Answer: C. 1 kg/m³ = 1 kg · m⁻³. Converting kg → g gives a factor of 10³ (1 kg = 10³ g), and converting m⁻³ → cm⁻³ gives a factor of 10⁻⁶ (since 1 m = 10² cm, m⁻³ = (10² cm)⁻³ = 10⁻⁶ cm⁻³). Multiplying the two conversion factors: 10³ × 10⁻⁶ = 10⁻³. So 1 kg/m³ = 10⁻³ g/cm³ — consistent with water's density, 1000 kg/m³ = 1 g/cm³ (NCERT Class 11 Physics, Chapter 1, pages 1–2).
Why A is wrong: Forgetting to convert kg→g (treating 1 kg as 1 g) while correctly cubing the length factor (10⁻⁶) gives only 10⁻⁶ g/cm³ — the mass conversion factor (10³) is missing.
Why B is wrong: Converting the length factor only once instead of cubing it (10³ × 10⁻² = 10, treating m³ → cm³ as a single linear step of 10² rather than (10²)³ = 10⁶) gives 10 g/cm³ — this drops two of the three length-conversion factors.
Why D is wrong: Inverting the mass conversion (using 10⁻³ instead of 10³ for kg→g) while correctly cubing the length factor gives 10⁻³ × 10⁻⁶ = 10⁻⁹ g/cm³ — the mass factor is applied backwards.