Dual Nature De Broglie

8 MCQs3 revision cards9-step worked example
Source: NCERT Structure of AtomPYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

De Broglie's hypothesis bridges the classical particle world with quantum wave behaviour: every moving particle has an associated wavelength λ = h/(mv). This relationship, confirmed experimentally by Davisson and Germer's electron diffraction, is the conceptual foundation for why electrons cannot be described by definite orbits in the quantum model (NCERT Class 11 Chemistry Chapter 2, page 24).

The formula and its moving parts. λ = h/(mv), where h is Planck's constant (6.626 × 10⁻³⁴ J·s), m is particle mass in kg, and v is velocity in m/s. Equivalently, λ = h/p where p = mv is momentum. For a particle accelerated through potential V, kinetic energy = eV, so p = √(2meV), giving λ = h/√(2meV).

Where aspirants lose marks. The most common confusion is unit inconsistency: mass given in grams or amu is plugged directly without converting to kg, or velocity in cm/s is used without converting to m/s. Since λ = h/(mv), a factor-of-1000 error in mass gives a factor-of-1000 error in wavelength — and that wrong answer is usually sitting among the options.

A second confusion: applying de Broglie to macroscopic objects and concluding "wavelength is zero." It is not zero — it is negligibly small (≈10⁻³⁴ m for a cricket ball) because mass is enormous. NEET may ask you to compute it to test whether you handle powers of ten correctly.

Key takeaway. Heavier or faster → shorter wavelength. Lighter or slower → longer wavelength. The relationship is inverse: double the momentum, halve the wavelength.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Direct ApplicationPractice

The de Broglie wavelength of a particle moving with velocity v is λ. If its velocity is doubled, the new wavelength is:

MCQ 2Easy RecallPractice

De Broglie's relationship λ = h/(mv) is valid for:

MCQ 3Direct ApplicationPractice

An electron (mass 9.1 × 10⁻³¹ kg) moves with a velocity of 1.0 × 10⁶ m/s. Its de Broglie wavelength is approximately:

MCQ 4CalculationPractice

If a proton and an α-particle are accelerated through the same potential difference, the ratio of their de Broglie wavelengths (λ_p / λ_α) is:

MCQ 5Easy RecallPractice

Which experiment provided the first direct evidence for de Broglie's hypothesis of matter waves?

MCQ 6Direct ApplicationPractice

A cricket ball of mass 0.15 kg is bowled at 30 m/s. Its de Broglie wavelength is of the order of:

MCQ 7Concept TrapPractice

An electron and a proton have the same kinetic energy. Which has the longer de Broglie wavelength?

MCQ 8CalculationPractice

The de Broglie wavelength of an electron accelerated through a potential difference of 100 V is closest to: (Given: m_e = 9.1 × 10⁻³¹ kg, e = 1.6 × 10⁻¹⁹ C, h = 6.6 × 10⁻³⁴ J·s)

Quick recall before you leave

Worked Example

  1. 1

    Given

    - Proton: mass m_p = 1.67 × 10⁻²⁷ kg, charge e = 1.6 × 10⁻¹⁹ C - α-particle: mass m_α = 4m_p = 6.68 × 10⁻²⁷ kg, charge q_α = 2e = 3.2 × 10⁻¹⁹ C - Both accelerated through the same potential difference V

  2. 2

    Required

    Ratio λ_p : λ_α

  3. 3

    Concept

    For a charged particle starting from rest and accelerated through V: KE = qV. Then λ = h/√(2m·KE) = h/√(2mqV).

  4. 4

    Formula

    λ = h / √(2mqV)

  5. 5

    Substitution (ratio form)

    λ_p / λ_α = √(m_α · q_α) / √(m_p · q_p) = √(4m_p · 2e) / √(m_p · e) = √(8m_p · e) / √(m_p · e)

  6. 6

    Calculation

    λ_p / λ_α = √8 = 2√2 ≈ 2.83 Note: The integers 4 (mass ratio) and 2 (charge ratio) are exact counting/defined values and do not limit significant figures.

  7. 7

    Final answer

    λ_p : λ_α = 2√2 : 1 The proton has a wavelength 2√2 times longer than the α-particle when both are accelerated through the same potential.

  8. 8

    Common trap

    Forgetting the charge factor. If you use only the mass ratio: √(m_α/m_p) = √4 = 2, you get the wrong ratio of 2:1 instead of 2√2:1. The α-particle carries charge 2e — this enters the formula via KE = qV.

  9. 9

    Similar NEET-style question

    A deuteron (mass 2m_p, charge e) and a proton are accelerated through the same potential difference. Find λ_p/λ_d. Solution sketch: λ_p/λ_d = √(m_d · q_d) / √(m_p · q_p) = √(2m_p · e) / √(m_p · e) = √2. ---

Before solving, remember these

de Broglie: λ = h/(mv). Every moving particle has wave nature. Heisenberg: Δx · Δp ≥ h/(4π); position and momentum cannot both be known precisely.

-- NCERT Class 11 Chemistry, Ch. 2, p. 24

Formulas

Bohr energy (hydrogen-like)

Energy of nth orbit. Negative (bound). Ground state H: -13.6 eV.

SymbolQuantitySI Unit
E_norbit energyeV
Znuclear charge-
nprincipal-

Valid when

  • Hydrogen-like atom
  • Non-relativistic

Bohr radius (hydrogen-like)

Radius of nth Bohr orbit for hydrogen-like atom of nuclear charge Z.

SymbolQuantitySI Unit
nprincipal quantum number-
Znuclear charge-
r_norbit radiusÅ

Valid when

  • Hydrogen-like (one-electron) atom
  • Non-relativistic

de Broglie wavelength

Wavelength associated with moving particle of momentum mv.

SymbolQuantitySI Unit
hPlanck 6.626e-34J*s
mmasskg
vvelocitym/s

Valid when

  • Non-relativistic

Heisenberg uncertainty

Position and momentum cannot both be known with arbitrary precision.

SymbolQuantitySI Unit
Δxposition uncertaintym
Δpmomentum uncertaintykg*m/s

Valid when

  • Quantum scale; meaningful only when Δx, Δp comparable to atomic dimensions

Rydberg formula (H spectrum)

Spectral wavelengths of hydrogen-like atoms. Lyman (n1=1, UV), Balmer (n1=2, visible), Paschen (n1=3, IR).

SymbolQuantitySI Unit
lambdawavelengthm
R_HRydberg 1.097e71/m
Znuclear charge-
n1, n2integers, n2>n1-

Valid when

  • One-electron atom

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Inorganic Exception

Student writes Cr as [Ar]3d⁴4s² (expected) instead of actual [Ar]3d⁵4s¹. Same for Cu: actual [Ar]3d¹⁰4s¹ (one e⁻ promoted from 4s to 3d).

When it triggers

Question asks for ground-state electronic configuration of Cr (Z=24) or Cu (Z=29).

How to avoid

Half-filled (d⁵) and fully filled (d¹⁰) configurations have extra stability from exchange energy and symmetry. Cr and Cu adopt these configurations by promoting one 4s electron.

Category: Similar Terms

Student forgets Z² scaling when applying Bohr formulas to He⁺ (Z=2) or Li²⁺ (Z=3).

When it triggers

Question involves hydrogen-like ion (He+, Li2+, etc.).

How to avoid

E_n = -13.6 × Z²/n² eV. r_n = (0.529/Z) × n² Å. He+: 4× more bound than H. Li²⁺: 9× more bound. Always include Z².

Past Year Questions

9 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2024Revised key

Given below are two statements : Statement I : [Co(NH ) ]3+ is a homoleptic complex whereas [Co(NH ) Cl ]+ is a heteroleptic complex. 3 6 3 4 2 Statement II : Complex [Co(NH ) ]3+ has only one kind of ligands but [Co(NH ) Cl ]+ has more than one kind 3 6 3 4 2 of ligands. In the light of the above statements, choose the correct answer from the options given below.

1Both Statement I and Statement II are true
2Both Statement I and Statement II are false
3Statement I is true but Statement II is false
4Statement I is false but Statement II is true
NTA Answer: Option 1(revised_final)
NEET 2023

Select the correct statements from the following A. Atoms of all elements are composed of two fundamental particles. B. The mass of the electron is 9.10939 × 10–31 kg. C. All the isotopes of a given element show same chemical properties: D. Protons and electrons are collectively known as nucleons. E. Dalton’s atomic theory, regarded the atom as an ultimate particles of matter Choose the correct answer from the options given below

1C, D and E only
2A and E only
3B, C and E only
4A, B and C only
NTA Answer: Option 3(final)
NEET 2021

Statement I : Acid strength increases in the order given as HF << HCl << HBr << HI. Statement II : As the size of the elements F, Cl, Br, I increases down the group, the bond strength of HF, HCl, HBr and HI decreases and so the acid strength increases. In the light of the above statements, choose the correct answer from the options given below.

1Statement I is incorrect but Statement II is true
2Both statement I and Statement II are true
3Both Statement I and Statement II are false
4Statement I : correct but statement II is false
NTA Answer: Option 2(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Sources

NCERT refs: Class 11 Chemistry Chapter 2, p.24

Test yourself on this topic with real past-paper questions:

Practice this topic →

Free NEET study resources

Get a structured 30-day study plan and a complete formula booklet — delivered to your inbox instantly.