Mohr's salt FeSO4·(NH4)2SO4·6H2O: dissolve equimolar FeSO4 + (NH4)2SO4 in dilute H2SO4, evaporate, cool — pale-green double salt crystallises. Potash alum K2SO4·Al2(SO4)3·24H2O: dissolve equimolar K2SO4 + Al2(SO4)3, evaporate, cool — octahedral colourless crystals. Both are double salts (ionise to constituent ions).
-- NCERT Class 12 Chemistry, Ch. 4, p. 118Mohr Salt Potash Alum
Lesson
The trap that costs marks here: aspirants confuse the indicator choice for titration of Mohr's salt with KMnO₄. Mohr's salt titration is a redox titration — KMnO₄ is self-indicating (decolourises until end-point, then first persistent pink). Picking phenolphthalein or methyl orange is a category error; those are acid-base indicators with pH-range logic that does not apply to permanganimetry.
What is Mohr's salt? Ferrous ammonium sulphate, FeSO₄·(NH₄)₂SO₄·6H₂O — a double salt (NCERT Class 12 Chemistry, Chapter 4, page 118). It is preferred over plain FeSO₄ because the ammonium ion stabilises Fe²⁺ against aerial oxidation. In NEET practical chemistry, it appears as the primary standard for standardising KMnO₄.
What is potash alum? K₂SO₄·Al₂(SO₄)₃·24H₂O — prepared by mixing hot concentrated solutions of K₂SO₄ and Al₂(SO₄)₃ in stoichiometric proportions, then crystallising on slow cooling. Its NEET relevance is limited to identification (colourless octahedral crystals, acidic solution, gives white gelatinous Al(OH)₃ with NaOH).
Bridge to NEET: Questions test (a) why Mohr's salt is preferred over FeSO₄, (b) indicator choice for permanganimetric titration, (c) the normality equation N₁V₁ = N₂V₂ applied to redox end-points.
Watch-out: The end-point of KMnO₄ vs Mohr's salt is the first persistent faint pink — not deep purple. Overshooting (adding excess KMnO₄ past the first colour hold) invalidates the titre value. Slow drop-wise addition near end-point is the procedural safeguard.
Practice MCQs
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
Mohr's salt has the formula:
Mohr's salt is preferred over ferrous sulphate as a primary standard because:
Potash alum has the formula:
In the titration of Mohr's salt against KMnO₄, the indicator used is:
In an acid-base titration of a weak acid with a strong base, which indicator is appropriate?
25.0 mL of 0.1 N Mohr's salt solution requires how many mL of 0.02 N KMnO₄ to reach the end-point?
A student performing KMnO₄ vs Mohr's salt titration notices the pink colour appears but fades on swirling. The correct action is:
A Mohr's salt solution is prepared by dissolving 3.92 g in 100 mL. Given M(Mohr's salt) = 392 g/mol and that Fe²⁺ → Fe³⁺ involves a 1-electron change, what is the normality of the solution with respect to the KMnO₄ titration?
Quick recall before you leave
Worked Example
- 1
Given
- Volume of Mohr's salt solution (analyte): V₁ = 25.00 mL - Normality of Mohr's salt: N₁ = 0.1 N (n-factor = 1 for Fe²⁺ → Fe³⁺) - Normality of KMnO₄ solution: N₂ = unknown - Titre volume (KMnO₄ used): V₂ = 20.00 mL - Medium: dilute H₂SO₄ (acidic), no separate indicator required
- 2
Required
Find the normality (N₂) of the KMnO₄ solution.
- 3
Concept
At the redox equivalence point, equivalents of reducing agent = equivalents of oxidising agent. This is expressed as N₁V₁ = N₂V₂.
- 4
Formula
N₁V₁ = N₂V₂
- 5
Substitution
0.1 × 25.00 = N₂ × 20.00
- 6
Calculation
N₂ = (0.1 × 25.00) / 20.00 = 2.500 / 20.00 = 0.125 N Note on exact values: The volumes 25.00 mL and 20.00 mL are measured values (4 significant figures from a burette). The normality 0.1 N is given as a 1-sig-fig value, so the final answer is limited to 1 significant figure. However, in NEET practical contexts, 0.1 N is conventionally treated as exact (defined concentration), giving the answer as 0.125 N (3 sig figs from the volume ratio).
- 7
Final answer
**N₂ = 0.125 N** The n-factor of KMnO₄ in acidic medium is 5 (Mn⁷⁺ → Mn²⁺), so the corresponding molarity = 0.125 / 5 = 0.025 M. This cross-check confirms the answer is physically reasonable.
- 8
Common trap
Overshooting the end-point: if the student records the titre as, say, 21.5 mL (added KMnO₄ past the first persistent pink), the calculated N₂ would be falsely low (0.116 N). The procedural safeguard is drop-wise addition near end-point and accepting the first 30-second-persistent faint pink.
- 9
Similar NEET-style question
"25.0 mL of a FeSO₄ solution of unknown concentration is titrated against 0.04 N KMnO₄. If 12.5 mL of KMnO₄ is consumed, what is the concentration of FeSO₄ in g/L?" (Apply N₁V₁ = N₂V₂ to find N₁, then convert normality to g/L using equivalent weight of FeSO₄.) ---
Before solving, remember these
Formulas
Molarity-stoichiometry titration
Use when normality is awkward (e.g., diprotic acids). Stoichiometric coefficients from balanced equation.
| Symbol | Quantity | SI Unit |
|---|---|---|
| M | molarity | mol/L |
| V | volume | L |
| n | coefficient | - |
Valid when
- Balanced equation known
- Same end-point
Normality equation in titration
Equivalents of acid = equivalents of base at end-point. Or for redox: equivalents of oxidant = equivalents of reductant.
| Symbol | Quantity | SI Unit |
|---|---|---|
| N | normality | eq/L |
| V | volume | mL or L |
Valid when
- Same titration end-point
- Equivalent factors known
Exam Traps & Common Mistakes
These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.
Category: Inorganic Exception
Cations like Pb²⁺ precipitate in BOTH Group I (with HCl) and Group II (with H2S) — assigning to only one group misses the redundancy.
When it triggers
Cation that appears in two analytical groups, e.g. Pb²⁺ (Group I + Group II) or Hg²⁺ vs Hg2²⁺.
How to avoid
Apply confirmatory tests for each candidate group; do not assume mutual exclusivity.
Category: Overthinking
Continuing to add titrant past the first persistent colour change because the colour seemed to fade after a swirl.
When it triggers
Question describes 'colour faded after swirling' or 'persistent colour' — distinguishes transient vs end-point.
How to avoid
End-point = first PERSISTENT colour change (lasts ≥30 s). Transient fades back to original on swirling.
Category: Similar Terms
Phenolphthalein (pH 8.2–10) and methyl orange (pH 3.1–4.4) only mark equivalence when the eq-pt pH falls within their range; using the wrong indicator gives an end-point that disagrees with the actual equivalence point.
When it triggers
Titration prompt mentions a specific weak/strong combination but asks which indicator is suitable.
How to avoid
Match the indicator's pH-change range to the equivalence-point pH: phenolphthalein for eq-pt > 7, methyl orange for eq-pt < 7.
Root cause: concept gap
Correction
Pb²⁺ appears in both Group I (PbCl2 white ppt, soluble in hot water) and Group II (PbS black ppt). Confirm with hot-water solubility test.
Root cause: concept gap
Correction
Strong-acid + strong-base: any indicator (eq pt = 7). Weak-acid + strong-base: phenolphthalein (eq pt > 7). Strong-acid + weak-base: methyl orange (eq pt < 7).
Root cause: rushed under time pressure
Correction
Slow drop-wise addition near the end-point; first persistent colour change is the end-point. Re-do if overshot.
Past Year Questions
3 questions from NEET 2024, 2025. Answers verified against NTA official keys.
How NEET usually asks this
Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.
Practical chemistry — titrimetric end-point selection, indicator–pH matching, qualitative-analysis cation/anion identification, organic functional-group tests.
Common distractors
wrong zero error direction
Sign convention is easily flipped.
Sources
Test yourself on this topic with real past-paper questions:
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