Phenol Acidic Nature

8 MCQs9-step worked example
Source: NCERT BiomoleculesPYQ coverage: NEET 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

Why phenol is acidic — and why NEET keeps testing the reasoning behind it.

A common confusion on exam day: students know phenol is acidic but pick the wrong explanation for why, or they misjudge acidity order when substituents enter the picture.

The core fact. Phenol (C₆H₅OH) has a pKa of approximately 10, making it roughly 10⁶ times more acidic than a typical aliphatic alcohol (pKa 16–18). It is, however, a weaker acid than carboxylic acids (pKa 4–5). Phenol turns blue litmus red slowly and reacts with NaOH but does NOT react with NaHCO₃ — that bicarbonate test distinguishes phenols from carboxylic acids. (NCERT Class 12 Chemistry Chapter 7, Part 2, page 12.)

Why the acidity gap? When phenol loses its O–H proton, the resulting phenoxide ion (C₆H₅O⁻) is stabilised by resonance: the negative charge delocalises into the benzene ring across five contributing structures. In an aliphatic alkoxide (like CH₃CH₂O⁻), no such delocalisation is available — the charge sits localised on oxygen. Greater stabilisation of the conjugate base means greater acidity of the parent compound.

Substituent effects — the NEET trap zone. Electron-withdrawing groups (–NO₂, –Cl, –CN) on the ring further stabilise phenoxide → increase acidity (lower pKa). Electron-donating groups (–CH₃, –OCH₃, –NH₂) destabilise phenoxide → decrease acidity (higher pKa). Position matters: para-nitrophenol is more acidic than ortho-nitrophenol (intramolecular hydrogen bonding in the ortho isomer partially stabilises the undissociated form). The pattern NEET pattern: phenol electrophilic substitution has appeared in four NEET papers (2021–2025), often asking you to rank substituted phenols by acid strength.

Watch-out. Don't confuse resonance stabilisation of phenoxide (which explains acidity) with the activating effect of –OH on electrophilic substitution (which explains ortho-para directing). They share the same resonance arrows but answer different questions.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Phenol reacts with aqueous NaOH but does NOT react with aqueous NaHCO₃. What does this indicate about phenol's acid strength?

MCQ 2Easy RecallPractice

The pKa of phenol is approximately:

MCQ 3Easy RecallPractice

Which of the following does NOT react with aqueous NaHCO₃ to liberate CO₂?

MCQ 4Direct ApplicationPractice

Phenol is more acidic than ethanol. The primary reason is:

MCQ 5Direct ApplicationPractice

Arrange the following in order of increasing acid strength: ethanol, phenol, p-nitrophenol.

MCQ 6Direct ApplicationPractice

Among the following substituted phenols, which is the LEAST acidic?

MCQ 7Concept TrapPractice

A student argues that phenol is acidic because the –OH group directly donates its lone pair to the ring, weakening the O–H bond. Which statement best corrects this reasoning?

MCQ 8CalculationPractice

Consider the following compounds:

Worked Example

  1. 1

    Given

    Four phenol derivatives with different para-substituents: –NO₂ (strong EWG, –I and –M), –Cl (EWG, –I dominates), –H (no substituent), –CH₃ (EDG, +I).

  2. 2

    Required

    Decreasing order of acid strength (lowest pKa first).

  3. 3

    Concept

    Acid strength of substituted phenols depends on the stability of the corresponding phenoxide ion. Electron-withdrawing groups (EWGs) stabilise phenoxide by dispersing the negative charge → increase acidity. Electron-donating groups (EDGs) destabilise phenoxide → decrease acidity. (NCERT Class 12 Chemistry Chapter 7, Part 2, page 12.)

  4. 4

    Formula

    No arithmetic formula required. Apply the substituent-effect rule: EWG → lower pKa; EDG → higher pKa. Reference pKa values: phenol ≈ 10.0.

  5. 5

    Substitution / classification

    - –NO₂: strong EWG (–I and –M) → strongly stabilises phenoxide → most acidic - –Cl: moderate EWG (–I dominates over weak +M) → moderately stabilises phenoxide - –H: reference compound - –CH₃: weak EDG (+I, hyperconjugation) → slightly destabilises phenoxide → least acidic

  6. 6

    Ranking

    Decreasing acid strength: p-nitrophenol > p-chlorophenol > phenol > p-methylphenol. Approximate pKa values: 7.15 < 9.4 < 10.0 < 10.3.

  7. 7

    Final answer

    **(a) > (d) > (b) > (c)** — p-nitrophenol > p-chlorophenol > phenol > p-methylphenol.

  8. 8

    Common trap

    Confusing the +M (resonance-donating) effect of –Cl with its –I (inductive-withdrawing) effect. In the para position, the –I effect of chlorine dominates over the weak +M, making p-chlorophenol MORE acidic than phenol. Students who focus only on resonance donation may incorrectly place p-chlorophenol as less acidic than phenol.

  9. 9

    Similar NEET-style question

    Arrange in order of increasing acid strength: 2,4,6-trinitrophenol, m-nitrophenol, o-cresol, phenol. (*Answer: o-cresol < phenol < m-nitrophenol < 2,4,6-trinitrophenol.*) ---

Before solving, remember these

Ammonia is trigonal pyramidal (sp³, one lone pair). Haber process: N₂ + 3H₂ ⇌ 2NH₃ (Fe catalyst, 200 atm, 700 K). NH₃ has high bp (239.7 K) and mp (198.4 K) for its molar mass because of intermolecular H-bonding. Dissolves readily in water: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻. Acts as Lewis base (lone pair donor). Na dissolved in liquid NH₃ gives blue solution (solvated electrons); on standing or with catalyst gives NaNH₂ (colourless).

-- NCERT Class 12 Chemistry, Ch. 7, p. 5

Formulas

pKa of carboxylic acid

Stronger acid than phenol due to more effective resonance over two equivalent oxygens. EWG substituents (Cl, NO2) increase acidity.

SymbolQuantitySI Unit
pKa-log Ka-

Valid when

  • Aqueous solution
  • α-substituent effects strongest

pKa of phenol vs aliphatic alcohol

Phenols ~10⁶× more acidic than aliphatic alcohols due to resonance stabilisation of phenoxide ion. Electron-withdrawing substituents lower pKa further.

SymbolQuantitySI Unit
pKa-log Ka-

Valid when

  • Aqueous solution
  • Substituent effects shift values

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

Category: Organic Reaction Conditions

1° alcohol: PCC/PDC → aldehyde (stops). KMnO4/K2Cr2O7 in acidic → carboxylic acid (continues). 2° alcohol: any oxidiser → ketone. 3° alcohol: not oxidised by ordinary reagents.

When it triggers

Question gives 1° alcohol oxidation with specified reagent.

How to avoid

PCC, PDC, Swern, DMP: mild → stop at aldehyde. KMnO4, K2Cr2O7, CrO3, jones: strong → carboxylic acid. Reagent choice matches desired product.

Past Year Questions

20 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.

NEET 2024Revised key

Given below are two statements: Statement I : Aniline does not undergo Friedel-Crafts alkylation reaction. Statement II : Aniline cannot be prepared through Gabriel synthesis . In the light of the above statements, choose the correct answer from the options given below:

1Both statement I and Statement II are true
2Both Statement I and Statement II are false
3Statement I is correct but Statement II is false
4Statement I is incorrect but Statement II is true
NTA Answer: Option 1(revised_final)
NEET 2024Revised key

Fehling’s solution ‘A’ is

1aqueous copper sulphate
2alkaline copper sulphate
3alkaline solution of sodium potassium tartrate (Rochelle’s salt)
4aqueous sodium citrate
NTA Answer: Option 1(revised_final)
NEET 2022

Given below are two statements: Statement I: In Lucas test, primary, secondary and tertiary alcohols are distinguished on the basis of their reactivity with conc. HCl + ZnCl , known as Lucas Reagent. 2 Statement II: Primary alcohols are most reactive and immediately produce turbidity at room temperature on reaction with Lucas Reagent. In the light of the above statements, choose the most appropriate answer from the options given below:

1Statement I is incorrect but Statement II is correct
2Both Statement I and Statement II are correct
3Both Statement I and Statement II are incorrect
4Statement I is correct but Statement II is incorrect
NTA Answer: Option 4(final)
NEET 2021

Match List-I with List-II List-I List-II CO, HCI (a) (i) Hell-Volhard-Zelinsky Anhyd. AlCl/ Cu3Cl reaction O R — C — CH + (b) (ii) Gattermann-Koch 3 NaOX reaction R — CH — OH (c) (iii) Haloform reaction 2 +R′ COOH Conc. HSO 2 4 (d) R — CH COOH (iv) Esterification 2 ( II) X /Red P 2 (ii) HO 2 Choose the correct answer from the options given below.

1(a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)
2(a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
3(a) - (iii), (b) - (ii), (c) - (i), (d) - (iv)
4(a) - (i), (b) - (iv), (c) - (iii), (d) - (ii)
NTA Answer: Option 1(final)

How NEET usually asks this

Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.

Test yourself on this topic with real past-paper questions:

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