Biotech Medicine Insulin

8 MCQs9-step worked example
Source: NCERT BiomoleculesPYQ coverage: NEET 2020, 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The insulin trap: A and B chains are NOT made in one cell.

When NEET asks about recombinant insulin (Humulin), the most common mistake is assuming both polypeptide chains are produced together inside a single E. coli cell. They are not.

What NCERT says (Class 12 Biology, Chapter 11, page 242):

Human insulin consists of two polypeptide chains — chain A (21 amino acids) and chain B (30 amino acids). These are linked by disulfide bridges. In the human pancreas, insulin is initially synthesised as proinsulin — a single polypeptide that includes chain A, chain B, and a connecting C-peptide. The C-peptide is removed during maturation.

The biotechnology approach:

Eli Lilly produced Humulin in 1983 using a key strategy: the genes for chain A and chain B were introduced into two separate E. coli strains. Each strain expressed only one chain. The chains were then extracted, purified, and combined in vitro, where disulfide bonds formed between them to produce functional insulin.

Why not express proinsulin directly? Early E. coli systems could not reliably process the C-peptide removal. Separate expression avoided this folding problem entirely.

What NEET targets:

Questions test whether you know: (a) insulin has two chains linked by disulfide bonds, (b) recombinant production uses separate bacterial cultures for each chain, (c) assembly happens outside the cell, and (d) the distinction between proinsulin (with C-peptide) and mature insulin (without it).

Watch out: A distractor claiming "A and B chains are co-expressed and self-assemble inside E. coli" exploits the gap between knowing the chain structure and knowing the production method. The assembly is extracellular — that is the fact NEET rewards.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Human insulin consists of how many polypeptide chains, and what connects them?

MCQ 2Easy RecallPractice

What is the C-peptide in the context of insulin biosynthesis?

MCQ 3Easy RecallPractice

Which company first produced recombinant human insulin (Humulin) commercially?

MCQ 4Direct ApplicationPractice

In Eli Lilly's production of Humulin, the A and B chains of insulin were:

MCQ 5Direct ApplicationPractice

Why were the A and B chains of recombinant insulin expressed in separate *E. coli* cultures rather than as a single proinsulin polypeptide?

MCQ 6Direct ApplicationPractice

A student claims: "Proinsulin and mature insulin are identical molecules." Which correction is accurate?

MCQ 7Concept TrapPractice

If a biotechnology company wanted to produce functional human insulin by expressing proinsulin as a single polypeptide in *E. coli*, what additional processing step would be essential before the product could be used therapeutically?

MCQ 8CalculationPractice

Consider the following statements about recombinant insulin production:

Worked Example

  1. 1

    Given

    A question states: "In the production of recombinant human insulin, Eli Lilly expressed the A and B polypeptide chains of insulin in two separate *E. coli* strains. Explain why this approach was used instead of expressing proinsulin directly, and describe how functional insulin is obtained from the separately produced chains."

  2. 2

    Required

    Explain the rationale for separate-chain expression and describe the *in vitro* assembly process.

  3. 3

    Concept

    Human insulin is initially produced in the pancreas as proinsulin — a single polypeptide containing chain A (21 amino acids), chain B (30 amino acids), and a connecting C-peptide. Mature insulin is formed when the C-peptide is enzymatically removed and disulfide bonds link the two chains. Early *E. coli* expression systems lacked the post-translational machinery to cleave the C-peptide correctly.

  4. 4

    Formula/principle

    No mathematical formula applies. The governing principle is: *E. coli* can transcribe and translate eukaryotic cDNA but cannot perform complex post-translational processing (C-peptide excision).

  5. 5

    Substitution/application

    Eli Lilly introduced the chain A gene into one *E. coli* strain and the chain B gene into a separate strain. Each culture produces its respective polypeptide independently.

  6. 6

    Calculation/reasoning

    After expression and extraction: 1. Chain A and chain B are purified separately. 2. The purified chains are mixed under controlled oxidising conditions *in vitro*. 3. Disulfide bonds form between the correct cysteine residues, producing the two-chain insulin molecule. 4. The product (Humulin) is structurally identical to native human insulin.

  7. 7

    Final answer

    The two-strain approach was necessary because early *E. coli* could not process proinsulin's C-peptide. By expressing chains separately and assembling them extracellularly via disulfide bond formation, Eli Lilly produced functional human insulin identical to the native hormone.

  8. 8

    Common trap

    The common mistake is claiming that both chains are expressed together in one *E. coli* cell and self-assemble intracellularly. The assembly is extracellular (*in vitro*) — this is the fact NEET distractors exploit.

  9. 9

    Similar NEET-style question

    "Assertion (A): Recombinant insulin produced by *E. coli* is structurally identical to human insulin. Reason (R): Both A and B chains are co-expressed in the same *E. coli* cell, allowing natural folding. Choose the correct option." Answer: A is true, R is false. The chains are expressed in separate *E. coli* strains and combined *in vitro*. The product is indeed identical to human insulin, but the reason stated is incorrect. ---

Before solving, remember these

Recombinant insulin: Eli Lilly 1983 (Humulin) — A + B chains in E. coli, joined by disulfide. Gene therapy: ADA-deficient SCID (1990, Ashanti DeSilva). ELISA: enzyme-linked immunosorbent assay (HIV diagnosis). Molecular diagnosis: PCR for early detection.

-- NCERT Class 12 Biology, Ch. 11, p. 242

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Similar Terms

Bt: insect resistance (Cry toxin). RNAi: nematode resistance via gene silencing. Herbicide-tolerant: bar/EPSPS gene.

When it triggers

Question on which gene/strategy gives which trait.

How to avoid

Cry → insects. RNAi → nematodes. EPSPS → herbicide tolerance.

Category: Similar Terms

PCR amplifies (makes copies); blotting transfers + visualises specific bands. Different stages of analysis.

When it triggers

Question asks which technique amplifies vs detects.

How to avoid

Amplify = PCR. Detect specific = blot (Southern DNA, Northern RNA, Western protein).

Category: Similar Terms

Restriction enzymes CUT at recognition sites; ligase JOINS sticky ends with phosphodiester bonds; polymerase synthesises strands.

When it triggers

Question asks which tool performs which step.

How to avoid

Cut = restriction. Paste = ligase. Copy = polymerase. Cohen-Boyer used EcoRI + ligase for first rDNA.

Past Year Questions

26 questions from NEET 2020, 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2024

The following diagram shown restriction sites in E. coli cloning vector pBR322. Find the role of ‘X’ and ‘Y’ gens :

1The gene ‘X’ is responsible for resistance to antibiotics and ‘Y’ for protein involved in the replication of Plasmid.
2The gene ‘X’ is responsible for controlling the copy number of the linked DNA and ‘Y’ for protein involved in the replication of Plasmid.
3The gene ‘X’ is for protein involved in replication of Plasmid and ‘Y’ for resistance to antibiotics.
4Gene ’X’ is responsible for recognitions sites and ‘Y’ is responsible for antibiotic resistance
NTA Answer: Option 2(final)
NEET 2022

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Polymerase chain reaction is used in DNA amplification. Reason (R) : The ampicillin resistant gene is used as a selectable marker to check transformation In the light of the above statements, choose the correct answer from the options given below :

1(A) is not correct but (R) is correct
2Both (A) and (R) are correct and (R) is the correct explanation of (A)
3Both (A) and (R) are correct but (R) is not the correct explanation of (A)
4(A) is correct but (R) is not correct
NTA Answer: Option 3(final)
NEET 2022

Given below are two statements: Statement I: Restriction endonucleases recognise specific sequence to cut DNA known as palindromic nucleotide sequence. Statement II: Restriction endonucleases cut the DNA strand a little away from the centre of the palindromic site. In the light of the above statements, choose the most appropriate answer from the options given below:

1Statement I is incorrect but Statement II is correct
2Both Statement I and Statement II are correct
3Both Statement I and Statement II are incorrect
4Statement I is correct but Statement II is incorrect
NTA Answer: Option 2(final)
NEET 2020

¬˝ÁÃ’ œŸ ∞ ¡Êß◊Ê ∑ § Áfl ÿ ◊ ª‹Ã ∑§ÕŸ ∑§Ê ¬„øÊÁŸ∞– (4) After zygote formation

1Áø¬Áø¬ Á‚⁄ U «UË.∞Ÿ.∞. ‹Êߪ ¡ mÊ⁄UÊ ¡Ê «∏ ¡Ê ‚∑§Ã „Ò – 112. Identify the wrong statement with regard to Restriction Enzymes.
2¬˝àÿ ∑§ ¬˝ÁÃ’ œŸ ∞ ¡Êß◊ «UË.∞Ÿ.∞. ∑˝§◊ ∑§Ë ‹ê’Ê߸ ∑§Ê (1) Sticky ends can be joined by using DNA ÁŸ⁄UˡÊáÊ ∑§⁄U∑ § ∑§Êÿ¸ ∑§⁄Uà „Ò – ligases.
3ÿ «UË.∞Ÿ.∞. ∑§Ë ‹«∏Ë ∑§Ê ¬ÒÁ‹ã«˛UÊ Á◊∑§ SÕ‹Ê ¬⁄U (2) Each restriction enzyme functions by ∑§Ê≈Uà „Ò – inspecting the length of a DNA sequence. (3) They cut the strand of DNA at palindromic
4ÿ •ÊŸÈfl Á‡Ê∑§ ß ¡ËÁŸÿÁ⁄ Uª ◊ ©¬ÿÊ ªË „Ò – sites.
NTA Answer: Option 1(final)
NEET 2020

The sequence that controls the copy number of the 115. ∞∑§ fl Ä≈U⁄U ◊ ‚„‹ÇŸË «UË.∞Ÿ.∞. ∑§Ë ¬˝Áà ∑§Ë ‚ ÅÿÊ ∑§Ê linked DNA in the vector, is termed : ÁŸÿ ÁòÊà ∑§⁄UŸ flÊ‹ •ŸÈ∑˝§◊ ∑§Ê ÄÿÊ ∑§„Ê ¡ÊÃÊ „Ò?

1Recognition site (1) Á⁄U∑§ÊÚǟˇʟ (¬„øÊŸ) ‚Êß≈U
2Selectable marker
3Ori site (2) øÿŸÿÈÄà ◊Ê∑¸§⁄U
4Palindromic sequence (3) •Ê ⁄UË ‚Êß≈U (4) ¬Ò‹Ë «˛UÊ Á◊∑§ •ŸÈ∑˝§◊ 116. Name the enzyme that facilitates opening of DNA helix during transcription.
NTA Answer: Option 3(final)
NEET 2020

In gel electrophoresis, separated DNA fragments 124. ¡ ‹ ß‹ Ä≈˛UÊ »§Ê ⁄ UÁ‚‚ ◊ , ¬ÎÕ∑§ „È∞ «UË.∞Ÿ.∞. ∑ § πá«UÊ ∑§Ê can be visualized with the help of : Á∑§‚∑§Ë ‚„ÊÿÃÊ ‚ Œ πÊ ¡Ê ‚∑§ÃÊ „Ò?

1Ethidium bromide in infrared radiation (1) •fl⁄UÄà ÁflÁ∑§⁄UáÊ ◊ ∞ÁÕÁ«Uÿ◊ ’˝Ê ◊Êß«U ‚
2Acetocarmine in bright blue light (2) ø◊∑§Ë‹ ŸË‹ ¬˝∑§Ê‡Ê ◊ ∞ ‚Ë≈UÊ ∑§ÊÁ◊¸Ÿ ‚
3Ethidium bromide in UV radiation (3) UV ÁflÁ∑§⁄UáÊ ◊ ∞ÁÕÁ«Uÿ◊ ’˝Ê ◊Êß«U ‚
4Acetocarmine in UV radiation (4) UV ÁflÁ∑§⁄UáÊ ◊ ∞‚Ë≈UÊ ∑§ÊÁ◊¸Ÿ ‚
NTA Answer: Option 3(final)

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