Heat Temperature Thermal Expansion

8 MCQs1 revision card0-step worked example
Source: NCERT Properties of Bulk MatterPYQ coverage: NEET 2020, 2021, 2022, 2023, 2024, 2025Official key: NTA-verifiedLast reviewed: May 2026

Lesson

Thermal expansion is quietly one of the most conceptually clean topics in NEET physics — and the trap is that students treat it as too simple and then misapply the coefficients.

The core idea. When a solid is heated, its atoms vibrate with larger amplitude about their mean positions. The mean interatomic separation increases because the potential-energy curve is asymmetric (steeper on the repulsive side). This produces measurable changes in length, area, and volume (NCERT Class 11 Physics, Chapter 11, page 3).

Three coefficients, one relationship. For an isotropic solid:

  • Linear: ΔL/L = α ΔT
  • Areal: ΔA/A = 2α ΔT
  • Volume: ΔV/V = β ΔT, where β = 3α

The factors 2 and 3 come from the binomial approximation (higher-order α² terms are negligible for modest ΔT). This is where NEET questions test you: they give α and ask for β, or vice versa, and a common confusion is using the wrong multiplier.

Temperature vs heat. Temperature measures the average kinetic energy of molecules — it is a state variable. Heat is the energy transferred due to a temperature difference — it is a process quantity. The distinction matters: two bodies can be at the same temperature with vastly different heat contents. NCERT defines temperature operationally via the zeroth law of thermodynamics (Chapter 11, page 2): two systems each in thermal equilibrium with a third are in thermal equilibrium with each other.

Watch-out for NEET. Questions on thermal expansion typically test whether you can (a) correctly relate α, 2α, and 3α for the three types, (b) handle the expansion of a hole or cavity (it expands as if filled — the hole gets bigger, not smaller), and (c) convert between Celsius and Kelvin temperature changes (ΔT is numerically identical in both, but students sometimes second-guess themselves). These are direct-application problems; the arithmetic is light, but the conceptual step must be precise.


Practice MCQs

Select an option to see the explanation. Wrong answers show why your choice was tempting — and name the exact trap it exploits.

MCQ 1Easy RecallPractice

Temperature is a physical quantity that measures:

MCQ 2Easy RecallPractice

The zeroth law of thermodynamics provides the basis for the concept of:

MCQ 3Easy RecallPractice

For an isotropic solid, if α is the coefficient of linear expansion, the coefficient of volume expansion β is:

MCQ 4Direct ApplicationPractice

A metal rod of length 1.00 m at 20 °C is heated to 120 °C. If the coefficient of linear expansion is α = 1.2 × 10⁻⁵ K⁻¹, the increase in length is:

MCQ 5Direct ApplicationPractice

A thin metal plate has a circular hole of diameter 2.000 cm at 25 °C. When heated to 125 °C, the diameter of the hole (α = 2.0 × 10⁻⁵ K⁻¹):

MCQ 6Direct ApplicationPractice

A metal sphere has a coefficient of linear expansion α = 1.5 × 10⁻⁵ K⁻¹. If its temperature increases by 200 K, the percentage increase in its volume is approximately:

MCQ 7Concept TrapPractice

A bimetallic strip is made of brass (higher α) bonded to iron (lower α). When heated uniformly, the strip bends such that:

MCQ 8CalculationPractice

A steel rail is 10.0 m long at 15 °C. The rail is laid without expansion gaps on a day when the temperature is 15 °C. If the temperature rises to 45 °C (α_steel = 1.2 × 10⁻⁵ K⁻¹, Y_steel = 2.0 × 10¹¹ Pa, cross-sectional area = 4.0 × 10⁻³ m²), the compressive force developed in the rail if it is prevented from expanding is:

Quick recall before you leave

Before solving, remember these

Heat (Q) is energy in transfer due to a temperature difference. Temperature is a measure of the average kinetic energy of molecules. Heat flows spontaneously from higher T to lower T.

-- NCERT, p. 2

Linear: ΔL/L = α ΔT. Area: ΔA/A = 2α ΔT. Volume: ΔV/V = β ΔT, where β = 3α (isotropic). α is the coefficient of linear expansion (units: 1/K).

-- NCERT, p. 3

Formulas

12 formulas — click to collapse

Bernoulli's equation

Conservation of energy along a streamline of incompressible non-viscous flow.

SymbolQuantitySI Unit
PpressurePa
rhodensitykg/m^3
vspeedm/s
ggravitym/s^2
hheightm

Valid when

  • Steady, non-viscous, incompressible flow
  • Along a single streamline
  • No work added/removed

Bulk modulus

Resistance of a material to uniform compression. Inverse: compressibility.

SymbolQuantitySI Unit
Kbulk modulusPa
Vvolumem^3
PpressurePa

Valid when

  • Isotropic compression
  • Within elastic regime

Capillary rise/depression

Height a liquid rises (or falls) in a capillary tube. cos(theta) > 0: rises (wetting); < 0: depresses.

SymbolQuantitySI Unit
hcapillary heightm
Tsurface tensionN/m
thetacontact anglerad
rhodensitykg/m^3
rtube radiusm

Valid when

  • Narrow tube (capillary regime)
  • Constant theta

Pressure in static fluid

Pressure at depth h below free surface of fluid of density rho.

SymbolQuantitySI Unit
Ptotal pressurePa
P0atmospheric/surface pressurePa
rhodensitykg/m^3
hdepthm

Valid when

  • Static fluid (no flow)
  • Constant g
  • Constant rho (incompressible)

Latent heat

Heat absorbed/released during phase change at constant T. L_fusion or L_vaporisation.

SymbolQuantitySI Unit
QheatJ
mmasskg
Llatent heatJ/kg

Valid when

  • Phase transition (constant T during)
  • All mass m undergoes the transition

Specific heat / heat capacity

Heat required to raise mass m by temperature Delta_T. Specific heat c is material property.

SymbolQuantitySI Unit
QheatJ
mmasskg
cspecific heatJ/kg/K
Delta_Ttemp changeK

Valid when

  • No phase change during heating
  • c approximately constant in temp range

Stefan-Boltzmann radiation law

Radiation power from a body. Black body epsilon=1; net to surroundings P = sigma*epsilon*A*(T^4 - T_s^4).

SymbolQuantitySI Unit
sigmaStefan-Boltzmann = 5.67e-8W/m^2/K^4
epsilonemissivity (0-1)-
Asurface aream^2
Tabsolute tempK

Valid when

  • Body in radiative equilibrium
  • T in kelvins

Stokes' law (viscous drag on sphere)

Drag force on a sphere of radius r moving with velocity v through viscous fluid (low Reynolds number).

SymbolQuantitySI Unit
Fdrag forceN
etaviscosityPa*s
rsphere radiusm
vvelocitym/s

Valid when

  • Smooth, slow flow (low Reynolds number)
  • Spherical body
  • Newtonian fluid

Excess pressure inside drop/bubble

Excess internal pressure due to surface tension. Bubble has 2 surfaces, hence factor 4.

SymbolQuantitySI Unit
Delta_Pexcess pressurePa
Tsurface tensionN/m
rradiusm

Valid when

  • Spherical drop or bubble
  • Constant T (one fluid pair)

Terminal velocity of sphere in viscous fluid

Constant velocity reached when net force is zero (gravity balanced by buoyancy + viscous drag).

SymbolQuantitySI Unit
v_tterminal velocitym/s
rsphere radiusm
rho_ssphere densitykg/m^3
rho_ffluid densitykg/m^3
etaviscosityPa*s

Valid when

  • Steady state (net force zero)
  • Stokes regime applicable

Thermal expansion (linear/area/volume)

Fractional change in length, area, volume per degree temperature change.

SymbolQuantitySI Unit
alphalinear coefficient1/K
betavolume coefficient1/K
Delta_Ttemperature changeK

Valid when

  • Isotropic material
  • Modest temperature range (alpha ~ constant)

Young's modulus

Ratio of longitudinal stress to longitudinal strain in a stretched wire/rod within elastic limit.

SymbolQuantitySI Unit
YYoung's modulusPa
Fapplied forceN
Across-section aream^2
Loriginal lengthm
Delta_Lextensionm

Valid when

  • Within elastic limit (Hooke's law region)
  • Uniform cross-section
  • Force along length

Exam Traps & Common Mistakes

These are the exact patterns that cause wrong answers in NEET. Each trap includes when it triggers and how to avoid it.

5 items — click to collapse

Category: Similar Terms

Student uses 2T/r for soap bubble (drop formula). Bubble has 2 surfaces → 4T/r.

When it triggers

Question mentions soap bubble OR liquid drop OR air bubble in liquid.

How to avoid

Drop in air: 1 surface → 2T/r. Soap bubble in air: 2 surfaces → 4T/r. Air bubble in liquid: 1 surface → 2T/r.

Category: Similar Terms

Student uses Y formula when problem is about volumetric compression (use K) or vice versa.

When it triggers

Problem describes longitudinal stretching (use Y), volumetric pressure (use K), or shear (use G).

How to avoid

Y: longitudinal stress/strain. K: volumetric. G: shear. Match modulus to deformation type.

Past Year Questions

15 questions from NEET 2020, 2021, 2022, 2023, 2024, 2025. Answers verified against NTA official keys. — click to collapse
NEET 2025

A balloon is made of a material of surface tension S and its inflation outlet (from where gas is filled in it) has small area A. It is filled with a gas of density ρ and takes a spherical shape of radius R. When the gas is allowed to flow freely out of it, its radius r changes from R to 0 (zero) in time T. If the speed v(r) of gas coming out of the balloon depends on r as ra and T ∝ Sα Aβ ργ Rδ then 1 1 1 1 7 1 1 3

1a= ,α= ,β=− ,γ= ,δ=
2a= ,α= ,β=−1,γ=+1,δ= 2 2 2 2 2 2 2 2 1 1 1 5 1 1 1 7
3a=− ,α=– ,β=−1,γ=− ,δ=
4a=− ,α=− ,β=−1,γ= ,δ= 2 2 2 2 2 2 2 2
NTA Answer: Option 4(final)
NEET 2025

Consider a water tank shown in the figure. It has one wall at x = L and can be taken to be very wide in the z direction. When filled with a liquid of surface tension S and density ρ, the liquid surface makes angle θ 0 (θ 0 << 1) with the x-axis at x = L. If y(x) is the height of the surface then the equation for y(x) is: dy (takeθ(x)=sinθ(x)=tanθ(x)= ,g is the acceleration due to gravity) dx dy ρg d2y ρg

1= x
2= x dx S dx2 S d2y ρg d2y ρg
3= y
4= dx2 S dx2 S
NTA Answer: Option 3(final)
NEET 2023

The venturi-meter works on

1Bernoulli’s principle
2The principle of parallel axes
3The principle of perpendicular axes
4Huygen’s principle
NTA Answer: Option 1(final)
NEET 2022

Given below are two statements : One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The stretching of a spring is determined by the shear modulus of the material of the spring. Reason (R): A coil spring of copper has more tensile strength than a steel spring of same dimensions. In the light of the above statements, choose the most appropriate answer from the options given below

1(A) is false but (R) is true
2Both (A) and (R) are true and (R) is the correct explanation of (A)
3Both (A) and (R) are true and (R) is not the correct explanation of (A)
4(A) is true but (R) is false
NTA Answer: Option 4(final)

How NEET usually asks this

5 recurring patterns from past papers — click to collapse

Sources

NCERT refs: Class 11 Physics Chapter 11, p.3 | Class 11 Physics Chapter 11, p.2

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