Heisenberg Uncertainty

8 MCQs2 revision cards9-step worked example
Source: NCERT Structure of AtomPYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The trap that costs marks: using h instead of h/(4π) as the minimum product of uncertainties. The Heisenberg principle states Δx·Δp ≥ h/(4π), not Δx·Δp ≥ h. Dropping the 4π denominator inflates your answer by roughly 12.6 times — and that wrong value will be waiting as a distractor.

The principle (NCERT Class 11 Chemistry Chapter 2, page 24): It is impossible to determine simultaneously the exact position and exact momentum of a microscopic particle with arbitrary precision. The product of uncertainties has a lower bound:

Δx · Δp ≥ h/(4π)

where h = 6.626 × 10⁻³⁴ J·s and Δp = m·Δv for a particle of mass m.

Why it matters for NEET: The principle explains why Bohr orbits (precise r and v simultaneously) are fundamentally invalid — electrons don't have well-defined trajectories. Questions typically give one uncertainty and ask you to compute the minimum value of the other. The calculation is straightforward substitution, but the 4π factor is the discriminator between correct and wrong options.

Variant you must handle: Sometimes the question gives Δv (velocity uncertainty) instead of Δp directly. Then Δp = m·Δv, and the formula becomes:

Δx ≥ h/(4π·m·Δv)

Watch-out: The inequality uses ≥. "Minimum uncertainty in position" means you use the equality: Δx_min = h/(4π·Δp). If the question asks for "minimum," replace ≥ with =.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

The Heisenberg uncertainty principle is expressed as Δx·Δp ≥ h/(4π). What does this principle fundamentally state?

MCQ 2Easy RecallPractice

What is the minimum value of Δx·Δp according to the Heisenberg uncertainty principle?

MCQ 3Direct ApplicationPractice

The uncertainty in the velocity of a particle is 3.0 × 10⁵ m/s. If the mass of the particle is 1.0 × 10⁻²⁸ kg, what is the minimum uncertainty in its position? (h = 6.6 × 10⁻³⁴ J·s)

MCQ 4Direct ApplicationPractice

An electron (mass = 9.1 × 10⁻³¹ kg) has uncertainty in position Δx = 0.1 nm. What is the minimum uncertainty in its velocity? (h = 6.6 × 10⁻³⁴ J·s)

MCQ 5Easy RecallPractice

Which of the following correctly represents the Heisenberg uncertainty relationship?

MCQ 6Concept TrapPractice

Why does the Heisenberg uncertainty principle make Bohr's model fundamentally incorrect?

MCQ 7Concept TrapPractice

A proton (mass = 1.67 × 10⁻²⁷ kg) and an electron (mass = 9.1 × 10⁻³¹ kg) have the same uncertainty in momentum. Which has greater minimum uncertainty in position?

MCQ 8Direct ApplicationPractice

If the uncertainty in the position of an electron is 2.0 × 10⁻¹⁰ m, what is the minimum uncertainty in its momentum? (h = 6.6 × 10⁻³⁴ J·s)

Quick recall before you leave

Worked Example

  1. 1

    Given

    - Mass of electron, m = 9.1 × 10⁻³¹ kg - Uncertainty in velocity, Δv = 5.0 × 10⁵ m/s - h = 6.6 × 10⁻³⁴ J·s

  2. 2

    Required

    Minimum uncertainty in position (Δx_min).

  3. 3

    Concept

    Heisenberg uncertainty principle: the product of uncertainties in position and momentum has a minimum value h/(4π). Since we are given velocity uncertainty, we first convert to momentum uncertainty using Δp = m·Δv.

  4. 4

    Formula

    Δx_min = h/(4π·m·Δv)

  5. 5

    Substitution

    Δx_min = (6.6 × 10⁻³⁴) / (4 × 3.14 × 9.1 × 10⁻³¹ × 5.0 × 10⁵)

  6. 6

    Calculation

    Denominator = 4 × 3.14 × 9.1 × 10⁻³¹ × 5.0 × 10⁵ = 12.56 × 4.55 × 10⁻²⁵ = 5.715 × 10⁻²⁴ Δx_min = 6.6 × 10⁻³⁴ / 5.715 × 10⁻²⁴ = 1.155 × 10⁻¹⁰ m ≈ 1.16 × 10⁻¹⁰ m **Note on exact constants:** The integers 4 and the mathematical constant π are exact and do not limit significant figures. The answer precision is governed by the given data (2 significant figures).

  7. 7

    Final answer

    Δx_min ≈ 1.16 × 10⁻¹⁰ m (≈ 1.16 Å)

  8. 8

    Common trap

    Using h/(m·Δv) without the 4π factor gives 1.45 × 10⁻⁹ m — approximately 12.6× too large. This is the most frequent wrong answer in NEET options for this pattern. Also watch for using h/(2π) = ℏ instead of h/(4π) = ℏ/2.

  9. 9

    Similar NEET-style question

    A proton (mass 1.67 × 10⁻²⁷ kg) has uncertainty in position 1.0 × 10⁻¹¹ m. Find the minimum uncertainty in its velocity. [Answer: Δv_min = h/(4π·m·Δx) = 6.6 × 10⁻³⁴/(4 × 3.14 × 1.67 × 10⁻²⁷ × 1.0 × 10⁻¹¹) ≈ 3.15 × 10⁴ m/s] ---

Before solving, remember these

de Broglie: λ = h/(mv). Every moving particle has wave nature. Heisenberg: Δx · Δp ≥ h/(4π); position and momentum cannot both be known precisely.

-- NCERT Class 11 Chemistry, Ch. 2, p. 24

Formulas

Bohr energy (hydrogen-like)

Energy of nth orbit. Negative (bound). Ground state H: -13.6 eV.

SymbolQuantitySI Unit
E_norbit energyeV
Znuclear charge-
nprincipal-

Valid when

  • Hydrogen-like atom
  • Non-relativistic

Bohr radius (hydrogen-like)

Radius of nth Bohr orbit for hydrogen-like atom of nuclear charge Z.

SymbolQuantitySI Unit
nprincipal quantum number-
Znuclear charge-
r_norbit radiusÅ

Valid when

  • Hydrogen-like (one-electron) atom
  • Non-relativistic

de Broglie wavelength

Wavelength associated with moving particle of momentum mv.

SymbolQuantitySI Unit
hPlanck 6.626e-34J*s
mmasskg
vvelocitym/s

Valid when

  • Non-relativistic

Heisenberg uncertainty

Position and momentum cannot both be known with arbitrary precision.

SymbolQuantitySI Unit
Δxposition uncertaintym
Δpmomentum uncertaintykg*m/s

Valid when

  • Quantum scale; meaningful only when Δx, Δp comparable to atomic dimensions

Rydberg formula (H spectrum)

Spectral wavelengths of hydrogen-like atoms. Lyman (n1=1, UV), Balmer (n1=2, visible), Paschen (n1=3, IR).

SymbolQuantitySI Unit
lambdawavelengthm
R_HRydberg 1.097e71/m
Znuclear charge-
n1, n2integers, n2>n1-

Valid when

  • One-electron atom

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Inorganic Exception

Student writes Cr as [Ar]3d⁴4s² (expected) instead of actual [Ar]3d⁵4s¹. Same for Cu: actual [Ar]3d¹⁰4s¹ (one e⁻ promoted from 4s to 3d).

When it triggers

Question asks for ground-state electronic configuration of Cr (Z=24) or Cu (Z=29).

How to avoid

Half-filled (d⁵) and fully filled (d¹⁰) configurations have extra stability from exchange energy and symmetry. Cr and Cu adopt these configurations by promoting one 4s electron.

Category: Similar Terms

Student forgets Z² scaling when applying Bohr formulas to He⁺ (Z=2) or Li²⁺ (Z=3).

When it triggers

Question involves hydrogen-like ion (He+, Li2+, etc.).

How to avoid

E_n = -13.6 × Z²/n² eV. r_n = (0.529/Z) × n² Å. He+: 4× more bound than H. Li²⁺: 9× more bound. Always include Z².

Past Year Questions

9 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2024Revised key

Given below are two statements : Statement I : [Co(NH ) ]3+ is a homoleptic complex whereas [Co(NH ) Cl ]+ is a heteroleptic complex. 3 6 3 4 2 Statement II : Complex [Co(NH ) ]3+ has only one kind of ligands but [Co(NH ) Cl ]+ has more than one kind 3 6 3 4 2 of ligands. In the light of the above statements, choose the correct answer from the options given below.

1Both Statement I and Statement II are true
2Both Statement I and Statement II are false
3Statement I is true but Statement II is false
4Statement I is false but Statement II is true
NTA Answer: Option 1(revised_final)
NEET 2023

Select the correct statements from the following A. Atoms of all elements are composed of two fundamental particles. B. The mass of the electron is 9.10939 × 10–31 kg. C. All the isotopes of a given element show same chemical properties: D. Protons and electrons are collectively known as nucleons. E. Dalton’s atomic theory, regarded the atom as an ultimate particles of matter Choose the correct answer from the options given below

1C, D and E only
2A and E only
3B, C and E only
4A, B and C only
NTA Answer: Option 3(final)
NEET 2021

Statement I : Acid strength increases in the order given as HF << HCl << HBr << HI. Statement II : As the size of the elements F, Cl, Br, I increases down the group, the bond strength of HF, HCl, HBr and HI decreases and so the acid strength increases. In the light of the above statements, choose the correct answer from the options given below.

1Statement I is incorrect but Statement II is true
2Both statement I and Statement II are true
3Both Statement I and Statement II are false
4Statement I : correct but statement II is false
NTA Answer: Option 2(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Sources

NCERT refs: Class 11 Chemistry Chapter 2, p.24

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