Significant Figures

8 MCQs2 revision cards9-step worked example
Source: NCERT Units and MeasurementsPYQ coverage: NEET 2020, 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

The trap that costs marks on significant figures is deceptively simple: aspirants apply the wrong rounding rule to the wrong arithmetic operation. Multiplication and division require rounding to the fewest significant figures among the inputs. Addition and subtraction require rounding to the fewest decimal places. Swapping these two rules is a high-frequency mistake on NEET (NCERT Class 11 Physics Chapter 1, pages 4–5).

What are significant figures? Every measured quantity carries uncertainty. Significant figures are the digits in a measurement that are known reliably plus the first uncertain digit (NCERT Class 11 Physics Chapter 1, page 3). They encode the precision of the instrument that produced the number.

Counting rules (NCERT conventions):

  1. All non-zero digits are significant: 1234 has 4 sig figs.
  2. Zeros between non-zero digits are significant: 1007 has 4 sig figs.
  3. Leading zeros are never significant: 0.0034 has 2 sig figs.
  4. Trailing zeros after a decimal point are significant: 2.500 has 4 sig figs.
  5. Trailing zeros in a whole number without a decimal point are ambiguous: 2300 could be 2, 3, or 4 sig figs. Use scientific notation to remove ambiguity (e.g. 2.30 × 10³ = 3 sig figs).

The two rounding rules:

  • Multiplication / division → result has the fewest significant figures of any input.
  • Addition / subtraction → result has the fewest decimal places of any input.

Watch out: When a subtraction problem like 9.99 m − 0.0099 m appears, the fewest decimal places is 2 (from 9.99). The answer is 9.98 m — not 9.9801 m (keeping all digits) and not 1.0 × 10¹ m (wrongly applying the sig-fig rule). This is the exact trap NEET has tested.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

How many significant figures are in the measurement 0.00470 kg?

MCQ 2Easy RecallPractice

The number 8.0 × 10⁴ has how many significant figures?

MCQ 3Easy RecallPractice

Which of the following numbers has exactly 4 significant figures?

MCQ 4Direct ApplicationPYQ Pattern

A rectangular plate has length 4.234 m and breadth 1.05 m. The area of the plate, expressed with the correct number of significant figures, is:

MCQ 5Direct ApplicationPYQ Pattern

The result of 28.4 m + 2.175 m, expressed with the correct number of significant figures, is:

MCQ 6Direct ApplicationPYQ Pattern

A student measures two lengths as 12.50 m and 2.1 m and subtracts them: 12.50 − 2.1 = 10.40. The correctly rounded result is:

MCQ 7CalculationPractice

Two rods are measured as 5.2 cm and 3.34 cm. Their difference is calculated as 5.2 − 3.34 = 1.86 cm. A student reports the answer as 1.9 cm. Another student reports it as 2 cm. Which student is correct and why?

MCQ 8CalculationPYQ Pattern

A student computes the area of a square sheet with side 2.1 cm as 2.1 × 2.1 = 4.41 cm². She then subtracts the area of a small hole, 0.065 cm², from the sheet area. What is the correct final answer?

Quick recall before you leave

Worked Example

  1. 1

    Given

    Two measured lengths: L₁ = 9.99 m (2 decimal places, 3 sig figs) and L₂ = 0.0099 m (4 decimal places, 2 sig figs).

  2. 2

    Required

    Find L₁ − L₂ expressed with the correct number of significant figures.

  3. 3

    Concept

    When measured quantities are subtracted, the result must be rounded to the fewest decimal places among the inputs — not the fewest significant figures. This is the addition/subtraction rounding convention (NCERT Class 11 Physics Chapter 1, page 5).

  4. 4

    Formula

    For Z = A ± B: round Z to the fewest decimal places among A and B.

  5. 5

    Substitution

    Raw subtraction: 9.99 − 0.0099 = 9.9801 m. Decimal places: L₁ has 2 decimal places; L₂ has 4 decimal places. The fewest is 2.

  6. 6

    Calculation

    9.9801 rounded to 2 decimal places → 9.98 m. No exact constants are involved in this problem — both numbers are measured quantities with inherent uncertainty.

  7. 7

    Final answer

    **9.98 m** (3 significant figures, 2 decimal places). Note: if we had wrongly applied the multiplication/division rule (fewest sig figs = 2, from 0.0099), we would get 1.0 × 10¹ m — a drastically different and incorrect answer.

  8. 8

    Common trap

    The most common error is applying the "fewest significant figures" rule to this subtraction. L₂ = 0.0099 has only 2 significant figures, which tempts students to round the answer to 2 sig figs (giving 10 m or 1.0 × 10¹ m). But subtraction demands the decimal-place rule, not the sig-fig rule.

  9. 9

    Similar NEET-style question

    Two masses are measured: m₁ = 25.0 g and m₂ = 0.034 g. Express (m₁ − m₂) with the correct significant figures. *Answer: 25.0 − 0.034 = 24.966 → fewest decimal places is 1 (from 25.0) → 25.0 g.* ---

Before solving, remember these

All the reliably-known digits in a measured quantity, plus the first uncertain (estimated) digit, are called significant figures. Significant figures indicate the precision of measurement.

-- NCERT Class 11 Physics, Ch. 1, p. 3

Rules: (i) all non-zero digits are significant; (ii) zeros between non-zero digits are significant; (iii) leading zeros (before the first non-zero digit) in a decimal number are NOT significant; (iv) trailing zeros in a number without a decimal point are NOT significant; (v) trailing zeros after a decimal point ARE significant. Exact numbers (counted, definitions) have unlimited significant figures.

-- NCERT Class 11 Physics, Ch. 1, p. 4

Multiplication/division: result has the same number of significant figures as the input with the fewest significant figures. Addition/subtraction: result has the same number of decimal places as the input with the fewest decimal places.

-- NCERT Class 11 Physics, Ch. 1, p. 5

A cube has side measured as 7.203 m (4 sig figs). Surface area 6 × 7.203² = 311.299254 m² rounded to 311.3 m² (4 sig figs). Volume 7.203³ = 373.714754 m³ rounded to 373.7 m³ (4 sig figs).

-- NCERT Class 11 Physics, Ch. 1, p. 6

Formulas

3 formulas — click to collapse

Error in a power expression

The maximum relative error in a power expression is the sum of the absolute exponents weighted by the relative errors of the bases. Negative exponents (divisions) still take the |.| value because we want the worst-case error.

SymbolQuantitySI Unit
ZResult(combined)
p, q, rExponents (signed)(dimensionless)
A, B, CMeasured quantities(measured)

Valid when

  • Use absolute values of exponents — signs do not cancel in worst-case error analysis
  • Independent measurements assumption

Combination of errors — product or quotient

When two measured quantities are multiplied or divided, the maximum RELATIVE errors add. The absolute error in the result is then Delta_Z = Z * (relative-error sum).

SymbolQuantitySI Unit
ZResult of product/quotient(combined unit)
AFirst measured quantity(measured)
BSecond measured quantity(measured)
Delta_A/ARelative error in A(dimensionless)
Delta_B/BRelative error in B(dimensionless)

Valid when

  • A and B are independent measurements
  • Errors are quoted as maximum absolute uncertainties (worst-case)
  • For powers (Z = A^p * B^q), the rule generalises: Delta_Z/Z = |p|*Delta_A/A + |q|*Delta_B/B

Do NOT use when

  • Quantities are added or subtracted (use absolute-error rule instead)

Combination of errors — sum or difference

When two quantities are added or subtracted, the maximum absolute errors of the inputs simply add to give the maximum absolute error of the output. The relative error is NOT what adds in this case.

SymbolQuantitySI Unit
ZResult of sum/difference(same as A,B)
AFirst measured quantity(measured)
BSecond measured quantity(measured)
Delta_ZMaximum absolute error in Z(same as A,B)
Delta_AMaximum absolute error in A(same as A)
Delta_BMaximum absolute error in B(same as B)

Valid when

  • A and B are independent measurements (no correlated errors)
  • Errors are quoted as maximum absolute uncertainties (not standard deviations)
  • Use this rule for ADDITION or SUBTRACTION only — NOT for product/quotient

Do NOT use when

  • Quantities are multiplied or divided (use relative-error rule instead)
  • Errors are statistical (standard deviations) — quadrature-sum rule applies

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

9 items — click to collapse

Category: Similar Terms

Student gets the time exponent wrong by 1 (e.g. T⁻¹ vs T⁻²) when manipulating dimensional formulas.

When it triggers

Question asks for dimensions of a derived combination (e.g. E/G, F = αt² + βt) where time exponent matters.

How to avoid

Write each base quantity's dimensional formula explicitly, then combine. Common errors: dividing forces forgets sub of T exponents; energy/length includes implicit time. Always check final units against expected SI.

Category: Similar Terms

Student sums relative errors of all measured quantities without weighting by the exponent. For ρ = m/(πr²L), the relative error contribution of r is 2 × Δr/r, NOT Δr/r — the exponent of r in the formula carries through as a multiplicative factor.

When it triggers

Question gives a derived quantity formula with mixed-power dependencies; asks for the max relative error. Distractors omit the power factor.

How to avoid

Always write the full general rule: for Z = A^p B^q C^r, ΔZ/Z = |p|·ΔA/A + |q|·ΔB/B + |r|·ΔC/C. Identify the powers (1, 2, 3, ½) before adding.

Category: Similar Terms

Student conflates random errors (statistical, unpredictable, reduced by averaging) with instrumental errors (consistent bias from the apparatus) or with systematic errors (consistent bias from the method). Each has a distinct definition and different mitigation.

When it triggers

Question describes an error source and asks for its taxonomic category. Distractors include cognate categories.

How to avoid

Memorise the 5-category taxonomy: PERSONAL (observer-side), INSTRUMENTAL (apparatus calibration), LEAST-COUNT (instrument resolution floor), RANDOM (statistical, reduced by repeated trials), SYSTEMATIC (method-level bias, NOT reduced by averaging).

Category: Similar Terms

Student swaps which is the input vs the output: least count = pitch / N (where N is the number of circular-scale divisions). Distractors offer the ratio inverted or the wrong unit.

When it triggers

Question gives one of (pitch, N, least count) and asks for another; distractors offer the inverted ratio or off-by-factor-of-10.

How to avoid

Anchor on the definition: least count is the SMALLEST measurement the instrument can resolve. It is always SMALLER than the pitch. So pitch = LC × N (and not LC = pitch × N).

Category: Similar Terms

Student applies the 'fewest significant figures' rule (which governs multiplication and division) to a sum or difference. Subtraction of two measured numbers must instead reflect the FEWEST decimal places.

When it triggers

Question involves addition/subtraction of measured numbers with very different magnitudes or decimal-place counts (e.g. 9.99 - 0.0099). Distractors offer answers rounded by sig-fig rule rather than decimal-place rule.

How to avoid

Memorise: multiplication/division → fewest SIGNIFICANT FIGURES; addition/subtraction → fewest DECIMAL PLACES. Always identify which arithmetic operation is being performed before applying any rule.

Category: Similar Terms

Student treats radian/steradian as having dimensions because they have unit names.

When it triggers

Question asks about dimensions of plane angle, solid angle, or comparison.

How to avoid

Plane angle (radian) and solid angle (steradian) are DIMENSIONLESS — they're ratios (arc/radius for radian; surface-area/r² for steradian). They have unit NAMES for clarity but no dimensions.

Category: Similar Terms

Confusing whether N or N+1 is the smaller count when (N+1) divisions of vernier match N divisions of main scale.

When it triggers

Question gives '(N+1) divisions of vernier coincide with N divisions of main' or similar phrasing.

How to avoid

Always interpret carefully: N+1 vernier divisions span the SAME LENGTH as N main divisions. So 1 VSD = (N/(N+1)) MSD; vernier constant = 1 MSD - 1 VSD = 1 MSD / (N+1). Result smaller than 1 MSD.

Root cause: formula misuse

Correction

Use Delta_Z = Delta_A + Delta_B for sums/differences (absolute errors add). Use Delta_Z/Z = Delta_A/A + Delta_B/B for products/quotients (relative errors add). They are NOT interchangeable — the rule is dictated by whether the operation is additive or multiplicative.

Wrong option pattern

Distractor option uses the wrong rule (e.g. quotes a small relative error for a sum where absolute errors should add).

Past Year Questions

13 questions from NEET 2020, 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys. — click to collapse
NEET 2025

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at x = 0.1 cm when the jaws of Vernier callipers are closed. If the main scale reading for the diameter is M = 5 cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction, is

15.00 cm
25.18 cm
35.08 cm
44.98 cm
NTA Answer: Option 4(final)
NEET 2022

Plane angle and solid angle have

1Both units and dimensions
2Units but no dimensions
3Dimensions but no units
4No units and no dimensions
NTA Answer: Option 2(final)
NEET 2022

Match List-I with List-II List-I List-II (a) Gravitational constant (G) (i) [L2T–2] (b) Gravitational potential energy (ii) [M–1L3T–2] (c) Gravitational potential (iii) [LT–2] (d) Gravitational intensity (iv) [ML2T–2] Choose the correct answer from the options given below

1(a) - (iv), (b) - (ii), (c) - (i), (d) - (iii)
2(a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
3(a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
4(a) - (ii), (b) - (iv), (c) - (iii), (d) - (i)
NTA Answer: Option 3(final)

How NEET usually asks this

9 recurring patterns from past papers — click to collapse

Density ρ = m/V where V depends on measured dimensions raised to powers (e.g. cylindrical wire V = πr²L). Apply combination of errors: Δρ/ρ = Δm/m + 2 Δr/r + ΔL/L (radius gets factor of 2 from r²). Common shape: wire with mass, radius, length each ± uncertainty; find max % error in density. Distractors test (i) forgetting the 2× on radius, (ii) using absolute instead of relative errors.

Multi StepMedium

Common distractors

forgets power of two on radius

Default to summing all relative errors with weight 1

Subtraction of two measured quantities with very different decimal places; the answer must reflect the FEWEST decimal places (not the fewest significant figures). Common shape: 9.99 m - 0.0099 m, or similar. Distractors test (i) using sig-fig rule from multiplication/division, (ii) keeping all digits unchanged, (iii) over-rounding to 1-2 sig figs.

Direct ApplicationEasy

Common distractors

applies mult rule to subtraction

Default to 'fewest sig figs' without distinguishing subtraction's decimal-places rule

Sources

NCERT refs: Class 11 Physics Chapter 1, p.3

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