Ammonia is trigonal pyramidal (sp³, one lone pair). Haber process: N₂ + 3H₂ ⇌ 2NH₃ (Fe catalyst, 200 atm, 700 K). NH₃ has high bp (239.7 K) and mp (198.4 K) for its molar mass because of intermolecular H-bonding. Dissolves readily in water: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻. Acts as Lewis base (lone pair donor). Na dissolved in liquid NH₃ gives blue solution (solvated electrons); on standing or with catalyst gives NaNH₂ (colourless).
-- NCERT Class 12 Chemistry, Ch. 7, p. 5Phenol Acidic Nature
Lesson
Why phenol is acidic — and why NEET keeps testing the reasoning behind it.
A common confusion on exam day: students know phenol is acidic but pick the wrong explanation for why, or they misjudge acidity order when substituents enter the picture.
The core fact. Phenol (C₆H₅OH) has a pKa of approximately 10, making it roughly 10⁶ times more acidic than a typical aliphatic alcohol (pKa 16–18). It is, however, a weaker acid than carboxylic acids (pKa 4–5). Phenol turns blue litmus red slowly and reacts with NaOH but does NOT react with NaHCO₃ — that bicarbonate test distinguishes phenols from carboxylic acids. (NCERT Class 12 Chemistry Chapter 7, Part 2, page 12.)
Why the acidity gap? When phenol loses its O–H proton, the resulting phenoxide ion (C₆H₅O⁻) is stabilised by resonance: the negative charge delocalises into the benzene ring across five contributing structures. In an aliphatic alkoxide (like CH₃CH₂O⁻), no such delocalisation is available — the charge sits localised on oxygen. Greater stabilisation of the conjugate base means greater acidity of the parent compound.
Substituent effects — the NEET trap zone. Electron-withdrawing groups (–NO₂, –Cl, –CN) on the ring further stabilise phenoxide → increase acidity (lower pKa). Electron-donating groups (–CH₃, –OCH₃, –NH₂) destabilise phenoxide → decrease acidity (higher pKa). Position matters: para-nitrophenol is more acidic than ortho-nitrophenol (intramolecular hydrogen bonding in the ortho isomer partially stabilises the undissociated form). The pattern NEET pattern: phenol electrophilic substitution has appeared in four NEET papers (2021–2025), often asking you to rank substituted phenols by acid strength.
Watch-out. Don't confuse resonance stabilisation of phenoxide (which explains acidity) with the activating effect of –OH on electrophilic substitution (which explains ortho-para directing). They share the same resonance arrows but answer different questions.
Practice MCQs
Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.
Phenol reacts with aqueous NaOH but does NOT react with aqueous NaHCO₃. What does this indicate about phenol's acid strength?
The pKa of phenol is approximately:
Which of the following does NOT react with aqueous NaHCO₃ to liberate CO₂?
Phenol is more acidic than ethanol. The primary reason is:
Arrange the following in order of increasing acid strength: ethanol, phenol, p-nitrophenol.
Among the following substituted phenols, which is the LEAST acidic?
A student argues that phenol is acidic because the –OH group directly donates its lone pair to the ring, weakening the O–H bond. Which statement best corrects this reasoning?
Consider the following compounds:
Worked Example
- 1
Given
Four phenol derivatives with different para-substituents: –NO₂ (strong EWG, –I and –M), –Cl (EWG, –I dominates), –H (no substituent), –CH₃ (EDG, +I).
- 2
Required
Decreasing order of acid strength (lowest pKa first).
- 3
Concept
Acid strength of substituted phenols depends on the stability of the corresponding phenoxide ion. Electron-withdrawing groups (EWGs) stabilise phenoxide by dispersing the negative charge → increase acidity. Electron-donating groups (EDGs) destabilise phenoxide → decrease acidity. (NCERT Class 12 Chemistry Chapter 7, Part 2, page 12.)
- 4
Formula
No arithmetic formula required. Apply the substituent-effect rule: EWG → lower pKa; EDG → higher pKa. Reference pKa values: phenol ≈ 10.0.
- 5
Substitution / classification
- –NO₂: strong EWG (–I and –M) → strongly stabilises phenoxide → most acidic - –Cl: moderate EWG (–I dominates over weak +M) → moderately stabilises phenoxide - –H: reference compound - –CH₃: weak EDG (+I, hyperconjugation) → slightly destabilises phenoxide → least acidic
- 6
Ranking
Decreasing acid strength: p-nitrophenol > p-chlorophenol > phenol > p-methylphenol. Approximate pKa values: 7.15 < 9.4 < 10.0 < 10.3.
- 7
Final answer
**(a) > (d) > (b) > (c)** — p-nitrophenol > p-chlorophenol > phenol > p-methylphenol.
- 8
Common trap
Confusing the +M (resonance-donating) effect of –Cl with its –I (inductive-withdrawing) effect. In the para position, the –I effect of chlorine dominates over the weak +M, making p-chlorophenol MORE acidic than phenol. Students who focus only on resonance donation may incorrectly place p-chlorophenol as less acidic than phenol.
- 9
Similar NEET-style question
Arrange in order of increasing acid strength: 2,4,6-trinitrophenol, m-nitrophenol, o-cresol, phenol. (*Answer: o-cresol < phenol < m-nitrophenol < 2,4,6-trinitrophenol.*) ---
Before solving, remember these
Formulas
pKa of carboxylic acid
Stronger acid than phenol due to more effective resonance over two equivalent oxygens. EWG substituents (Cl, NO2) increase acidity.
| Symbol | Quantity | SI Unit |
|---|---|---|
| pKa | -log Ka | - |
Valid when
- Aqueous solution
- α-substituent effects strongest
pKa of phenol vs aliphatic alcohol
Phenols ~10⁶× more acidic than aliphatic alcohols due to resonance stabilisation of phenoxide ion. Electron-withdrawing substituents lower pKa further.
| Symbol | Quantity | SI Unit |
|---|---|---|
| pKa | -log Ka | - |
Valid when
- Aqueous solution
- Substituent effects shift values
Exam Traps & Common Mistakes
These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.
Category: Organic Reaction Conditions
1° alcohol: PCC/PDC → aldehyde (stops). KMnO4/K2Cr2O7 in acidic → carboxylic acid (continues). 2° alcohol: any oxidiser → ketone. 3° alcohol: not oxidised by ordinary reagents.
When it triggers
Question gives 1° alcohol oxidation with specified reagent.
How to avoid
PCC, PDC, Swern, DMP: mild → stop at aldehyde. KMnO4, K2Cr2O7, CrO3, jones: strong → carboxylic acid. Reagent choice matches desired product.
Root cause: concept gap
Correction
Aldehydes more reactive: less steric hindrance, less +I from one R group. Order: HCHO > RCHO > R₂CO.
Root cause: concept gap
Correction
Iodoform test ONLY positive for: methyl ketones (CH₃-CO-R), ethanol, secondary alcohols of form CH₃-CH(OH)-R, ethanal.
Past Year Questions
20 questions from NEET 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys.
Identify the suitable reagent for the following conversion.
The correct order of decreasing acidity of the following aliphatic acids is
Identify the correct reagents that would bring about the following transformation.
In which of the following equilibria, K and K are NOT equal? p c
Taking stability as the factor, which one of the following represents correct relationship?
The right option for the statement "Tyndall effect is exhibited by", is :
Which of the following reactions is the metal displacement reaction? Choose the right option. → ↑
How NEET usually asks this
Recurring question shapes from past papers. Each pattern shows why wrong options look tempting.
Predict product of nucleophilic addition to aldehyde/ketone. Aldehydes more reactive than ketones.
Common distractors
inverts aldehyde ketone reactivity
Believes ketones more reactive
Identify which compounds give iodoform test. Methyl ketones, ethanal, ethanol, secondary alcohols of form CH3-CH(OH)-R.
Common distractors
includes non methyl ketones
Treats all ketones as positive
Predict acidity ordering of substituted phenols, or product of nitration/halogenation.
Common distractors
ignores resonance vs induction balance
Uses inductive only without considering resonance
Test yourself on this topic with real past-paper questions:
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