Carbohydrates Classification

8 MCQs1 revision card9-step worked example
Source: NCERT Unit 19PYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The trap that catches repeaters on carbohydrate classification: confusing the basis of classification. You know glucose and fructose share the molecular formula C₆H₁₂O₆ — but one is an aldohexose and the other a ketohexose. NEET distractors exploit exactly this overlap.

What carbohydrates are. NCERT Class 12 Chemistry Chapter 14 (Biomolecules) defines carbohydrates as polyhydroxy aldehydes or ketones, or compounds that yield these on hydrolysis. The general formula for monosaccharides is Cₙ(H₂O)ₙ.

Classification hierarchy:

  1. By hydrolysis products:

    • Monosaccharides — cannot be hydrolysed further (glucose, fructose, ribose)
    • Oligosaccharides — yield 2–10 monosaccharide units (sucrose → glucose + fructose; maltose → glucose + glucose; lactose → glucose + galactose)
    • Polysaccharides — yield many monosaccharide units (starch, cellulose, glycogen)
  2. By carbonyl group:

    • Aldoses — aldehyde at C-1 (glucose, galactose, ribose)
    • Ketoses — ketone at C-2 (fructose, ribulose)
  3. By carbon count:

    • Trioses (n=3), tetroses (n=4), pentoses (n=5: ribose, deoxyribose), hexoses (n=6: glucose, fructose, galactose)

Reducing vs non-reducing sugars: A sugar is reducing if it has a free anomeric carbon (hemiacetal/hemiketal) that can open to expose the carbonyl. All monosaccharides are reducing. Sucrose is non-reducing (both anomeric carbons are locked in the glycosidic bond). Maltose and lactose are reducing (one free anomeric carbon remains).

Watch-out for NEET: When a stem says "a ketohexose that is laevorotatory," the answer is fructose — but the distractor will offer glucose (an aldohexose) because both are C₆H₁₂O₆. Classify by functional group first, carbon count second.

Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Which of the following is a non-reducing sugar?

MCQ 2Easy RecallPractice

Fructose is classified as a:

MCQ 3Easy RecallPractice

Hydrolysis of sucrose yields:

MCQ 4Direct ApplicationPractice

A monosaccharide has the molecular formula C₅H₁₀O₅. It contains an aldehyde group. This sugar is best classified as:

MCQ 5Direct ApplicationPractice

Which of the following disaccharides will give a positive Tollens' test?

MCQ 6Direct ApplicationPractice

Cellulose and starch are both polysaccharides of glucose. The key structural difference is:

MCQ 7Concept TrapPractice

Glucose and fructose have the same molecular formula (C₆H₁₂O₆) but differ in their functional group position. They are best described as:

MCQ 8CalculationPractice

A polysaccharide on complete hydrolysis yields only D-glucose. A sample is found to dissolve in hot water, giving a blue colour with iodine. The polysaccharide and its structural component are:

Quick recall before you leave

Worked Example

  1. 1

    Given

    - Sugar: Ribose - Need to determine: carbon-count class, functional group type, molecular formula

  2. 2

    Required

    Complete classification of ribose by (a) carbon number, (b) carbonyl type, and (c) molecular formula using Cₙ(H₂O)ₙ.

  3. 3

    Concept

    Monosaccharide classification: first identify the number of carbons (triose/tetrose/pentose/hexose), then identify the functional group (aldehyde → aldose; ketone → ketose). Apply the general formula Cₙ(H₂O)ₙ.

  4. 4

    Formula

    Cₙ(H₂O)ₙ with n = number of carbons

  5. 5

    Substitution

    Ribose has 5 carbons → n = 5 C₅(H₂O)₅ = C₅H₁₀O₅

  6. 6

    Calculation

    Molecular formula: C₅H₁₀O₅ Ribose has an aldehyde group at C-1 → aldose Five carbons → pentose Note: n = 5 is a counting integer (exact); it does not affect significant-figure considerations.

  7. 7

    Final answer

    Ribose is an **aldopentose** with molecular formula **C₅H₁₀O₅**.

  8. 8

    Common trap

    Confusing ribose (aldopentose, C₅H₁₀O₅) with deoxyribose (also a pentose but with formula C₅H₁₀O₄ — one fewer oxygen). The prefix "deoxy" means one –OH is replaced by –H. NEET distractors may offer C₅H₁₀O₄ for ribose.

  9. 9

    Similar NEET-style question

    "Ribulose is a monosaccharide with 5 carbons and a ketone group. Classify it and write its molecular formula." (Answer: ketopentose, C₅H₁₀O₅.)

Before solving, remember these

Monosaccharides (simplest): glucose, fructose, galactose. Disaccharides: sucrose (glucose+fructose), lactose (glucose+galactose), maltose (2×glucose). Polysaccharides: starch, cellulose, glycogen.

-- NCERT, p. 2

Formulas

DNA hydrogen bonds per base pair

Used to compute total H-bonds in a duplex of given GC%/AT% composition.

SymbolQuantitySI Unit
%GCGC content-

Valid when

  • Watson–Crick double helix

General formula of monosaccharides

Empirical formula of simple monosaccharides; glucose/fructose are C6H12O6.

SymbolQuantitySI Unit
ncarbon count-

Valid when

  • Open-chain or cyclic forms of aldoses/ketoses

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Similar Terms

Student writes A=U for DNA or A=T for RNA. DNA: A=T, G≡C. RNA: A=U (no T), G≡C.

When it triggers

Question on base pairing or sugar identity.

How to avoid

DNA: deoxyribose, A-T-G-C bases. RNA: ribose, A-U-G-C bases (uracil instead of thymine). H-bond pairs: A=T (DNA) or A=U (RNA), G≡C (3 H-bonds, both).

Category: Similar Terms

Student claims denaturation breaks peptide bonds. Denaturation only breaks H-bonds, ionic, hydrophobic interactions; primary structure (peptide bonds) intact.

When it triggers

Question about protein denaturation effects.

How to avoid

Denaturation: heat/pH/organic solvents disrupt secondary, tertiary, quaternary structure. Primary structure (covalent peptide bonds) requires hydrolysis to break.

Past Year Questions

6 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2025

Given below are two statements : Statement-I : Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273 – 278 K. It decomposes easily in the dry state. Statement-II : Insertion of iodine into the benzene ring is difficult and hence iodobenzene is prepared through the reaction of benzenediazonium salt with KI. In the light of the above statements, choose the most appropriate answer from the options given below :

1Statement I is incorrect but Statement II is correct
2Both Statement I and Statement II are correct
3Both Statement I and Statement II are incorrect
4Statement I is correct but Statement II is incorrect
NTA Answer: Option 2(final)
NEET 2023

Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R : Assertion A : A reaction can have zero activation energy. Reasons R : The minimum extra amount of energy absorbed by reactant molecules so that their energy becomes equal to threshold value, is called activation energy. In the light of the above statements, choose the correct answer from the options given below :

1Both A and R are true and R is NOT the correct explanation of A
2A is true but R is false
3A is false but R is true
4Both A and R are true and R is the correct explanation of A
NTA Answer: Option 3(final)
NEET 2022

The incorrect statement regarding enzymes is

1Enzymes are very specific for a particular reaction and substrate.
2Enzymes are biocatalysts.
3Like chemical catalysts enzymes reduce the activation energy of bio processes.
4Enzymes are polysaccharides.
NTA Answer: Option 4(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

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