Avogadro Number

8 MCQs3 revision cards9-step worked example
Source: NCERT Kinetic TheoryPYQ coverage: NEET 2020, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

Avogadro's number, Nₐ = 6.022 × 10²³ mol⁻¹, is the bridge between microscopic molecular quantities and macroscopic molar quantities. It tells you how many molecules (or atoms, ions, or particles) sit in exactly one mole of any substance.

Where it comes from in NCERT: Class 11 Physics Chapter 13 (Kinetic Theory), page 3 states this as a fundamental physical constant linking the gas constant R and the Boltzmann constant k through R = Nₐk. This relation is how the ideal gas law PV = nRT converts to PV = NkT, where N is the actual number of molecules.

The key relation to internalise:

Nₐ = R / k = 8.314 J mol⁻¹ K⁻¹ / 1.381 × 10⁻²³ J K⁻¹ ≈ 6.022 × 10²³ mol⁻¹

This means:

  • n (moles) × Nₐ = N (number of molecules)
  • Any per-mole quantity divided by Nₐ gives the per-molecule quantity (and vice versa)

Common confusions in NEET context:

  1. R vs k mix-up. R is per mole; k is per molecule. When a problem gives molecular-level data, use k. When it gives molar data, use R. Swapping them changes the answer by a factor of ~10²³.

  2. Forgetting the mole–molecule conversion. Problems sometimes give mass and ask for the number of molecules. You must go mass → moles (using molar mass M) → molecules (multiplying by Nₐ). Skipping the mole step is a direct route to a wrong option.

  3. Confusing Nₐ with N. Nₐ is a fixed constant. N is the actual number of molecules in a given sample, which depends on how many moles you have: N = nNₐ.

Watch-out: When a NEET stem says "number of molecules in 2 moles," the answer is 2 × 6.022 × 10²³ = 1.204 × 10²⁴ — not 6.022 × 10²³. Read whether the problem asks per mole or for the given sample.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Avogadro's number (Nₐ) represents:

MCQ 2Easy RecallPractice

The Boltzmann constant k is related to Avogadro's number Nₐ and the gas constant R by:

MCQ 3Easy RecallPractice

The numerical value of Avogadro's number is approximately:

MCQ 4Direct ApplicationPractice

How many molecules are present in 3.0 moles of an ideal gas?

MCQ 5Direct ApplicationPractice

The gas constant R = 8.314 J mol⁻¹ K⁻¹ and Avogadro's number Nₐ = 6.022 × 10²³ mol⁻¹. The Boltzmann constant k is:

MCQ 6Direct ApplicationPractice

An ideal gas sample contains N = 1.204 × 10²⁴ molecules. The number of moles in the sample is:

MCQ 7CalculationPractice

A container holds n moles of an ideal gas at pressure P and temperature T. If the gas constant is R and Avogadro's number is Nₐ, which expression correctly gives the number of molecules per unit volume?

MCQ 8Concept TrapPractice

Two ideal gas samples — one containing helium (M = 4 g/mol) and the other nitrogen (M = 28 g/mol) — each have exactly one mole at the same temperature. Which statement about the number of molecules in each sample is correct?

Quick recall before you leave

Worked Example

  1. 1

    Given

    - R = 8.314 J mol⁻¹ K⁻¹ - k = 1.381 × 10⁻²³ J K⁻¹ - n = 5.0 mol

  2. 2

    Required

    (a) Avogadro's number Nₐ (b) Total molecules N in 5.0 moles

  3. 3

    Concept

    Avogadro's number bridges the molar scale (R) and the molecular scale (k). From R = Nₐk, we extract Nₐ. Then N = nNₐ converts moles to molecules.

  4. 4

    Formula

    (a) Nₐ = R / k (b) N = nNₐ

  5. 5

    Substitution

    (a) Nₐ = 8.314 / 1.381 × 10⁻²³ (b) N = 5.0 × Nₐ

  6. 6

    Calculation

    (a) Nₐ = (8.314 / 1.381) × 10²³ = 6.021 × 10²³ mol⁻¹ (Rounding: 8.314 / 1.381 = 6.0203… ≈ 6.021 to 4 significant figures, matching the precision of the given data.) (b) N = 5.0 × 6.022 × 10²³ = 3.011 × 10²⁴ Note on exact values: the factor 5.0 is a given counting quantity in this problem context and does not limit significant figures. The answer precision is governed by Nₐ (4 sig figs).

  7. 7

    Final answer

    (a) **Nₐ ≈ 6.022 × 10²³ mol⁻¹** (b) **N = 3.011 × 10²⁴ molecules**

  8. 8

    Common trap

    Confusing R and k: using k in place of R (or vice versa) changes the answer by ~10²³. If you get a Nₐ on the order of 10⁰ or 10⁴⁶, you have swapped R and k.

  9. 9

    Similar NEET-style question

    "The Boltzmann constant is 1.38 × 10⁻²³ J K⁻¹ and R = 8.31 J mol⁻¹ K⁻¹. How many molecules are present in 0.50 moles of oxygen at STP?" (Answer: N = 0.50 × (8.31/1.38 × 10⁻²³) ≈ 0.50 × 6.02 × 10²³ = 3.01 × 10²³.) ---

Before solving, remember these

N_A = 6.022 × 10²³ molecules/mol. Avogadro's law: equal volumes of gases at same T and P contain equal numbers of molecules. Universal gas constant R = N_A k.

-- NCERT, p. 3

Formulas

5 formulas — click to collapse

Average translational KE per molecule

Microscopic interpretation of temperature: T is direct measure of average translational kinetic energy.

SymbolQuantitySI Unit
kBoltzmann constantJ/K
Tabsolute temperatureK

Valid when

  • Translational degrees of freedom only
  • Ideal gas

Cv from degrees of freedom

Each quadratic DoF contributes (1/2)R to molar Cv. Mono: f=3, Cv=3R/2; di-rigid: f=5, Cv=5R/2; poly-rigid: f=6, Cv=3R.

SymbolQuantitySI Unit
Cvmolar specific heatJ/mol/K
fdegrees of freedom-
Rgas constantJ/mol/K

Valid when

  • Equipartition holds (temperature high enough)
  • Quadratic energy modes

Ideal gas equation

Fundamental equation of state of ideal gas relating pressure, volume, temperature.

SymbolQuantitySI Unit
PpressurePa
Vvolumem^3
nmolesmol
R8.314J/mol/K
Nmolecule count-
kBoltzmann 1.38e-23J/K
TtempK

Valid when

  • Gas obeys ideal gas approximation (low pressure, high temperature relative to phase transitions)

Mean free path of gas molecule

Average distance between successive molecular collisions.

SymbolQuantitySI Unit
lambdamean free pathm
nnumber density1/m^3
dmolecular diameterm

Valid when

  • Hard-sphere model
  • Equilibrium gas

RMS speed of gas molecules

Root-mean-square molecular speed; depends on T and molar mass M (or molecular mass m).

SymbolQuantitySI Unit
Rgas constantJ/mol/K
TtempK
Mmolar masskg/mol
kBoltzmannJ/K
mmolecular masskg

Valid when

  • Ideal gas
  • Maxwell-Boltzmann distribution

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

2 items — click to collapse

Category: Similar Terms

Student treats v_rms ∝ T instead of √T. Doubling T does NOT double v_rms; it multiplies by √2.

When it triggers

Question asks for new v_rms after T change.

How to avoid

v_rms = √(3RT/M). v_rms ∝ √T. To double v_rms, T must quadruple.

Past Year Questions

6 questions from NEET 2020, 2022, 2023, 2024, 2025. Answers verified against NTA official keys. — click to collapse

How NEET usually asks this

4 recurring patterns from past papers — click to collapse

Test yourself on this topic with real past-paper questions:

Practice this topic →

Free NEET study resources

Get a structured 30-day Mechanics plan and a complete formula booklet — delivered to your inbox instantly.