Functional group detection in organic qualitative analysis is a high-frequency practical chemistry topic. NEET questions test whether you can match a specific chemical test (reagent + observable change) to the correct functional group — and the trap is confusing tests that produce similar observations for different groups.
Core principle: Each functional group reacts with a characteristic reagent to give a unique observable — a colour change, precipitate, gas evolution, or effervescence. Your job is to memorise the reagent–observation–inference triplet, not just the reagent name.
Key functional-group tests (NCERT Class 11 Chemistry, Chapter 12, practical section):
- Unsaturation (C=C): Bromine water decolourises (addition across the double bond). Baeyer's test — dilute alkaline KMnO₄ decolourises (syn-hydroxylation).
- Alcoholic –OH: Lucas test (ZnCl₂ + conc. HCl) — turbidity timing distinguishes 1°, 2°, 3° alcohols. Ceric ammonium nitrate gives red colour. Sodium metal releases H₂ gas.
- Phenolic –OH: Neutral FeCl₃ gives violet/blue/green colouration. Liebermann's nitroso reaction (brown → green → blue colour transitions).
- Aldehydic –CHO: Tollens' test (silver mirror). Fehling's test (red Cu₂O precipitate). 2,4-DNP gives yellow/orange precipitate (carbonyl — shared with ketones).
- Ketonic C=O: 2,4-DNP positive (yellow/orange ppt), but Tollens' negative, Fehling's negative. This distinction is the single most tested point.
- Carboxylic –COOH: NaHCO₃ — effervescence (CO₂ evolution). Litmus turns red.
- Primary amine –NH₂: Carbylamine test (isocyanide — foul smell with CHCl₃ + alc. KOH). Hinsberg test distinguishes 1°, 2°, 3° amines.
Common NEET trap: 2,4-DNP is positive for BOTH aldehydes and ketones (it detects the C=O bond). Students who see "2,4-DNP positive" and immediately conclude "aldehyde" lose marks. You must check Tollens'/Fehling's to distinguish.
Second trap: Bromine water decolourisation is shared between alkenes and phenols (phenols undergo electrophilic substitution, not addition). Context matters — if the compound is aromatic and gives FeCl₃ colour, the Br₂ decolourisation is phenolic substitution, not unsaturation.