Alcohols, Phenols, Ethers and Carbonyl Compounds

Easy Recall (3)Direct Application (3)Concept Trap (1)Calculation (1)

Alcohols Primary Secondary Tertiary

8 MCQs1 PYQsWorked example

Direct Application (3)Easy Recall (3)Calculation (1)Concept Trap (1)

Alpha Hydrogen Aldol

8 MCQs2 PYQsWorked example

Easy Recall (3)Direct Application (3)Concept Trap (1)Calculation (1)

Cannizzaro

Easy Recall (3)Calculation (1)Direct Application (3)Concept Trap (1)

Carbonyl Nucleophilic Addition

8 MCQs2 PYQsWorked example

Easy Recall (3)Direct Application (3)Concept Trap (1)Calculation (1)

Carboxylic Acidic Strength

8 MCQs1 PYQs3 revision cardsWorked example

Easy Recall (3)Direct Application (3)Concept Trap (1)Calculation (1)

Ethers Structure

8 MCQs1 PYQsWorked example

Easy Recall (3)Direct Application (3)Concept Trap (2)

Haloform

8 MCQs1 PYQsWorked example

Easy Recall (3)Direct Application (3)Concept Trap (1)Calculation (1)

Oxidation Reduction Carbonyl

8 MCQs8 PYQsWorked example

Easy Recall (3)Direct Application (3)Concept Trap (1)Calculation (1)

Phenol Acidic Nature

8 MCQs1 PYQs3 revision cardsWorked example

Easy Recall (3)Direct Application (3)Concept Trap (1)Calculation (1)

Phenol Electrophilic Substitution

Easy Recall (3)Direct Application (3)Concept Trap (1)Calculation (1)

Reimer Tiemann

Easy Recall (3)Direct Application (3)Concept Trap (2)

Past-paper questions from this unit

23 questions from NEET 2020, 2021, 2022, 2024, 2025, 2026. Answers verified against NTA official keys.

By year in our set: 2020 (4) · 2021 (4) · 2022 (5) · 2024 (3) · 2025 (2) · 2026 (5)

Lesson: Haloform

NEET 2026

For the following reaction sequence, choose the correct option: benzene, treated with (i) CH₃COCl and AlCl₃, then (ii) NaOCl, gives P + Q.

1If P is the sodium salt of a carboxylic acid, Q is a primary alcohol.

2P and Q are aromatic compounds.

3If P gives a carboxylic acid on acidification, Q gives a poisonous gas on exposure to air and light.

4Both P and Q are carbonyl compounds.

NTA Answer: Option 3(final)

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One of the products formed in the reaction shown in the figure is

NEET 2026

NTA Answer: Option 4(final)

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Lesson: Alpha Hydrogen Aldol

NEET 2026

The compound that CANNOT be obtained from the aldol condensation reaction shown in the figure (2,2-dimethylcyclopentan-1-one with PhCHO, NaOH, Δ), is

NTA Answer: Option 1(final)

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Consider the following reaction, and choose the correct option. Toluene (C₆H₅CH₃) treated with (i) CrO₂Cl₂ in CS₂ and then (ii) H₃O⁺ gives P.

NEET 2026

1On treating compound P with saturated NaHCO₃ solution, brisk effervescence is observed.

2Compound P can be prepared by treating benzene with anhydrous AlCl₃ and CH₃COCl.

3On treatment with bromine water, compound P gives a white precipitate.

4Compound P is obtained by the hydrogenation of benzoyl chloride with Pd on BaSO₄.

NTA Answer: Option 4(final)

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Lesson: Carbonyl Nucleophilic Addition

NEET 2026

Arrange the following compounds in the increasing order of polarity. A. CH₃CH₂OCH₂CH₃, B. CH₃CH₂OH, C. CH₃COCH₃, D. CH₃COOH. Choose the correct answer from the options given below.

1A < B < C < D

2C < A < D < B

3C < A < B < D

4A < C < B < D

NTA Answer: Option 4(final)

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Identify the suitable reagent for the following conversion.

NEET 2025

1H2/Pd-BaSO4

2(i) LiAlH4, (ii) H+ /H2O

3(i) AlH(iBu)2, (ii) H2O

4(i) NaBH4, (ii) H+ /H2O

NTA Answer: Option 3(final)

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Lesson: Carboxylic Acidic Strength

NEET 2025

The correct order of decreasing acidity of the following aliphatic acids is

1HCOOH > (CH3)3CCOOH > (CH3)2CHCOOH > CH3COOH

2(CH3)3CCOOH > (CH3)2CHCOOH > CH3COOH > HCOOH

3CH3COOH > (CH3)2CHCOOH > (CH3)3CCOOH > HCOOH

4HCOOH > CH3COOH > (CH3)2CHCOOH > (CH3)3CCOOH

NTA Answer: Option 4(final)

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Identify the correct reagents that would bring about the following transformation.

NEET 2024Revised key

1(i) H₂O/H⁺ (ii) CrO₃

2(i) BH₃ (ii) H₂O₂/OH⁻ (iii) PCC

3(i) BH₃ (ii) H₂O₂/OH⁻ (iii) alk.KMnO₄ (iv) H₃O⁺

4(i) H₂O/H⁺ (ii) PCC

NTA Answer: Option 2(revised_final)

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NEET 2024Revised key

Fehling’s solution ‘A’ is

1aqueous copper sulphate

2alkaline copper sulphate

3alkaline solution of sodium potassium tartrate (Rochelle’s salt)

4aqueous sodium citrate

NTA Answer: Option 1(revised_final)

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Match List I with List II. List I (Reaction) List II (Reagents/Condition) Choose the correct answer from the options given below:

NEET 2024Revised key

1A-IV, B-I, C-III, D-II

2A-III, B-I, C-II, D-IV

3A-IV, B-I, C-II, D-III

4A-I, B-IV, C-II, D-III

NTA Answer: Option 3(revised_final)

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+ dry HO3 RMgX+CO Y RCOOH 2 ⎯⎯⎯→ ⎯⎯⎯→ ether What is Y in the above reaction?

NEET 2022

1(RCOO)2Mg

2RCOO–Mg+X

3R3CO–Mg+X

4RCOO–X+

NTA Answer: Option 2(final)

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Lesson: Phenol Acidic Nature

NEET 2022

Given below are two statements Statement I: The acidic strength of monosubstituted nitrophenol is higher than phenol because of electron withdrawing nitro group. Statement II: o-nitrophenol, m-nitrophenol and p-nitrophenol will have same acidic strength as they have one nitro group attached to the phenolic ring. In the light of the above statements, choose the most appropriate answer from the options given below:

1Statement I is incorrect but Statement II is correct.

2Both Statement I and Statement II are correct.

3Both Statement I and Statement II are incorrect.

4Statement I is correct but Statement II is incorrect.

NTA Answer: Option 4(final)

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Match List-I with List-II. List – I List – II (Products formed) (Reaction of carbonyl compound with) (a) Cyanohydrin (i) NH2OH (b) Acetal (ii) RNH2 (c) Schiff's base (iii) alcohol (d) Oxime (iv) HCN Choose the correct answer from the options given below

NEET 2022

1(a) – (iv), (b) – (iii), (c) – (ii), (d) – (i)

2(a) – (iii), (b) – (iv), (c) – (ii), (d) – (i)

3(a) – (ii), (b) – (iii), (c) – (iv), (d) – (i)

4(a) – (i), (b) – (iii), (c) – (ii), (d) – (iv)

NTA Answer: Option 1(final)

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Lesson: Carbonyl Nucleophilic Addition

NEET 2022

Given below are two statements : Statement I : The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions. Statement II : The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding. In the light of the above statements, choose the most appropriate answer from the given below

1Statement I is incorrect but Statement II is correct

2Both Statement I and Statement II are correct

3Both Statement I and Statement II are incorrect

4Statement I is correct but Statement II is incorrect

NTA Answer: Option 2(final)

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Lesson: Alcohols Primary Secondary Tertiary

NEET 2022

Given below are two statements: Statement I: In Lucas test, primary, secondary and tertiary alcohols are distinguished on the basis of their reactivity with conc. HCl + ZnCl2, known as Lucas Reagent. Statement II: Primary alcohols are most reactive and immediately produce turbidity at room temperature on reaction with Lucas Reagent. In the light of the above statements, choose the most appropriate answer from the options given below:

1Statement I is incorrect but Statement II is correct

2Both Statement I and Statement II are correct

3Both Statement I and Statement II are incorrect

4Statement I is correct but Statement II is incorrect

NTA Answer: Option 4(final)

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What is the IUPAC name of the organic compound formed in the following chemical reaction? Acetone ⎯⎯(i)C⎯2H⎯5Mg⎯Br,⎯dry⎯Eth⎯er⎯→Product (ii)H2O,H+

NEET 2021

12-methylbutan-2-ol

22-methylpropan-2-ol

3pentan-2-ol

4pentan-3-ol

NTA Answer: Option 1(final)

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The product formed in the following chemical reaction is:

NEET 2021

NTA Answer: Option 1(final)

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The intermediate compound 'X' in the following chemical reaction is: C₆H₅–CH₃ (toluene) + CrO₂Cl₂ —[CS₂]→ X —[H₃O⁺]→ C₆H₅–CHO (benzaldehyde)

NEET 2021

1C₆H₅–CH(Cl)H

2C₆H₅–CH(OCrOHCl₂)₂

3C₆H₅–CH(OCOCH₃)₂

4C₆H₅–CHCl₂

NTA Answer: Option 2(final)

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Match List-I with List-II List-I List-II (a) CO, HCI Anhyd. AlCl /3 CuCl (i) Hell-Volhard-Zelinsky reaction (b) R — C — CH +3 O NaOX (ii) Gattermann-Koch reaction (c) R — CH — OH 2 +R COOH ′ Conc. H SO24 (iii) Haloform reaction (d) R — CH2COOH (ii) H O2 ( ) X /Red P I 2 I (iv) Esterification Choose the correct answer from the options given below.

NEET 2021

1(a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

2(a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)

3(a) - (iii), (b) - (ii), (c) - (i), (d) - (iv)

4(a) - (i), (b) - (iv), (c) - (iii), (d) - (ii)

NTA Answer: Option 1(final)

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Reaction between acetone and methylmagnesium chloride followed by hydrolysis will give :

NEET 2020

1Isobutyl alcohol

2Isopropyl alcohol

3Sec. butyl alcohol

4Tert. butyl alcohol

NTA Answer: Option 4(final)

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Identify compound X in the following sequence of reactions : C6H5CH3 (toluene) —[Cl2/hν]→ X —[H2O, 373 K]→ C6H5CHO (benzaldehyde)

NEET 2020

1C6H5CCl3

2C6H5Cl

3C6H5CH2Cl

4C6H5CHCl2

NTA Answer: Option 4(final)

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Lesson: Alpha Hydrogen Aldol

NEET 2020

Reaction between benzaldehyde and acetophenone in presence of dilute NaOH is known as :

1Cross Aldol condensation

2Aldol condensation

3Cannizzaro’s reaction

4Cross Cannizzaro’s reaction

NTA Answer: Option 1(final)

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Lesson: Ethers Structure

NEET 2020

Anisole on cleavage with HI gives :

1C6H5I + C2H5OH

2C6H5OH + CH3I

3C6H5I + CH3OH

4C6H5OH + C2H5I

NTA Answer: Option 2(final)

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Exam traps and common mistakes in this unit

Trap

Oxidation product depends on reagent strength

Category: Organic Reaction Conditions

1° alcohol: PCC/PDC → aldehyde (stops). KMnO4/K2Cr2O7 in acidic → carboxylic acid (continues). 2° alcohol: any oxidiser → ketone. 3° alcohol: not oxidised by ordinary reagents.

When it triggers

Question gives 1° alcohol oxidation with specified reagent.

How to avoid

PCC, PDC, Swern, DMP: mild → stop at aldehyde. KMnO4, K2Cr2O7, CrO3, jones: strong → carboxylic acid. Reagent choice matches desired product.

Lesson: Carbonyl Nucleophilic Addition

Mistake

Believes ketones more reactive than aldehydes toward nucleophilic addition.

Root cause: concept gap

Correction

Aldehydes more reactive: less steric hindrance, less +I from one R group. Order: HCHO > RCHO > R₂CO.

Lesson: Haloform

Mistake

Marks non-methyl ketones as positive for iodoform test.

Root cause: concept gap

Correction

Iodoform test ONLY positive for: methyl ketones (CH₃-CO-R), ethanol, secondary alcohols of form CH₃-CH(OH)-R, ethanal.

Formulas in this unit

Lesson: Carboxylic Acidic Strength

pKa of carboxylic acid

pK_{a}^{RCOOH} \approx 4 - 5

Stronger acid than phenol due to more effective resonance over two equivalent oxygens. EWG substituents (Cl, NO2) increase acidity.

Symbol	Quantity	SI Unit
pKa	-log Ka	-

Valid when

Aqueous solution
α-substituent effects strongest

Lesson: Phenol Acidic Nature

pKa of phenol vs aliphatic alcohol

pK_{a}^{phenol} \approx 10

Phenols ~10⁶× more acidic than aliphatic alcohols due to resonance stabilisation of phenoxide ion. Electron-withdrawing substituents lower pKa further.

Symbol	Quantity	SI Unit
pKa	-log Ka	-

Valid when

Aqueous solution
Substituent effects shift values

NEET question patterns in this unit