Aufbau: orbitals filled in order of increasing energy (1s<2s<2p<3s<3p<4s<3d<...). Pauli: no two electrons in same atom have identical 4 quantum numbers. Hund: orbitals of same energy first filled singly with parallel spins.
-- NCERT Class 11 Chemistry, Ch. 2, p. 36Aufbau Pauli Hund
Lesson
The trap that costs marks here: You apply the Aufbau principle mechanically — fill 1s, 2s, 2p, 3s, 3p, 4s, 3d in sequence — and write Cr as [Ar] 3d⁴ 4s². The actual ground-state configuration is [Ar] 3d⁵ 4s¹. NEET exploits this directly.
The three rules governing electron filling:
Aufbau principle — Electrons occupy the lowest available energy orbital first. The filling order follows (n + l) rule: lower (n + l) fills first; for equal (n + l), lower n fills first. This gives the sequence: 1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → 5s → 4d → ...
Pauli exclusion principle — No two electrons in an atom can have the same set of four quantum numbers (n, l, mₗ, mₛ). Consequence: each orbital holds a maximum of 2 electrons with opposite spins.
Hund's rule of maximum multiplicity — Electrons occupy degenerate orbitals (same subshell) singly with parallel spins before pairing begins. In the 2p subshell (three orbitals), the fourth electron pairs — the first three go one each.
The Cr/Cu anomaly (NCERT Class 11 Chemistry Chapter 2, page 36):
Half-filled (d⁵) and fully filled (d¹⁰) d-subshells have extra stability due to exchange energy and symmetrical charge distribution. Chromium (Z = 24) adopts [Ar] 3d⁵ 4s¹ instead of [Ar] 3d⁴ 4s². Copper (Z = 29) adopts [Ar] 3d¹⁰ 4s¹ instead of [Ar] 3d⁹ 4s².
Watch-out: When writing configurations of ions (Cr³⁺, Cu²⁺), electrons are removed from 4s first (higher n), then 3d. Cr³⁺ = [Ar] 3d³. Cu²⁺ = [Ar] 3d⁹.
Practice MCQs
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
Which of the following represents the correct ground-state electronic configuration of chromium (Z = 24)?
The ground-state electronic configuration of Cu (Z = 29) is [Ar] 3d¹⁰ 4s¹. What is the configuration of Cu²⁺?
According to Hund's rule, the electronic configuration of nitrogen (Z = 7) in the ground state has the 2p electrons arranged as:
Which of the following sets of quantum numbers is NOT possible for an electron?
The Aufbau principle predicts the filling order based on the (n + l) rule. Which of the following orbitals is filled BEFORE 4d?
An atom has the electronic configuration [Ar] 3d⁵ 4s¹. This configuration is adopted because:
The maximum number of electrons that can have the quantum numbers n = 3 and mₛ = +½ is:
Which of the following electronic configurations violates the Pauli exclusion principle?
Worked Example
Pattern: P.CHE.U02.AUFBAU_ELECTRONIC_CONFIG — Write electronic configuration handling the Cr/Cu anomaly.
- 1
Given
Element: Chromium, Z = 24.
- 2
Required
Ground-state electronic configuration of Cr.
- 3
Concept
Apply the Aufbau principle with (n + l) filling order. Recognize that half-filled (d⁵) configurations have extra stability — Cr is a known anomaly where one 4s electron promotes to 3d.
- 4
Formula/Rule
Aufbau filling order: 1s → 2s → 2p → 3s → 3p → 4s → 3d. Anomaly rule: half-filled d⁵ → extra exchange-energy stability → one 4s electron promotes.
- 5
Substitution / Setup
Expected (mechanical Aufbau): [Ar] 3d⁴ 4s² (24 − 18 = 6 electrons after Ar; 2 in 4s, 4 in 3d). Apply anomaly: promote one 4s electron to 3d → [Ar] 3d⁵ 4s¹.
- 6
Calculation / Verification
Electron count check: 18 (Ar) + 5 (3d) + 1 (4s) = 24 ✓ d⁵ = half-filled (5 electrons in 5 orbitals, one per orbital with parallel spins per Hund's rule) ✓
- 7
Final answer
Cr (Z = 24): **[Ar] 3d⁵ 4s¹**
- 8
Common trap
Writing [Ar] 3d⁴ 4s² by mechanically applying Aufbau without recognizing the half-filled stability exception. NEET 2024 tested this directly.
- 9
Similar NEET-style question
"The ground-state electronic configuration of Cu⁺ (Z = 29) is:" Apply: Cu = [Ar] 3d¹⁰ 4s¹ (fully filled anomaly). Remove the 4s electron for Cu⁺ → [Ar] 3d¹⁰. ---
Before solving, remember these
Formulas
Bohr energy (hydrogen-like)
Energy of nth orbit. Negative (bound). Ground state H: -13.6 eV.
| Symbol | Quantity | SI Unit |
|---|---|---|
| E_n | orbit energy | eV |
| Z | nuclear charge | - |
| n | principal | - |
Valid when
- Hydrogen-like atom
- Non-relativistic
Bohr radius (hydrogen-like)
Radius of nth Bohr orbit for hydrogen-like atom of nuclear charge Z.
| Symbol | Quantity | SI Unit |
|---|---|---|
| n | principal quantum number | - |
| Z | nuclear charge | - |
| r_n | orbit radius | Å |
Valid when
- Hydrogen-like (one-electron) atom
- Non-relativistic
de Broglie wavelength
Wavelength associated with moving particle of momentum mv.
| Symbol | Quantity | SI Unit |
|---|---|---|
| h | Planck 6.626e-34 | J*s |
| m | mass | kg |
| v | velocity | m/s |
Valid when
- Non-relativistic
Heisenberg uncertainty
Position and momentum cannot both be known with arbitrary precision.
| Symbol | Quantity | SI Unit |
|---|---|---|
| Δx | position uncertainty | m |
| Δp | momentum uncertainty | kg*m/s |
Valid when
- Quantum scale; meaningful only when Δx, Δp comparable to atomic dimensions
Rydberg formula (H spectrum)
Spectral wavelengths of hydrogen-like atoms. Lyman (n1=1, UV), Balmer (n1=2, visible), Paschen (n1=3, IR).
| Symbol | Quantity | SI Unit |
|---|---|---|
| lambda | wavelength | m |
| R_H | Rydberg 1.097e7 | 1/m |
| Z | nuclear charge | - |
| n1, n2 | integers, n2>n1 | - |
Valid when
- One-electron atom
Exam Traps & Common Mistakes
These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.
Category: Inorganic Exception
Student writes Cr as [Ar]3d⁴4s² (expected) instead of actual [Ar]3d⁵4s¹. Same for Cu: actual [Ar]3d¹⁰4s¹ (one e⁻ promoted from 4s to 3d).
When it triggers
Question asks for ground-state electronic configuration of Cr (Z=24) or Cu (Z=29).
How to avoid
Half-filled (d⁵) and fully filled (d¹⁰) configurations have extra stability from exchange energy and symmetry. Cr and Cu adopt these configurations by promoting one 4s electron.
Category: Similar Terms
Student forgets Z² scaling when applying Bohr formulas to He⁺ (Z=2) or Li²⁺ (Z=3).
When it triggers
Question involves hydrogen-like ion (He+, Li2+, etc.).
How to avoid
E_n = -13.6 × Z²/n² eV. r_n = (0.529/Z) × n² Å. He+: 4× more bound than H. Li²⁺: 9× more bound. Always include Z².
Root cause: concept gap
Correction
Half-filled (d⁵) and full-filled (d¹⁰) configurations have extra exchange-energy stability. Cr and Cu adopt these by promoting one 4s electron.
Root cause: formula misuse
Correction
Always include Z². E_n = -13.6 × Z²/n². For He+: 4× more energetic than H. For Li²⁺: 9×.
Past Year Questions
9 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.
From the following pairs of ions which one is not an iso-electronic pair? Fe2+, Mn2+
How NEET usually asks this
Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.
Write electronic configuration, especially handling Cr/Cu anomalies and ions.
Common distractors
misses cr cu anomaly
Writes 3d⁴4s² instead of 3d⁵4s¹
Bohr energy difference between two levels; compute photon energy/wavelength using Rydberg or E_n formulas.
Common distractors
forgets z squared
Drops Z² for hydrogen-like
Apply Δx·Δp ≥ h/(4π) to find minimum uncertainty given the other.
Common distractors
uses h instead of h over 4pi
Drops 4π factor
Given orbital (e.g. 3p_z) or electron, identify n, l, m_l, m_s. Or check forbidden quantum number combinations.
Common distractors
uses wrong l range
Uses l ≤ n instead of l < n
Sources
Test yourself on this topic with real past-paper questions:
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