. This reaction is called:
Which of the following is the correct reagent and product for the Sandmeyer reaction starting from benzenediazonium chloride?
Which reagent is used in the Gattermann reaction to convert benzenediazonium chloride to chlorobenzene?
Benzenediazonium chloride on treatment with CuCN gives product X. What is X?
Benzenediazonium chloride reacts with warm water to form:
Which of the following reactions of benzenediazonium chloride follows the Balz–Schiemann pathway?
Benzenediazonium chloride couples with phenol in alkaline medium. The site of coupling on phenol is preferentially at the:
A student needs to convert aniline to iodobenzene. The correct sequence is: (i) NaNO₂ + HCl at 273–278 K (ii) Reagent X Identify Reagent X.
Given
- Starting material: Aniline (C₆H₅NH₂) - Reagent 1: NaNO₂ + HCl, 273–278 K - Reagent 2: CuBr
Required
Final organic product and reaction name.
Concept
Primary aromatic amines undergo diazotisation with NaNO₂ + HCl at low temperature to form diazonium salts. The diazonium group can then be replaced by various nucleophiles. Cuprous salts (CuX) drive the Sandmeyer reaction.
Formula / Reaction scheme
- Step 1: C₆H₅NH₂ + NaNO₂ + 2HCl → C₆H₅N₂⁺Cl⁻ + NaCl + 2H₂O (at 273–278 K) - Step 2: C₆H₅N₂⁺Cl⁻ + CuBr → C₆H₅Br + N₂ + CuCl
Substitution
Aniline → benzenediazonium chloride → bromobenzene. The cuprous bromide replaces –N₂⁺ with –Br.
Calculation
No numerical calculation. This is a product-identification problem. The key reasoning step is recognising CuBr as a Sandmeyer reagent (cuprous salt) rather than Gattermann (which would require Cu powder + HBr).
Final answer
The product is **bromobenzene (C₆H₅Br)**. The second step is the **Sandmeyer reaction**.
Common trap
Students confuse the Sandmeyer reagent (CuBr) with the Gattermann reagent (Cu + HBr). Both give bromobenzene, but the question asks you to identify the reaction by the reagent. If the reagent is a cuprous salt → Sandmeyer. If the reagent is copper powder + hydrogen halide → Gattermann. Picking "Gattermann" when CuBr is given loses you 4 marks.
Similar NEET-style question
"Aniline is diazotised and then treated with CuCN. Name the reaction and the product." (Answer: Sandmeyer reaction; product = cyanobenzene / benzonitrile.) ---
Aryl diazonium chloride: ArN₂⁺Cl⁻. Prepared by diazotisation: ArNH₂ + HCl + NaNO₂ at 0-5°C → ArN₂⁺Cl⁻. Highly versatile in synthesis.
-- NCERT, p. 16Sandmeyer: ArN₂⁺Cl⁻ + Cu/HX → ArX (X = Cl, Br, CN). Gattermann (Cu powder), Hofmann (KI for ArI). Hydrolysis: ArN₂⁺ + H₂O → ArOH. Coupling with phenols/anilines → azo dyes (orange/red).
-- NCERT, p. 18Aqueous basicity order: 2° ≈ 1° > 3° > NH3. Aromatic amines much weaker due to resonance delocalisation of lone pair.
| Symbol | Quantity | SI Unit |
|---|---|---|
| pKb | -log Kb | - |
These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.
Category: Inorganic Exception
Student treats aniline as stronger base than methylamine. Aniline weaker due to lone-pair delocalization into ring.
Basicity ordering across aromatic and aliphatic amines.
Aliphatic amines (CH3NH2) > NH3 > aromatic amines (C6H5NH2). Aniline lone pair delocalised into ring → less available for protonation.
Category: Organic Reaction Conditions
Quaternary ammonium hydroxide (Hofmann) elimination favours LESS substituted alkene (anti-Saytzeff). Halide elimination (E2) follows Saytzeff (more substituted).
E2 elimination question with quaternary ammonium hydroxide vs alkyl halide.
Hofmann: bulky leaving group + base → least substituted alkene (Hofmann product). Saytzeff: alkyl halide + base → most substituted alkene (Zaitsev product).
Root cause: concept gap
Gas phase: 3° > 2° > 1° > NH₃. Aqueous: 2° > 1° > 3° > NH₃ (steric + solvation effects).
Root cause: concept gap
Aniline's lone pair delocalised into ring → less basic. Order: aliphatic (CH3NH2) > NH3 > aromatic (PhNH2).
Root cause: concept gap
Sandmeyer: ArN₂⁺ + CuCl/CuBr/CuCN → ArCl/ArBr/ArCN. Gattermann: Cu powder + HX. Hydrolysis: H₂O → ArOH.
Root cause: concept gap
Hofmann (quaternary R₄N⁺ + OH⁻): least substituted alkene. Saytzeff (alkyl halide + base): most substituted.
11 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.
The highest number of helium atoms is in
The correct order of energies of molecular orbitals of N molecule, is 2
Which of the following reactions will NOT give primary amine as the product?
Which of the following sequence of reactions is suitable to synthesize chlorobenzene?
Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.
uses gas phase order in aqueous
Doesn't account for solvation reversal
confuses sandmeyer gattermann
Mixes up Cu reagents
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