Detection Functional Groups

8 MCQs9-step worked example
Source: NCERT Unit 20PYQ coverage: NEET 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

Functional group detection in organic qualitative analysis is a high-frequency practical chemistry topic. NEET questions test whether you can match a specific chemical test (reagent + observable change) to the correct functional group — and the trap is confusing tests that produce similar observations for different groups.

Core principle: Each functional group reacts with a characteristic reagent to give a unique observable — a colour change, precipitate, gas evolution, or effervescence. Your job is to memorise the reagent–observation–inference triplet, not just the reagent name.

Key functional-group tests (NCERT Class 11 Chemistry, Chapter 12, practical section):

  • Unsaturation (C=C): Bromine water decolourises (addition across the double bond). Baeyer's test — dilute alkaline KMnO₄ decolourises (syn-hydroxylation).
  • Alcoholic –OH: Lucas test (ZnCl₂ + conc. HCl) — turbidity timing distinguishes 1°, 2°, 3° alcohols. Ceric ammonium nitrate gives red colour. Sodium metal releases H₂ gas.
  • Phenolic –OH: Neutral FeCl₃ gives violet/blue/green colouration. Liebermann's nitroso reaction (brown → green → blue colour transitions).
  • Aldehydic –CHO: Tollens' test (silver mirror). Fehling's test (red Cu₂O precipitate). 2,4-DNP gives yellow/orange precipitate (carbonyl — shared with ketones).
  • Ketonic C=O: 2,4-DNP positive (yellow/orange ppt), but Tollens' negative, Fehling's negative. This distinction is the single most tested point.
  • Carboxylic –COOH: NaHCO₃ — effervescence (CO₂ evolution). Litmus turns red.
  • Primary amine –NH₂: Carbylamine test (isocyanide — foul smell with CHCl₃ + alc. KOH). Hinsberg test distinguishes 1°, 2°, 3° amines.

Common NEET trap: 2,4-DNP is positive for BOTH aldehydes and ketones (it detects the C=O bond). Students who see "2,4-DNP positive" and immediately conclude "aldehyde" lose marks. You must check Tollens'/Fehling's to distinguish.

Second trap: Bromine water decolourisation is shared between alkenes and phenols (phenols undergo electrophilic substitution, not addition). Context matters — if the compound is aromatic and gives FeCl₃ colour, the Br₂ decolourisation is phenolic substitution, not unsaturation.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Which reagent specifically distinguishes an aldehyde from a ketone?

MCQ 2Direct ApplicationPractice

A compound decolourises bromine water AND gives a violet colour with neutral FeCl₃. The functional group present is:

MCQ 3Easy RecallPractice

The carbylamine test (isocyanide test) is specific for:

MCQ 4Direct ApplicationPractice

A compound gives a positive 2,4-DNP test but negative Tollens' test. The functional group is:

MCQ 5Easy RecallPractice

Fehling's test gives a red precipitate with:

MCQ 6Direct ApplicationPractice

In the Hinsberg test, a secondary amine reacts with benzenesulphonyl chloride to form a product that is:

MCQ 7Easy RecallPractice

A liquid organic compound gives effervescence with NaHCO₃ solution. The gas evolved turns lime water milky. The functional group present is:

MCQ 8Concept TrapPractice

An organic compound gives a positive Baeyer's test (decolourises dilute alkaline KMnO₄) but does NOT decolourise bromine water. The most likely explanation is:

Worked Example

  1. 1

    Given

    - 2,4-DNP positive → carbonyl group (C=O) present - Tollens' negative → NOT an aldehyde - Iodoform positive → CH₃CO– group present

  2. 2

    Required

    Identify the functional group and the simplest structure consistent with all three tests.

  3. 3

    Concept

    2,4-DNP detects any C=O (aldehyde or ketone). Tollens' distinguishes: aldehydes positive, ketones negative. Iodoform test is positive for methyl ketones (CH₃–CO–R) and acetaldehyde (CH₃CHO) — but since Tollens' is negative, acetaldehyde is excluded.

  4. 4

    Reasoning chain

    - C=O present (2,4-DNP ✓) - Not aldehyde (Tollens' ✗) - Therefore: ketone - CH₃CO– group present (iodoform ✓) - Simplest methyl ketone: CH₃COCH₃ (acetone)

  5. 5

    Verification

    Acetone: 2,4-DNP → positive (ketone C=O) ✓ Acetone: Tollens' → negative (ketone, not aldehyde) ✓ Acetone: Iodoform → positive (has CH₃CO– adjacent to a methyl/H) ✓ All three observations are consistent.

  6. 6

    Final answer

    Functional group: **Ketone (C=O)** with a methyl group adjacent to the carbonyl. Simplest compound: **Acetone (CH₃COCH₃)**

  7. 7

    Common trap

    Students who see "iodoform positive" sometimes jump to "ethanol" (which also gives iodoform after oxidation). But ethanol has no C=O detectable by 2,4-DNP directly — you must read ALL test results together, not act on one alone.

  8. 8

    Extension

    If Tollens' had been POSITIVE (silver mirror) along with iodoform positive, the answer would be acetaldehyde (CH₃CHO) — the only aldehyde that gives iodoform.

  9. 9

    Similar NEET-style question

    "Compound Y gives a positive 2,4-DNP test, negative Fehling's test, and does NOT give iodoform. Identify the type of carbonyl compound." (Answer: a ketone without a CH₃CO– group, e.g., diethyl ketone.) ---

Before solving, remember these

Standard tests: (a) -OH alcohol: Na metal → H2 evolved. (b) Phenol: neutral FeCl3 → violet colour. (c) Aldehyde: Tollens reagent → silver mirror; Fehling → red Cu2O ppt. (d) Ketone: 2,4-DNP → orange/yellow ppt; iodoform if methyl ketone. (e) -COOH: NaHCO3 → effervescence (CO2). (f) -NH2: HNO2 → diazotisation (1° aromatic); carbylamine test.

-- NCERT, p. 290

Formulas

Molarity-stoichiometry titration

Use when normality is awkward (e.g., diprotic acids). Stoichiometric coefficients from balanced equation.

SymbolQuantitySI Unit
Mmolaritymol/L
VvolumeL
ncoefficient-

Valid when

  • Balanced equation known
  • Same end-point

Normality equation in titration

Equivalents of acid = equivalents of base at end-point. Or for redox: equivalents of oxidant = equivalents of reductant.

SymbolQuantitySI Unit
Nnormalityeq/L
VvolumemL or L

Valid when

  • Same titration end-point
  • Equivalent factors known

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Inorganic Exception

Cations like Pb²⁺ precipitate in BOTH Group I (with HCl) and Group II (with H2S) — assigning to only one group misses the redundancy.

When it triggers

Cation that appears in two analytical groups, e.g. Pb²⁺ (Group I + Group II) or Hg²⁺ vs Hg2²⁺.

How to avoid

Apply confirmatory tests for each candidate group; do not assume mutual exclusivity.

Category: Overthinking

Continuing to add titrant past the first persistent colour change because the colour seemed to fade after a swirl.

When it triggers

Question describes 'colour faded after swirling' or 'persistent colour' — distinguishes transient vs end-point.

How to avoid

End-point = first PERSISTENT colour change (lasts ≥30 s). Transient fades back to original on swirling.

Category: Similar Terms

Phenolphthalein (pH 8.2–10) and methyl orange (pH 3.1–4.4) only mark equivalence when the eq-pt pH falls within their range; using the wrong indicator gives an end-point that disagrees with the actual equivalence point.

When it triggers

Titration prompt mentions a specific weak/strong combination but asks which indicator is suitable.

How to avoid

Match the indicator's pH-change range to the equivalence-point pH: phenolphthalein for eq-pt > 7, methyl orange for eq-pt < 7.

Past Year Questions

3 questions from NEET 2024, 2025. Answers verified against NTA official keys.

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Test yourself on this topic with real past-paper questions:

Practice this topic →

Free NEET study resources

Get a structured 30-day study plan and a complete formula booklet — delivered to your inbox instantly.