Functional groups
Group of atoms responsible for characteristic reactions of a compound. Common: -OH (alcohol), -CHO (aldehyde), >C=O (ketone), -COOH (carboxylic acid), -NH₂ (amine), -X (halide), -O- (ether), -NO₂ (nitro).
-- NCERT, p. 10The functional group is the atom or group of atoms within an organic molecule that determines its chemical behaviour. Two molecules may have identical carbon chain lengths but behave completely differently because they carry different functional groups. This is the basis for classifying organic compounds — not by molecular formula or carbon count, but by the reactive site.
NCERT Class 11 Chemistry Chapter 9 (Part 2, page 10) lists the major functional groups systematically: hydroxyl (–OH) for alcohols and phenols, carbonyl (C=O) for aldehydes and ketones, carboxyl (–COOH) for carboxylic acids, amino (–NH₂) for amines, nitro (–NO₂), halide (–X), and so on. Each functional group defines a homologous series — a family of compounds with the same functional group but differing chain lengths, sharing similar chemical properties.
What NEET actually tests here: The exam checks whether you can identify the functional group present in a given structure, classify the compound into the correct homologous series, and distinguish between compounds that look similar but belong to different classes. A common confusion is between aldehydes and ketones — both contain C=O, but the position differs (terminal in aldehydes, internal in ketones). Another frequent error is confusing alcohols (–OH on sp³ carbon) with phenols (–OH directly on benzene ring) — they are classified separately because their chemical reactivity differs substantially.
The classification hierarchy works as follows: first identify the functional group, then name the homologous series, then apply IUPAC naming rules specific to that class. Compounds with more than one functional group are classified by the principal (highest-priority) functional group according to the IUPAC priority order: –COOH > –SO₃H > –COOR > –COX > –CONH₂ > –CHO > >C=O > –OH > –NH₂ > –C≡C– > –C=C–.
Watch out: when a molecule has both –OH and –CHO, it is classified as an aldehyde (not an alcohol), because –CHO has higher priority.
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
Which functional group is present in carboxylic acids?
Which of the following pairs of compounds belong to the same homologous series?
The functional group present in an ester is:
A compound has the molecular formula C₃H₆O. It gives a positive silver mirror test. The functional group present is:
A compound contains both –OH and –CHO functional groups. According to IUPAC priority rules, it is classified as:
Which of the following compounds is correctly classified?
Two compounds have the molecular formula C₂H₆O. Compound X reacts with sodium metal to release hydrogen gas; compound Y does not. What are the functional groups in X and Y respectively?
Among the following functional groups, which has the highest priority in IUPAC nomenclature for determining the principal characteristic group?
Given
- Molecular formula: C₄H₈O₂ - Functional groups present: –OH and –CHO - Degree of unsaturation: (2×4 + 2 − 8) / 2 = 1 (consistent with one C=O, no ring or C=C)
Required
Classify the compound, identify the principal functional group, and write the IUPAC name.
Concept
When a molecule has multiple functional groups, IUPAC rules require classifying by the highest-priority group. Priority order (relevant subset): –COOH > –CHO > –OH > –NH₂. The lower-priority group becomes a prefix substituent.
Formula / Rule
IUPAC priority: –CHO > –OH. Therefore the compound is classified as a **hydroxy aldehyde**, not an "aldehydic alcohol."
Substitution / Setup
Structure: HOCH₂CH₂CH₂CHO (4-hydroxybutanal). - Longest chain including –CHO: 4 carbons → butanal. - –CHO carbon = C-1 (by rule, aldehyde always gets position 1). - –OH is on C-4. - Name: 4-hydroxybutanal.
Calculation
No arithmetic calculation needed. This is a classification and naming problem. The key operation is applying the priority hierarchy: - –CHO is principal group → suffix "-al" (butanal) - –OH is subordinate → prefix "hydroxy-" at position 4
Final answer
The compound is classified as an **aldehyde** (not an alcohol). IUPAC name: **4-hydroxybutanal**. The –OH group appears as the prefix "hydroxy-" because it has lower priority than –CHO.
Common trap
Students sometimes classify this compound as an alcohol because –OH is the more "familiar" group, or they name it "4-oxobutan-1-ol" (treating –OH as principal). The IUPAC priority hierarchy is non-negotiable: –CHO always outranks –OH.
Similar NEET-style question
"A compound C₅H₁₀O₂ contains –OH and –COOH groups. What is the IUPAC classification and name?" (Answer: It is a carboxylic acid, not an alcohol. –COOH outranks –OH. Name: 5-hydroxypentanoic acid.) ---
Group of atoms responsible for characteristic reactions of a compound. Common: -OH (alcohol), -CHO (aldehyde), >C=O (ketone), -COOH (carboxylic acid), -NH₂ (amine), -X (halide), -O- (ether), -NO₂ (nitro).
-- NCERT, p. 10Stability from hyperconjugation (more α-H) and inductive donation (alkyl groups). Resonance can elevate primary cations.
| Symbol | Quantity | SI Unit |
|---|---|---|
| stability | relative | - |
These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.
Category: Similar Terms
Student writes 1° > 2° > 3° (linear with substitution count, but inverted) or treats methyl as more stable.
Question gives multiple carbocations and asks for stability ranking.
Stability: 3° > 2° > 1° > methyl. Hyperconjugation (more α-H = more stable). Resonance can elevate (allyl, benzyl > 1°).
Category: Similar Terms
Student treats inductive (through sigma bonds, decreases with distance) like resonance (through pi system, often dominant).
Comparison of substituent effects (acidity, basicity, dipole moment).
Inductive: through-bond, weakens with distance, only sigma. Resonance: through-pi-system, often more powerful, requires conjugation.
Category: Similar Terms
Student numbers carbon chain from wrong end, giving higher locants to substituents than necessary.
IUPAC naming question with multiple substituents.
Choose end that gives the LOWEST set of locants for all substituents (compare set, not first-encountered). Functional group has priority for lowest locant.
Category: Similar Terms
Student conflates optical (chirality, R/S) with geometrical (cis/trans). They're different stereoisomerism types.
Question about isomerism of a specific compound.
Optical isomerism requires chiral center (sp³ with 4 different groups). Geometrical isomerism requires restricted rotation (C=C with two different groups on each carbon).
Root cause: concept gap
Stability follows hyperconjugation: more α-H → more stable. Order: 3° > 2° > 1° > methyl. Allyl/benzyl resonance-stabilised.
Root cause: concept gap
Hyperconjugation requires α-C-H bond. tert-Butyl carbocation: 9 α-H → very stable. No-α-H carbocation: no hyperconjugation.
Root cause: concept gap
Inductive: through sigma, weakens with distance, weak. Resonance: through pi, often dominant for activated systems.
Root cause: rushed under time pressure
Try numbering from BOTH ends; pick the one giving the lowest SET of locants. Functional group has priority for lowest locant.
Root cause: concept gap
Optical: chirality (sp³ with 4 different groups). Geometrical: restricted rotation (C=C). Different molecular features required.
11 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.
Which one of the following compounds can exist as cis-trans isomers?
A compound with a molecular formula of C H has two tertiary carbons. Its IUPAC name is : 6 14
The incorrect statement regarding chirality is
The correct IUPAC name of the following compound is
Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.
ignores resonance
Compares only by alkyl substitution
Test yourself on this topic with real past-paper questions:
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